来自 Array[object..] 的逻辑运算符

Question

我目前正在使用类似此代码的布尔和逻辑运算符

仅供参考，我想将数组中的 object.Value 、 object.Logic 转换为逻辑运算符。示例：object1.logic object.operators object2.logic 为真或假

const input: Array<any> = [
    {
        type: "basic",
        value: true,
        logic: "or"
    },
    {
        type: "basic",
        value: false,
        logic: "and"
    },
    {
        type: "basic",
        value: true,
        logic: "and"
    },

我希望结果与

 true || false && true

有人对这个问题有想法吗？

Answer 1

您只需要运行reduce 运算符并返回一个新的运算符对象，该对象将具有先前运算符和值或当前计算的逻辑。

let input = [{
    type: "basic",
    value: true,
    logic: "or"
  },
  {
    type: "basic",
    value: false,
    logic: "and"
  },
  {
    type: "basic",
    value: true,
    logic: "and"
  }
]

// if type does not matter 

let result = input.reduce((op1, op2) => ({
  logic: op2.logic,
  value: op1.logic === 'or' ? op1.value || op2.value : op1.value && op2.value
}));
// if you have more than ||- && operations you can create function with switch case and call it here.

console.log(result);

如果您想控制操作顺序：

let input = [{
    type: "basic",
    value: true,
    logic: "or"
  },
  {
    type: "basic",
    value: false,
    logic: "and"
  },
  {
    type: "basic",
    value: true,
    logic: "and"
  }
]

// logic: and - or
// operation: (boolean, boolean) =>  boolean; 
let processOperation = (logic, operation, arr, op) => {
  // if emplty return first
  if (!arr.length) return [op];

  let prevOp = arr[arr.length - 1];

  if (prevOp.logic === logic) {
    // remove prevous and replace with operation result
    arr.pop()
    arr.push({
      logic: op.logic,
      value: operation(prevOp.value, op.value)
    });
  } else {
    arr.push(op); // if operation logic not matched push it in for future processing
  }
  return arr;
}



let result = input
  .reduce(processOperation.bind(this, 'and', (a, b) => a && b), [])
  .reduce(processOperation.bind(this, 'or', (a, b) => a || b), []);
// here you are deciding the order by the squence in the chiain

// result[0].value will be the solution
console.log('answer', result);