通过同一窗口中的 tkinter 按钮启动/暂停 pygame

Question

为了一个学校项目，我和一个朋友在 pygame 中做一个游戏。 pygame 窗口嵌入在 tkinter 框架中。只要您打开应用程序，游戏就会立即开始。现在我们想用 tkinter 的按钮开始和暂停游戏。很高兴得到任何帮助，谢谢。

import pygame, random, sys
from pygame.locals import *
from pygame.key import *
import tkinter as tk
from tkinter import *
import os

创建一个 tkinter 框架

root = tk.Tk()
root.title("Borderflip")
embed = tk.Frame(root, width = 500, height = 500) #Erzeugt einen 
eingebetteten Rahmen für das Pygame-Fenster
embed.grid(columnspan = (600), rowspan = 500) 
embed.pack(side = LEFT) #Fenster nach rechts
buttonwin = tk.Frame(root, width = 75, height = 500)
buttonwin.pack(side = LEFT)

这里是按钮 播放和暂停按钮没有功能

def play_button():

play_button = Button(root,  padx=8, width=18, pady=8, bd=8, font=("Arial", 
26), text="Play", command=play_button)
play_button.pack()

pause_button = Button(root,  padx=8, width=18, pady=8, bd=8, font=("Arial", 
26), text="Pause", command=root.quit)
pause_button.pack()

quit_button = Button(root, padx=8, width=18, pady=8, bd=8, font=("Arial", 
26), text="Quit", command=root.destroy)
quit_button.pack()

在 tkinter 中集成 pygame 的代码

os.environ['SDL_WINDOWID'] = str(embed.winfo_id())
os.environ['SDL_VIDEODRIVER'] = 'windib'
screen = pygame.display.set_mode((500,500))
screen.fill(pygame.Color(255,255,255))
pygame.display.init()
pygame.display.update()
frame = Frame(root)
frame.pack()

pygame 的代码

x = 500 # Breite und Höhe Fenster in Pixel
y = 500

sbreite = 100 # Breite und Höhe Schläger
shöhe = 15

sx = 200 # Definition 
sy = 450

bx = int(x/2)
by = int(y/2)

brad = 15

speed = 0

bxspeed = 1
byspeed = -2

leben = 10

def sblock():
    global speed
    if sx <= 0 or sx >= x-sbreite:
        speed = 0

def ballbewegung():
    global bx,by
    bx += bxspeed
    by += byspeed


def reset():
    global byspeed,bxspeed,leben,bx,by,sx,sy,speed
    sx = 200
    sy = 450

    bx = int(x/2)
    by = int(y/2)

speed = 0

bxspeed = random.randint(-2,2)
if bxspeed == 0:
    bxspeed = 1
byspeed = random.randint(-2,2)
if byspeed == 0:
    byspeed = 2
screen.fill((0,0,0))
pygame.draw.circle(screen, (255,255,0), (bx,by), brad, 0)
pygame.draw.rect(screen, (255,40,0), (sx,sy,sbreite,shöhe), 0)
pygame.display.flip()
pygame.time.wait(1000)
root.update()

def ballblock():
    global byspeed, bxspeed, leben
    if by-brad <= 0:
        byspeed *= -1
    if bx-brad <= 0:
        bxspeed *= -1
    if bx+brad >= x:
        bxspeed *= -1
    if by >= 435 and by <= 440:
        if bx >= sx-15 and bx <= sx + sbreite + 15:
            byspeed *= -1
        else:
            leben -= 1
            reset()
    root.update()

def sbewegung():
    global sx
    sx += speed

while leben > 0:
    for event in pygame.event.get():
        if event.type == pygame.QUIT: sys.exit()
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                speed = -2
            if event.key == pygame.K_RIGHT:
                speed = 2
screen.fill((0,0,0))
sbewegung()
sblock()
pygame.draw.rect(screen, (255,40,0), (sx,sy,sbreite,shöhe), 0)

ballbewegung()
ballblock()
pygame.draw.circle(screen, (255,255,0), (bx,by), brad, 0)

pygame.display.flip()
pygame.time.wait(5)

print ("haha verloren")

while True:
    pygame.display.update()
    root.update()

Answer 1

遗憾的是，Tkinter + Pygame 不能很好地协同工作，这通常是由于它们的图形库之间的冲突以及一个程序在另一个程序处于活动状态时如何休眠。

我个人建议从您的项目中删除 tkinter 并通过 pygame.sprite.Sprite() 构建一个 button 类，然后可以以与 tkinter 按钮相同的方式使用它。你可以阅读那个Here.的文档