.NET 中的 MailTo URI 对象？

Question

给定一个 URI（确认为 Uri.UriSchemeMailto），是否有一个可以强制转换的对象提供 mailto 属性？

就像.TargetURI 是 {mailto:your@email.com?subject=I'm all done&body=Finished&cc=his@email.com&bcc=her@email.com}一个将其作为 URI 并返回 MailTo 属性的对象？喜欢

伪代码

Dim mailDetails as New MailDetailsObject(MyURI.TargetURI)

Console.WriteLine(mailDetails.To)
Console.WriteLine(mailDetails.CC)
Console.WriteLine(mailDetails.BCC)
Console.WriteLine(mailDetails.Subject)
Console.WriteLine(mailDetails.Body)

结果：

your@email.com
他的@email.com
她@email.com
我已经完成了
完成

或者这是人们通常只是手动解析或构造 .TargetURI 下的属性的东西吗？

Answer 1

我不知道有哪个类可以做到这一点，但您可以使用HttpUtility.ParseQueryString() 方法轻松提取它：

var mailto = "mailto:your@email.com?subject=I'm all done&body=Finished&cc=his@email.com&bcc=her@email.com";
var values = HttpUtility.ParseQueryString(mailto.Split('?')[1]);
var subject = values["subject"];
var body = values["body"];
var cc = values["cc"];

Answer 2

我最终为此编写了自己的课程。它并不完整，也没有使用模式的所有可能部分对其进行测试，但对于大多数 mailto 来说，它似乎工作得很好。随意编辑此答案并进行改进。

Class MailToItem
    Public Property [To] As String
    Public Property Cc As String
    Public Property Subject As String
    Public Property Body As String
    Public Property Bcc As String
    Private _mailToParameters As String()
    Sub New(uri As String)
        Dim mailtoString As String() = uri.Split("?")
        Me.To = GetEmailToRecipients(mailtoString(0).Split(":")(1))
        _mailToParameters = mailtoString(1).Split("&")
        SetOtherEmailRecipients()
        SetSubject()
        SetBody()
    End Sub
    Private Sub SetOtherEmailRecipients()
        Me.Cc = GetEmailRecipients("cc")
        Me.Bcc = GetEmailRecipients("bcc")
    End Sub
    Private Function GetEmailRecipients(type As String) As String
        Dim recipients As String = Field(type)
        If recipients IsNot Nothing Then
            Dim recipientsAll() As String
            recipientsAll = recipients.Split("=")(1).Split(",")
            Dim s As New System.Text.StringBuilder
            If recipientsAll.Count > 1 Then
                For r = 0 To recipientsAll.Count - 1
                    If r < recipientsAll.GetUpperBound(0) Then
                        s.Append(recipientsAll(r) + ";")
                    Else
                        s.Append(recipientsAll(r))
                    End If
                Next
            Else
                s.Append(recipientsAll(0))
            End If
            Return s.ToString
        Else
            Return ""
        End If
    End Function
    Private Function Field(type As String) As String
        Return _mailToParameters.Where(Function(f) f.StartsWith(type, StringComparison.InvariantCultureIgnoreCase)).FirstOrDefault
    End Function
    Private Function GetEmailToRecipients(toString As String) As String
        Dim recipientsAll() As String = toString.Split(",")
        Dim s As New System.Text.StringBuilder
            If recipientsAll.Count > 1 Then
                For r = 0 To recipientsAll.Count - 1
                    If r < recipientsAll.GetUpperBound(0) Then
                        s.Append(recipientsAll(r) + ";")
                    Else
                        s.Append(recipientsAll(r))
                    End If
                Next
            Else
                s.Append(recipientsAll(0))
            End If
            Return s.ToString
    End Function
    Private Sub SetSubject()
        Dim subject As String = Field("subject")
        If subject IsNot Nothing Then
            Me.Subject = NormalizeText(subject.Split("=")(1))
        End If
    End Sub
    Private Sub SetBody()
        Dim body As String = Field("body")
        If body IsNot Nothing Then
            Me.Body = NormalizeText(body.Split("=")(1))
        End If
    End Sub
    Private Function NormalizeText(text As String) As String
        text.Replace("%20", " ")
        text.Replace("%0A%0A", Environment.NewLine + Environment.NewLine)
        text.Replace("%0A", Environment.NewLine)
        text.Replace("%0D", Environment.NewLine)
        Return text
    End Function
End Class

请注意，将.TargetURI 传递给构造函数可能会导致失败，因为它似乎没有涵盖完整的架构。例如 mailto:john@jim.com,jim@john.com（两个收件人）将导致 .TargetURI 失败。在这种情况下，您可以改为传入.TargetURI.OriginalString。