【发布时间】:2018-05-05 14:40:19
【问题描述】:
我有两个如下所述的 yaml 文件
test1.yaml
resources:
server_group_1:
type: OS::Nova::ServerGroup
properties:
name: { get_param: [server_groups, 5] }
policies: [ { get_param: [server_group_types, 5] } ]
server_group_2:
type: OS::Nova::ServerGroup
properties:
name: { get_param: [server_groups, 8] }
policies: [ { get_param: [server_group_types, 8] } ]
output:
check_1:
description: Name of the instance
value: { get_attr: [check_1, vname] }
test2.yaml
resources:
server_group_4:
type: OS::Nova::ServerGroup
properties:
name: { get_param: [server_groups, 4] }
policies: [ { get_param: [server_group_types, 4] } ]
server_group_9:
type: OS::Nova::ServerGroup
properties:
name: { get_param: [server_groups, 7] }
policies: [ { get_param: [server_group_types, 7] } ]
output:
check_6:
description: Name of the instance
value: { get_attr: [check_6, vname] }
我想合并这两个文件并创建一个新的输出文件,所以我使用 pyyaml 更改顺序在此 link 中发布相同
有人可以在不更改顺序的情况下帮助合并这些文件吗? 最终的yaml应该是这样的
final.yaml
resources:
server_group_1:
type: OS::Nova::ServerGroup
properties:
name: { get_param: [server_groups, 5] }
policies: [ { get_param: [server_group_types, 5] } ]
server_group_2:
type: OS::Nova::ServerGroup
properties:
name: { get_param: [server_groups, 8] }
policies: [ { get_param: [server_group_types, 8] } ]
server_group_4:
type: OS::Nova::ServerGroup
properties:
name: { get_param: [server_groups, 4] }
policies: [ { get_param: [server_group_types, 4] } ]
server_group_9:
type: OS::Nova::ServerGroup
properties:
name: { get_param: [server_groups, 7] }
policies: [ { get_param: [server_group_types, 7] } ]
output:
check_1:
description: Name of the instance
value: { get_attr: [check_1, vname] }
check_6:
description: Name of the instance
value: { get_attr: [check_6, vname] }
更新
我可以使用 ruamel.yaml 合并文件...这里是更新资源的示例代码
代码:
import ruamel.yaml
yaml = ruamel.yaml.YAML()
#Load the yaml files
with open('/test1.yaml') as fp:
data = yaml.load(fp)
with open('/test2.yaml') as fp:
data1 = yaml.load(fp)
#Add the resources from test2.yaml to test1.yaml resources
for i in data1['resources']:
print i,data1['resources'][i]
data['resources'].update({i:data1['resources'][i]})
#create a new file with merged yaml
yaml.dump(data,file('/tmp/lal.yaml', 'w'))
【问题讨论】:
-
尝试后我来到这里......我尝试使用 pyyaml 但由于嵌套它没有给出正确的输出并且顺序也在改变
-
@anthon 建议使用 ruamel.yaml 将尝试使用它
-
@mkrieger1 与 ruamel.yaml 合作......我的要求不要急于通过说不尝试来否决......
标签: python pyyaml ruamel.yaml