如何检测用户是否停止在 Swift 中摇晃手机

Question

我想知道用户什么时候停止摇晃，什么时候停止摇晃，我想关闭 alertViewController。任何帮助将不胜感激。谢谢。

我已经尝试过使用motionEnded和motionBegan方法。

这是我的代码。当用户停止摇晃手机时，我想关闭 alertViewController。

       let alertController = UIAlertController(title: nil, message:
        "Shaking", preferredStyle: UIAlertController.Style.alert)

    override func motionBegan(_ motion: UIEvent.EventSubtype, with event: UIEvent?) {
        if motion == .motionShake {
            self.present(alertController, animated: true, completion: nil)

        }
    }

    override func motionEnded(_ motion: UIEvent.EventSubtype, with event: UIEvent?) {
        if alertController.isBeingPresented {
            alertController.dismiss(animated: true, completion: nil)
        }
    }

Answer 1

使用以下方法结束运动，更多信息请参阅此帖子https://developer.apple.com/documentation/uikit/uiresponder/1621090-motionended

在委托方法之外声明alertController。

let alertController = UIAlertController(title: nil, message:
    "Shaking", preferredStyle: UIAlertController.Style.alert)

override func motionBegan(_ motion: UIEvent.EventSubtype, with event: UIEvent?) {
    if motion == .motionShake && !alertController.isBeingPresented {
        self.present(alertController, animated: true, completion: nil)

    }
}

override func motionEnded(_ motion: UIEvent.EventSubtype, with event: UIEvent?) {
    if motion == .motionShake {
         alertController.dismiss(animated: true, completion: nil)
    }
}