【发布时间】:2020-12-03 09:48:24
【问题描述】:
使用 Rails API 构建。提交 API 请求登录时收到错误 SystemStackError (stack level too deep)。
错误在于在这一行上渲染 JSON render json: {user: @user, token: token}.as_json, serializer: nil, :status => :ok
尝试过的解决方案:
SystemStackError (stack level too deep)
Ruby 2.4 and Rails 4 stack level too deep (SystemStackError)
https://github.com/rmosolgo/graphql-ruby/issues/2214
用户控制器:
class UsersController < ApplicationController
#auth_login only action to be authorized before an action
before_action :authenticate_request, only: [:auto_login, :edit]
def login
@user = User.find_by(email: params[:email])
if @user && @user.authenticate(params[:password])
token = encode_token({email: @user.email})
render json: {user: @user, token: token}.as_json, serializer: nil, :status => :ok
else
render json: {error: "Invalid email or password"}, :status => :unauthorized
end
end
private
def default_serializer_options
{
serializer: nil
}
end
end
这个错误很烦人,因为它不一致!有时它可以毫无问题地构建,有时则不会。不知道该去哪里,因为我看不到代码递归的任何地方。
更新:应用程序控制器encode_token
class ApplicationController < ActionController::API
before_action :authenticate_request
def encode_token(payload)
JWT.encode(payload, 's3cr3t')
end
def auth_header
#requesting the header type of authorization (with token) that we will declare through our api requests
# { Authorization: 'Bearer <token>' }
request.headers['Authorization']
end
def decoded_token
if auth_header
#going to take the token and decode it
token = auth_header.split(' ')[1]
# header: { 'Authorization': 'Bearer <token>' }
begin
puts token
JWT.decode(token, 's3cr3t') #The header is sending the correct token but returning a fail.
rescue JWT::DecodeError
# puts "fail"
nil
end
end
end
def logged_in_user
#consults decode_token to check the header for valid information
if decoded_token
puts "Do"
email = decoded_token[0]['email']
@user = User.find_by(email: email)
end
end
def logged_in?
#returns true or false
!!logged_in_user
end
def authenticate_request
#consults logged_in? see see if user is authorized
render json: { message: 'Please log in' }, status: :unauthorized unless logged_in?
end
end
【问题讨论】:
-
能否在此处添加 encode_token 的代码?
-
@RishiPithadiya 是的,添加了!