使用 php cURL 从文件头获取文件名

Question

我有这个 php cURL 函数：

function curl_login($url,$data,$proxy,$proxystatus){
$fp = fopen("cookietlt.txt", "w");
fclose($fp);
$login = curl_init();
curl_setopt($login, CURLOPT_COOKIEJAR, "cookie.txt");
curl_setopt($login, CURLOPT_COOKIEFILE, "cookie.txt");
curl_setopt($login, CURLOPT_USERAGENT, "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)");
curl_setopt($login, CURLOPT_TIMEOUT, 40);
curl_setopt($login, CURLOPT_RETURNTRANSFER, TRUE);
if ($proxystatus == 'on') {
    curl_setopt($login, CURLOPT_SSL_VERIFYHOST, FALSE);
    curl_setopt($login, CURLOPT_HTTPPROXYTUNNEL, TRUE);
    curl_setopt($login, CURLOPT_PROXY, $proxy);
}
curl_setopt($login, CURLOPT_URL, $url);
curl_setopt($login, CURLOPT_HEADER, TRUE);
curl_setopt($login, CURLOPT_USERAGENT, $_SERVER['HTTP_USER_AGENT']);
curl_setopt($login, CURLOPT_FOLLOWLOCATION, TRUE);
curl_setopt($login, CURLOPT_POST, TRUE);
curl_setopt($login, CURLOPT_POSTFIELDS, $data);
ob_start();      // prevent any output
return curl_exec ($login); // execute the curl command
ob_end_clean();  // stop preventing output

curl_close ($login);

unset($login);    
}                  
function curl_grab_page($site,$proxy,$proxystatus){
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
if ($proxystatus == 'on') {
    curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE);
    curl_setopt($ch, CURLOPT_HTTPPROXYTUNNEL, TRUE);
    curl_setopt($ch, CURLOPT_PROXY, $proxy);
}
curl_setopt($ch, CURLOPT_COOKIEFILE, "cookie.txt");
curl_setopt($ch, CURLOPT_URL, $site);
ob_start();      // prevent any output
return curl_exec ($ch); // execute the curl command
ob_end_clean();  // stop preventing output
curl_close ($ch);
}


curl_login('http://www.site.tdl/login.php','username=test&password=demo','','off');
curl_grab_page('http://www.site.tdl/1965.torrent','','off');

我需要从文件(http://www.site.tdl/1965.torrent) 标头中获取文件名到变量中。

http://www.site.tdl/1965.torrent 标题：

Content-Disposition: attachment; filename="Linux.Mint.torrent"
Content-Type: application/x-bittorrent
Content-Length: 4525

所以输出将是 Linux.Mint。我怎样才能做到这一点？

谢谢！

Answer 1

您需要分配一个回调来读取标题。

curl_setopt($ch, CURLOPT_HEADERFUNCTION, readHeader);

function readHeader($ch, $header)
{
     // read headers
}

Answer 2

我知道这个问题有点老了，但我想澄清一下CURLOPT_HEADERFUNCTION，我发现 php.net 上的文档令人困惑。

curl 将一次向标头回调函数发送一个标头。回调函数必须返回读取的字节数，否则 curl 将失败（并且请求将结束）

curl_setopt($ch, CURLOPT_HEADERFUNCTION, "readHeader");

function readHeader($ch, $header)
{
     // read headers
    echo "Read header: ", $header;
    return strlen($header);
}

示例输出：

 Read header: HTTP/1.1 200 OK
    Read header: Server: nginx/0.8.32
    Read header: Date: Wed, 31 Mar 2010 14:23:18 GMT
    Read header: Content-Type: image/jpeg
    Read header: Content-Length: 886308
    Read header: Connection: close
    Read header: Accept-Ranges: bytes
    Read header: 

如果没有readHeader的返回，curl会在第一个header发送后结束。