【发布时间】:2014-03-13 05:12:37
【问题描述】:
在我的 main 函数中,我使用 new 创建了三个对象。然后我删除它们。运行 Valgrind 显示 8 字节的仍然可访问的内存。我尝试将整个 main 函数粘贴在一个循环中,以便它运行多次。它仍然只有 8 个字节。
我的主要 -
int main()
{
settings *st = new settings();
thread_data *td = new thread_data(st);
client_handler *cl = new client_handler(td);
delete cl;
delete td;
delete st;
}
相关的 valgrind 输出 -
==24985== 8 bytes in 1 blocks are still reachable in loss record 1 of 1
==24985== at 0x4C2CD7B: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==24985== by 0x4E494F9: boost::detail::get_once_per_thread_epoch() (in /usr/lib/libboost_thread.so.1.49.0)
==24985== by 0x4E4182F: ??? (in /usr/lib/libboost_thread.so.1.49.0)
==24985== by 0x4E41B08: boost::detail::get_current_thread_data() (in /usr/lib/libboost_thread.so.1.49.0)
==24985== by 0x4E41D58: boost::this_thread::interruption_enabled() (in /usr/lib/libboost_thread.so.1.49.0)
==24985== by 0x4E41D88: boost::this_thread::disable_interruption::disable_interruption() (in /usr/lib/libboost_thread.so.1.49.0)
==24985== by 0x421854: boost::shared_mutex::lock_upgrade() (shared_mutex.hpp:195)
==24985== by 0x423A3B: boost::upgrade_lock<boost::shared_mutex>::lock() (locks.hpp:875)
==24985== by 0x422FA6: boost::upgrade_lock<boost::shared_mutex>::upgrade_lock(boost::shared_mutex&) (locks.hpp:766)
==24985== by 0x41E15C: settings::load() (settings.cpp:91)
==24985== by 0x41D796: settings::settings() (settings.cpp:34)
==24985== by 0x40A3BB: main (main.cpp:26)
settings::load() 仅从构造函数调用一次。第 91 行是第一行 -
bool settings::load()
{
boost::upgrade_lock<boost::shared_mutex> lock(_access);
boost::upgrade_to_unique_lock<boost::shared_mutex> uniqueLock(lock);
我不明白内存是如何仍然可以访问的。设置对象被删除。 _access 应该在调用设置构造函数时被删除(它是设置的成员)。我尝试将 _access 更改为指针并在构造函数/析构函数中分配/删除无济于事。 升级锁在超出范围时应该被解构。
即使存在内存泄漏(据我所知,在 boost::thread(1.49 版)中没有已知错误),内存肯定会丢失吗?
我意识到这不是一个大问题,但它令人恼火(同行不会让我忘记它)
有什么想法吗?
【问题讨论】:
-
这篇文章link 似乎相关,但我在返回之前加入了我所有的线程,所以假设他们应该在 valgrind 之前退出?特别是因为这个调用来自 main.
标签: c++ memory-leaks valgrind boost-thread