我打算编写一个测验程序，当答案正确时加分，在python中给出错误答案时减分[重复]

Question

这是我想出的，我不明白为什么会这样，因为我的期望是每个正确答案都会增加分数，任何错误答案都会扣分。

name = str(input("What is your name?: "))
score = 0

answer1 = str(input("(1) What is the name of the first president of Nigeria? \n(a) Amadu Bello \n(b) Shehu Shagari \n(c) Olusegun Obasanjo \n(d) Nnamdi Azikwe\n:Your answer: "))

if answer1 == "d" or "D" or "Nnamdi" or "Nnamdi Azikwe" and "Azikwe":
    score = score+5
    print ( "Weldone", name, "you've scored", score, "points")
else:
    score = score - 5
    print( "ouch!!!", name, "you missed that, you've scored, ", score, "points")


answer2 = str(input("(2) What is the name of the capital of Lagos state? \n(a) Ikorodu\n(b) Ikeja\n(c) Surulere\n(d) Victoria Island\nYour answer: "))

if answer2 == "a" or "A" or "Ikeja":
    score = score+5
    print ( "Weldone", name, "you've scored", score, "points")
else:
    score = score - 5
    print( "ouch!!!", name, "you missed that, you've scored, ", score, "points")


answer3 = str(input("(3) What is the name of the first capital of Nigeria?\n(a) Kano \n(b) Abuja\n(c) Lagos\n(d) Calabar\nYour Answer: "))

if answer3 == "c" or "C" or "lagos" and "Lagos":
    score = score+5
    print ( "Weldone", name, "you've scored", score, "points")
else:
    score = score - 5
    print( "ouch!!!", name, "you missed that, you've scored, ", score, "points")


answer4 = str(input("(4) What is the name of the governor of Lagos when Code-Lagos was first implemented? \n(a)Raji Fashola\n(b)Akinwunmi Ambode\n(c) Ahmed Tinubu\n (d) Lateef Jakande\nYour answer: "))

if answer4 == "b" or "B" or "Ambode" or "Akinwunmi Ambode" or "akinwunmi ambode":
    score = score+5
    print ( "Weldone", name, "you've scored", score, "points")
else:
    score = score - 5
    print( "ouch!!!", name, "you missed that, you've scored, ", score, "points")


answer5 = str(input("(5) Which of the following is indigenous Nigerian content? \n(a) Etisalat\n(b) Airtel\n(c) MTN\n(d) Globacoms\n Your Answer: "))

if answer5 == "d" or "D" or "glo" or "Glo" or "GLO":
    score = score+5
    print ( "Weldone", name, "you've scored", score, "points")
else:
    score = score - 5
    print( "ouch!!!", name, "you missed that, you've scored, ", score, "points")

输出，只接受任何正确答案并加分。

Answer 1

您的代码中的问题是您在if 条件中错误地使用了or 运算符。

一般来说，如果您想检查变量 a 与值 B 和 C，您需要这样做：

if a == B or a == C:

而不是简单地

if a == B or C

请注意，在第二种情况下，它采用布尔值 B or C 的值并将其与 a 进行比较，这显然不是您想要的。

如果您想将 a 与整个变量列表进行比较，您可以这样做：

if a in [B, C, D, ...]:

所以，在你的代码中，尝试替换这个：

if answer1 == "d" or "D" or "Nnamdi" or "Nnamdi Azikwe" and "Azikwe":

用这个：

if answer1 in ["d", "D", "Nnamdi", "Nnamdi Azikwe", "Azikwe"]:

...等等

您可以使用字典来存储您的问题、选项和答案，从而大大消除代码中的冗余，如下所示：

questions = [
    {
        "question": "What is the name of the first president of Nigeria?",
        "options": ["Amadu Bello", "Shehu Shagari", "Olusegun Obasanjo", "Nnamdi Azikwe"],
        "answers": ["d", "nnamdi", "nnamdi azikwe", "azikwe"]
    },
# add more questions here in the same format as above
]

name = str(input("What is your name?: "))
score = 0

for q_number, q in enumerate(questions):
    question_text = '({}) {}\n'.format(q_number + 1, q["question"])
    options_text = '\n'.join("({}) {}".format(chr(i + 65), qsn) for i, qsn in enumerate(q["options"])) + "\n"
    display_text = question_text + options_text

    # answer is converted to lower case to make comparison with options easier
    answer = str(input(display_text)).lower()

    if answer in q["answers"]:
        score += 5
        print ("Well done", name, "you've scored", score, "points")
    else:
        score -= 5
        print("ouch!!!", name, "you missed that, you've scored, ", score, "points")