iOS：今天（和明天）@ 0:00:00am 的时间戳 [重复]

Question

我想从今天凌晨 0 点（以及明天）创建一个时间戳。任何人都可以提供一些代码如何将其作为字符串获取吗？

Answer 1

要获得今天上午 12:00，请使用 NSCalendar 获得日、月和年，然后使用这些日期组件（不包括时间）获得 NSDate：

NSDate *now = [NSDate date];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay fromDate:now];
NSDate *thisMorning = [calendar dateFromComponents:components];

要获得明天凌晨 12:00，请添加一天：

NSDate *tomorrowMorning = [calendar dateByAddingUnit:NSCalendarUnitDay value:1 toDate:thisMorning options:0];

要将这些转换为字符串，请使用NSDateFormatter。

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
formatter.dateStyle = NSDateFormatterLongStyle;
formatter.timeStyle = NSDateFormatterLongStyle;

NSString *thisMorningString = [formatter stringFromDate:thisMorning];
NSString *tomorrowMorningString = [formatter stringFromDate:tomorrowMorning];

显然，使用您想要的任何 dateStyle 和 timeStyle（或 dateFormat 字符串）。

---

如果你想要自 1970 年以来的秒数，那就是

NSTimeInterval thisMorningIntervalSince1970 = [thisMorning timeIntervalSince1970];
NSTimeInterval tomorrowMorningIntervalSince1970 = [tomorrowMorning timeIntervalSince1970];

如果您希望将它们作为字符串，则可以是：

NSString *thisMorningTimeIntervalString = [NSString stringWithFormat:@"%f", thisMorningIntervalSince1970];
NSString *tomorrowMorningTimeIntervalString = [NSString stringWithFormat:@"%f", tomorrowMorningIntervalSince1970];

或者

NSString *thisMorningTimeIntervalString = [NSString stringWithFormat:@"%lld", (long long) thisMorningIntervalSince1970];
NSString *tomorrowMorningTimeIntervalString = [NSString stringWithFormat:@"%lld", (long long) tomorrowMorningIntervalSince1970];

Answer 2

给你。

 NSString * yourDate = @"2015-02-13 00:00:00";   
 NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
 [dateFormat setDateFormat:@"yyyy-MM-dd HH:mm:ss"];
 NSDate * date = [dateFormat dateFromString:yourDate]; 
 NSString * timestamp = [NSString stringWithFormat:@"%f",[date timeIntervalSince1970]];