在 Python 中的搜索中跳过目录

Question

我正在运行以下代码，并且我想跳过 3 个具有各自名称的文件夹： 文件夹 1、文件夹 2、.repository。

但是，如果某些文件夹不存在，我会收到错误：

indentationerror: unindent 不匹配任何外部缩进级别

如何跳过该文件夹进行搜索，即使它们不存在也不会出现任何错误？这是我的代码：

import re
import os
from os.path import join
comment=re.compile(r"<!--\s+\| Start of user code \(user defined modules\)\s+\|-->\s+<!--\s+\| End of user code\s+\|-->", re.MULTILINE)
tag="<module>"

for root, dirs, files in os.walk("."):
    dirs.remove("folder1")
    dirs.remove("folder2")
    dirs.remove(".repo")
    if "pom.xml" in files:
        p=join(root, "pom.xml") 
        print("Checking",p)
        with open(p) as f:
            s=f.read()
        if tag in s and comment.search(s):
            print("The following file has been modified",p)

--------更新：

import re
import os
from os.path import join
comment=re.compile(r"<!--\s+\| Start of user code \(user defined modules\)\s+\|-->\s+<!--\s+\| End of user code\s+\|-->", re.MULTILINE)
tag="<module>"

for root, dirs, files in os.walk("/home/temp/"):
 dirs.remove("/home/temp/test1")
 dirs.remove("/home/temp/test2")
 dirs.remove("/home/temp/test3")

       if "pom.xml" in files:
        p=join(root, "pom.xml") 
        print("Checking",p)
        with open(p) as f:
            s=f.read()
        if tag in s and comment.search(s):
            print("The following file contains user code modules:-------------> ",p)

这里是输出：

python /home/temp/test_folder/python_script_4.py
  File "/home/temp/test_folder/python_script_4.py", line 12
    if "pom.xml" in files:
    ^
IndentationError: unexpected indent

最后更新 --------->

import re
import os
from os.path import join
comment=re.compile(r"<!--\s+\| Start of user code \(user defined modules\)\s+\|-->\s+<!--\s+\| End of user code\s+\|-->", re.MULTILINE)
tag="<module>"

for root, dirs, files in os.walk("/home/dlopez/temp/test_folder/"):
 dirs.remove("/home/temp/test_folder/test1")
 dirs.remove("/home/temp/test_folder/test2")
 dirs.remove("/home/temp/test_folder/test3")

 if "pom.xml" in files:
    p=join(root, "pom.xml") 
    print("Checking",p)
    with open(p) as f:
       s=f.read()
       if tag in s and comment.search(s):
          print("The following file contains user code modules:-------------> ",p)

我的输出：

    python /home/temp/test_folder/python_script_5.py
Traceback (most recent call last):
  File "/home/dlopez/temp/test_folder/python_script_5.py", line 8, in <module>
    dirs.remove("/home/temp/test_folder/test1")
ValueError: list.remove(x): x not in list

请帮忙，谢谢！ :)

Answer 1

if 的缩进与当前的缩进不匹配

import re
import os
from os.path import join
comment=re.compile(r"<!--\s+\| Start of user code \(user defined modules\)\s+\|-->\s+<!--\s+\| End of user code\s+\|-->", re.MULTILINE)
tag="<module>"

for root, dirs, files in os.walk("/home/dlopez/temp/"):
 dirs.remove("/home/dlopez/temp/test1")
 dirs.remove("/home/dlopez/temp/test2")
 dirs.remove("/home/dlopez/temp/test3")

       if "pom.xml" in files:  # The if statement is not aligned to anything
        p=join(root, "pom.xml") 
        print("Checking",p)
        with open(p) as f:
            s=f.read()
        if tag in s and comment.search(s):
            print("The following file contains user code modules:-------------> ",p)

改成：

import re
import os
from os.path import join
comment=re.compile(r"<!--\s+\| Start of user code \(user defined modules\)\s+\|-->\s+<!--\s+\| End of user code\s+\|-->", re.MULTILINE)
tag="<module>"

for root, dirs, files in os.walk("/home/dlopez/temp/"):
    # Skip the dirs you want looping a list
    for skipped in ("/home/dlopez/temp/test1", "/home/dlopez/temp/test1", "/home/dlopez/temp/test3"):
        if skipped in dirs: dirs.remove(skipped)

    if "pom.xml" in files:
        p=join(root, "pom.xml") 
        print("Checking",p)
        with open(p) as f:
           s=f.read()
           if tag in s and comment.search(s):
              print("The following file contains user code modules:-------------> ",p)