仅关闭 ImagePicker 并将图像传递给 ScrollViewController答案

【问题标题】：Closing only the ImagePicker and passing image to ScrollViewController仅关闭 ImagePicker 并将图像传递给 ScrollViewController
【发布时间】：2017-01-03 16:31:45
【问题描述】：

我有一个ImagePicker，在出现ScrollViewController 之后显示(1)。

问题：

从ImagePicker 中选择图像后，如何关闭只是 ImagePicker 以便显示 ScrollViewController 然后将选取的图像传递给 ScrollViewController?

(1) 呈现ScrollViewController和ImagePicker

let storyboard = UIStoryboard(name: "Main", bundle: nil)
let vc = storyboard.instantiateViewControllerWithIdentifier("ScrollViewControllerID") as! ScrollViewController
self.presentViewController(vc, animated: true) {
    let imagePicker = MyImagePickerController()
    imagePicker.delegate = self
    imagePicker.sourceType = .PhotoLibrary
    imagePicker.allowsEditing = false
    imagePicker.modalTransitionStyle = UIModalTransitionStyle.CoverVertical
    vc.presentViewController(imagePicker, animated: true, completion: nil)
}

关闭后处理ImagePicker

func imagePickerController(picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : AnyObject]) {
        let myImage = info[UIImagePickerControllerOriginalImage] as! UIImage

//How to send myImage to the ScrollViewController and close ImagePicker?

}

【问题讨论】：

标签： ios swift uiviewcontroller uiimagepickercontroller presentviewcontroller

【解决方案1】：

MyImagePickerController

class MyImagePickerController: ... {

     var controller:ScrollViewController!

     convenience init(controller: ScrollViewController) {
         self.init()
         self.controller = controller
     }

}

func imagePickerController(picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : AnyObject]) {
    let myImage = info[UIImagePickerControllerOriginalImage] as! UIImage

    controller.imageName = myImage
    self.dismissViewControllerAnimated(true, completion: nil)

}

这就是你将如何应用它

let storyboard = UIStoryboard(name: "Main", bundle: nil)
let vc = storyboard.instantiateViewControllerWithIdentifier("ScrollViewControllerID") as! ScrollViewController
self.presentViewController(vc, animated: true) {
    let imagePicker = MyImagePickerController(controller: vc)
    imagePicker.delegate = self
    imagePicker.sourceType = .PhotoLibrary
    imagePicker.allowsEditing = false
    imagePicker.modalTransitionStyle = UIModalTransitionStyle.CoverVertical
    vc.presentViewController(imagePicker, animated: true, completion: nil)
}

【讨论】：

谢谢，我会试试这个。我可以进一步了解这部分到底是做什么的吗？ convenience init(controller: ScrollViewController) { self.controller = controller}
它提供了你自己的自定义初始化器，convenience init，它允许你接受你自己的变量。然后使用这些变量，您可以访问其他类的内容。因此，您将前一个控制器作为变量接收，然后您可以使用controller.items 或controller.myImage 访问前一个控制器的项目。有意义吗？
谢谢@impression7vx 但是，代码的哪一部分消除了ImagePicker，但在屏幕上保留了ScrollViewController？
啊，我明白了！所以要做到这一点，你只需在 controller.imageName = myImage 之后执行 self.dismissViewControllerAnimated(true, completion: nil) ，它应该删除 imagepicker 并显示 imagePicker 后面的任何内容，即你的 scrollView
不幸的是，convenience init 给出了两个错误：Use of 'self' in property access 'controller' before self.init initializes self 和 Self.init isn't called on all paths before returning from initializer。 self.dismissViewControllerAnimated(true, completion: nil) 似乎也同时解雇了ImagePicker 和ScrollViewController。但是，如果我删除 imagePicker.delegate = self 只有 ImagePicker 被解雇。我将不得不更深入地研究这一切，看看发生了什么。谢谢。