每次我绕过 while 循环时，如何保持我的值相同？答案

【问题标题】：How do I keep my values the same each time I go around the while loop?每次我绕过 while 循环时，如何保持我的值相同？
【发布时间】：2020-10-19 20:34:39
【问题描述】：

我正在制作一个有五轮的两人骰子游戏，但我想保持前几轮的分数相同，我该怎么做？

游戏规则如下：

• 每位玩家掷骰子的点数会加到他们的分数中。 • 如果总分是偶数，则在他们的分数上增加 10 分。 • 如果总分是奇数，则从他们的分数中减去 5 分。 • 如果他们掷出双倍骰子，他们可以多掷一个骰子，并将掷出的点数加到他们的分数。 • 球员的得分在任何时候都不能低于0。 • 5 轮结束时得分最高的人获胜。 • 如果两个玩家在 5 轮结束时得分相同，则他们每人掷 1 颗骰子，然后得分最高的人获胜（如此重复，直到有人获胜）。

import random
import time


total_player2score = 0
total_player1score = 0
rounds = 0
player_1 = 0
player_2 = 0
while rounds != 5:
    total_player2score = total_player2score + player_2
    total_player1score = total_player1score + player_1
    rounds = rounds + 1
    number = random.randint(1, 6)
    number2 = random.randint(1, 6)
    total_player1score = number + number2
    print("*"*50)
    print("Round {}!".format(rounds))
    print("*"*50)
    print("Player 1's turn. Type 'roll' to roll the dice.")
    player1_input = input(">>> ")
    if player1_input == "roll":
        time.sleep(0.5)
        print("Player 1's first roll is", number)
    print("Player 1's second roll.Type 'roll' to roll the dice")
    player1_input = input(">>> ")
    if player1_input == "roll":
        time.sleep(0.5)
        print("player 1's second roll is", number2)
    if total_player1score % 2 == 0:
        total_player1score = total_player1score + 10
        print("Player 1's total is even so 10 points will be added")
        print("*"*50)
        print("Player 1 has", total_player1score, "points")
    else:
        total_player1score = total_player1score - 5
        total_player1score = max(0, total_player2score)
        print("player 1's total is odd so 5 points will be deducted")
        print("*"*50)
        print("Player 1 has", total_player1score, "points")
    number = random.randint(1, 6)
    number2 = random.randint(1, 6)
    total_player2score = number + number2
    print("*"*50)
    print("Player 2's turn. Type 'roll' to roll the dice")
    player2_input = input(">>> ")
    if player2_input == "roll":
        time.sleep(0.5)
        print("Player 2's first roll is", number)
    print("Player 2's second roll.Type 'roll' to roll the dice")
    player2_input = input(">>> ")
    if player2_input == "roll":
        time.sleep(0.5)
        print("player 2's second roll is", number2)
    if total_player2score % 2 == 0:
        total_player2score = total_player2score + 10
        print("Player 2's total is even so 10 points will be added")
        print("*"*50)
        print("Player 2 has", total_player2score, "points")
    else:
        total_player2score = total_player2score - 5
        total_player2score = max(0, total_player2score)
        print("player 2's total is odd so 5 points will be deducted")
        print("*"*50)
        print("Player 2 has", total_player2score, "points")

【问题讨论】：

欢迎来到 Stack Overflow。如果您将代码减少到minimal reproducible example，您的问题可能会得到改善。目前很难确定您的问题适用于代码中的哪个位置。
我不知道在哪里实际改进我的代码，这样我就可以存储前几轮的值，所以我把所有东西都放进去，这样查看这个问题的人就可以知道我的错误在哪里，也知道重点的程序。
您可以将分数存储在一个 .txt 文件中，如下面的@herbaltea 建议的那样，或者您可以为每个玩家创建一个字典，并将每个键设置为回合，将值设置为分数。

标签： python loops while-loop project

【解决方案1】：

def writeUp(score_1,score_2,nameoffile):
    with open(f"{nameoffile}.txt","a") as logz:
        print(f"score1 {score_1}\nscore2 {score_2}",file=logz)



def readUp(nameoffile):
    with open(f"{nameoffile}.txt","r") as data:
        lines = data.readlines()
        last_2 = lines[:2]
        score_1,score_2 = None,None
        for element in last_2:
            splitt = element.split(' ')
            if element.find('score1') != -1:
                score_1 = int(splitt[1])
            elif element.find('score2') != -1:

                score_2 = int(splitt[1])

    return score_1,score_2



sci1,sci2 = 50,50
writeUp(sci1,sci2,'mysaves')

sc1,sc2 = readUp('mysaves')
print(sc1,sc2)

#这应该会有所帮助，给定的函数会创建一个 txt 文件并将分数存储到其中

【讨论】：