AS2 从数组中提取前 5 个

Question

大家晚上好！ 任何人都知道如何从数组中提取前 5 个数字（最高）？ 我有一个包含姓名、姓氏和分数的 XML，并且想要提取前 5 个来创建图表。 至于现在，我是通过这种方式获取所有信息的：

num = xmlData.childNodes.length;
    for (var i = 0; i <= num - 1; i++)
    {
        names[i] = this.childNodes[i].childNodes[6].firstChild.nodeValue;
        surnames[i] = this.childNodes[i].childNodes[5].firstChild.nodeValue;
        points[i] = this.childNodes[i].childNodes[0].firstChild.nodeValue;
        pointsint[i] = parseInt(speeds[i]);
        trace(i + "." + pointsint[i] + " (" + names[i] + " " + surnames[i] + ")");
    }

感谢您的帮助！

Answer 1

将数据组织为通用对象条目和 Array.sortOn(...) (http://help.adobe.com/en_US/as2/reference/flashlite/WS5b3ccc516d4fbf351e63e3d118ccf9c47f-7ea5.html)。我没有测试它，但我认为这个想法很清楚：

var num = xmlData.childNodes.length;
var entries = [];

for (var i = 0; i <= num - 1; i++)
{
    var anEntry = {};
    var aNode = xmlData.childNodes[i];

    anEntry['name'] = aNode.childNodes[6].firstChild.nodeValue;
    anEntry['surname'] = aNode.childNodes[5].firstChild.nodeValue;

    var aSpeed = aNode.childNodes[0].firstChild.nodeValue;
    anEntry['speed'] = parseInt(aSpeed);

    entries.push(anEntry);

    trace(i + "." + anEntry['speed'] + " (" + anEntry['name'] + " " + anEntry['surname'] + ")");
}

entries.sortOn("speed", Array.DESCENDING | Array.NUMERIC);
// Now first five elements of entries Array is what you want.