使用 volley 在 url 请求中传递 Long 参数的方法

Question

服务器不在发出 json 对象请求（通过 post 方法）使用 volley 时接受 String 参数，在自定义 volley 请求中也是如此需要在 getParams() 方法中传递字符串哈希映射我有字符串以及要传递的长值，也由 Uri 类尝试，但也有appendQueryParameter() 中需要 sting。我使用了以下链接Link 1 Link 2Link 3

Volley class

公共类 CustomRequest 扩展请求 {

private Listener<JSONObject> listener;
private Map<String, String> params;

public CustomRequest(String url, Map<String, String> params,
                     Listener<JSONObject> reponseListener, ErrorListener errorListener) {
    super(Method.GET, url, errorListener);
    this.listener = reponseListener;
    this.params = params;
}

public CustomRequest(int method, String url, Map<String, String> params,
                     Listener<JSONObject> reponseListener, ErrorListener errorListener) {
    super(method, url, errorListener);
    this.listener = reponseListener;
    this.params = params;
}

protected Map<String, String> getParams()
        throws com.android.volley.AuthFailureError {
    return params;
}


@Override
protected Response<JSONObject> parseNetworkResponse(NetworkResponse response) {
    try {
        String jsonString = new String(response.data,
                HttpHeaderParser.parseCharset(response.headers));
        return Response.success(new JSONObject(jsonString),
                HttpHeaderParser.parseCacheHeaders(response));
       /* return Response.success(
                gson.fromJson(json, clazz), HttpHeaderParser.parseCacheHeaders(response));*/
    } catch (UnsupportedEncodingException e) {
        return Response.error(new ParseError(e));
    } catch (JSONException je) {
        return Response.error(new ParseError(je));
    }
}

@Override
public Map<String, String> getHeaders() throws AuthFailureError {
    Map<String, String> headers = new HashMap<>();
    String loginEncoded = new String(Base64.encode(("uictester:?f!T!ziX}.,(").getBytes(), Base64.DEFAULT));
    headers.put("Authorization", "Basic " + loginEncoded);
    return headers;
}

@Override
protected void deliverResponse(JSONObject response) {
    // TODO Auto-generated method stub
    listener.onResponse(response);
}

}

Answer 1

您首先需要使用 String.valueOf(long value) 方法将 long 参数转换为 String，然后将此参数及其键放入 hashmap。如：

params.put("key", String.valueOf(long value));