IOS在一年中返回错误的周数[重复]

Question

试图计算一年中的周数，下面是代码，但它返回的周数错误。

NSDateComponents * components = [[NSDateComponents alloc] init];
    components.year = 2015;
    components.weekday=2;
    NSCalendar * calendar = [NSCalendar currentCalendar];
    NSDate * date = [calendar dateFromComponents:components];
    NSInteger length = [calendar rangeOfUnit:NSCalendarUnitWeekOfYear inUnit:NSCalendarUnitYearForWeekOfYear forDate:date].length;
    NSLog(@"%ld",(long)length);

2015 = 53 周，但返回 52 周。

Answer 1

- (NSInteger) getNumberOfWeeks : (NSDate *) fromDate {
       NSCalendar *cal = [NSCalendar currentCalendar];
      NSDateComponents *components = [cal components:NSCalendarUnitWeekOfYear fromDate:fromDate];
     return [components weekOfYear];
  }

或者试试这个

NSDate *date = [NSDate date];//since you are forming date, put it here
NSCalendar *calender = [NSCalendar currentCalendar];
NSRange weekRange = [calender rangeOfUnit:NSWeekCalendarUnit inUnit:NSMonthCalendarUnit forDate:date];
NSInteger weeksCount=weekRange.length;
NSLog(@"%d",weeksCount);

此方法将返回从 12 月 31 日到您在此函数中传递的日期的周数。