运算符的 SQL 2003 到 2014 转换 *=答案

【问题标题】：SQL 2003 to 2014 conversion for the operator *=运算符的 SQL 2003 到 2014 转换 *=
【发布时间】：2019-03-19 10:44:36
【问题描述】：

请帮助将下面的查询从 Sql2003 转换为 2014，运算符 *= 不起作用，当替换遗漏加入时它会忽略空行。

SELECT REJECT_CODE,IsNull(SUM(REJ_M2),0.00) as Rejection 
FROM   dbo.Reject_Code a, dbo.QA_Rej_Det1 b 
WHERE  a.REJ_RKEY *= b.REJ_CODE and b.CUSTOMER_PART_DESC = 'XXXXX'  
GROUP BY REJECT_CODE order by REJECT_CODE

【问题讨论】：

"隐式连接语法自 1992 年以来已过时" - stackoverflow.com/questions/983862/sql-server-operator
没有 2003 年的产品。

标签： sql sql-server sql-server-2008 sql-server-2012

【解决方案1】：

*= 运算符已弃用。您应该开始使用 ANSI 语法，例如：

SELECT REJECT_CODE,IsNull(SUM(REJ_M2),0.00) as Rejection 
FROM   dbo.Reject_Code a 
LEFT OUTER JOIN dbo.QA_Rej_Det1 b 
ON a.REJ_RKEY = b.REJ_CODE AND b.CUSTOMER_PART_DESC = 'XXXXX'  
GROUP BY REJECT_CODE order by REJECT_CODE

【讨论】：