获取 iOS 上所有联系人的列表

Question

我想获取 iPhone 的所有联系人列表。

我检查了Address Book 参考，我可能遗漏了一些东西，但我没有看到它提供了获取联系人列表的方法。

Answer 1

也许ABPerson 函数ABAddressBookCopyArrayOfAllPeople 可以吗？

Example:

ABAddressBookRef addressBook = ABAddressBookCreate( );
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople( addressBook );
CFIndex nPeople = ABAddressBookGetPersonCount( addressBook );

for ( int i = 0; i < nPeople; i++ )
{
    ABRecordRef ref = CFArrayGetValueAtIndex( allPeople, i );
    ...
}

Answer 2

确保你有正确的导入

#import <AddressBook/AddressBook.h>

然后你可以得到一个包含所有联系人的 CFArray 对象

CFArrayRef ABAddressBookCopyArrayOfAllPeople (ABAddressBookRef addressBook);

Answer 3

在 iOS 6 中，请确保使用 ABAddressBookCreateWithOptions，这是 ABAddressBookCreate 的更新版本

CFErrorRef * error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
CFIndex numberOfPeople = ABAddressBookGetPersonCount(addressBook);

for(int i = 0; i < numberOfPeople; i++){
  ABRecordRef person = CFArrayGetValueAtIndex( allPeople, i );
  // More code here
}

Answer 4

使用此代码显示所有姓名 + 姓氏 + 电话号码 (iOS 6)。也适用于模拟器：

CFErrorRef *error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
CFIndex numberOfPeople = ABAddressBookGetPersonCount(addressBook);

for(int i = 0; i < numberOfPeople; i++) {

    ABRecordRef person = CFArrayGetValueAtIndex( allPeople, i );

    NSString *firstName = (__bridge NSString *)(ABRecordCopyValue(person, kABPersonFirstNameProperty));
    NSString *lastName = (__bridge NSString *)(ABRecordCopyValue(person, kABPersonLastNameProperty));
    NSLog(@"Name:%@ %@", firstName, lastName);

    ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);

    for (CFIndex i = 0; i < ABMultiValueGetCount(phoneNumbers); i++) {
        NSString *phoneNumber = (__bridge_transfer NSString *) ABMultiValueCopyValueAtIndex(phoneNumbers, i);
        NSLog(@"phone:%@", phoneNumber);
    }

    NSLog(@"=============================================");

}

Answer 5

ABAddressBookRef addressBook = ABAddressBookCreate( );
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople( addressBook );
CFIndex nPeople = ABAddressBookGetPersonCount( addressBook );

for ( int i = 0; i < nPeople; i++ )
{
ABRecordRef ref = CFArrayGetValueAtIndex( allPeople, i );
  ...
}

Answer 6

查看https://github.com/heardrwt/RHAddressBook（2014 年 1 月 254 颗星）。

使用更简单的 API 为 AddressBook 提供 ObjC 包装器。

Answer 7

更新iOS 9.0。 Apple 已弃用 AddressBook，现在他们添加了 Contacts 框架：

添加CNContactStore 属性并像这样定义它：

self.contactsStrore = [[CNContactStore alloc] init];

然后添加这些方法来读取所有联系人：

-(void)checkContactsAccess{

[self requestContactsAccessWithHandler:^(BOOL grandted) {

    if (grandted) {

        CNContactFetchRequest *request = [[CNContactFetchRequest alloc] initWithKeysToFetch:@[CNContactFamilyNameKey, CNContactGivenNameKey, CNContactNamePrefixKey, CNContactMiddleNameKey, CNContactPhoneNumbersKey]];
        [self.contactsStrore enumerateContactsWithFetchRequest:request error:nil usingBlock:^(CNContact * _Nonnull contact, BOOL * _Nonnull stop) {

            NSLog(@"%@", contact.familyName);
            NSLog(@"%@", contact.givenName);
            NSLog(@"%@", contact.namePrefix);
            NSLog(@"%@", contact.middleName);
            NSLog(@"%@", contact.phoneNumbers);
            NSLog(@"=============================================");
        }];
    }
}];
}

-(void)requestContactsAccessWithHandler:(void (^)(BOOL grandted))handler{

switch ([CNContactStore authorizationStatusForEntityType:CNEntityTypeContacts]) {
    case CNAuthorizationStatusAuthorized:
        handler(YES);
        break;
    case CNAuthorizationStatusDenied:
    case CNAuthorizationStatusNotDetermined:{
        [self.contactsStrore requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) {

            handler(granted);
        }];
        break;
    }
    case CNAuthorizationStatusRestricted:
        handler(NO);
        break;
}
}

iOS 9.0 之前 => 使用 AddressBook 框架。 您必须先检查访问权限并请求访问用户联系人：

// Prompt the user for access to their Address Book data
-(void)requestAddressBookAccess
{
   YourViewController * __weak weakSelf = self;

  ABAddressBookRequestAccessWithCompletion(self.addressBook, ^(bool granted, CFErrorRef error)
                                         {
                                             if (granted)
                                             {
                                                 dispatch_async(dispatch_get_main_queue(), ^{
                                                     [weakSelf accessGrantedForAddressBook];

                                                 });
                                             }
                                         });
}



-(void)checkAddressBookAccess
{
   switch (ABAddressBookGetAuthorizationStatus())
       {
        // Update our UI if the user has granted access to their Contacts
    case  kABAuthorizationStatusAuthorized:
        [self accessGrantedForAddressBook];
        break;
        // Prompt the user for access to Contacts if there is no definitive answer
    case  kABAuthorizationStatusNotDetermined :
        [self requestAddressBookAccess];
        break;
        // Display a message if the user has denied or restricted access to Contacts
    case  kABAuthorizationStatusDenied:
    case  kABAuthorizationStatusRestricted:
    {
        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Privacy Warning"
                                                        message:@"Permission was not granted for Contacts."
                                                       delegate:nil
                                              cancelButtonTitle:@"OK"
                                              otherButtonTitles:nil];
        [alert show];
    }
        break;
    default:
        break;
 }
   }

Answer 8

感谢 mahesh 和 wzbozon，以下代码对我有用：

CFErrorRef * error = NULL;
addressBook = ABAddressBookCreateWithOptions(NULL, error);
ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error)
 {
     if (granted)
     {
         dispatch_async(dispatch_get_main_queue(), ^{
             CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
             CFIndex numberOfPeople = ABAddressBookGetPersonCount(addressBook);

             for(int i = 0; i < numberOfPeople; i++){
                 ABRecordRef person = CFArrayGetValueAtIndex( allPeople, i );

                 NSString *firstName = (__bridge NSString *)(ABRecordCopyValue(person, kABPersonFirstNameProperty));
                 NSString *lastName = (__bridge NSString *)(ABRecordCopyValue(person, kABPersonLastNameProperty));
                 NSLog(@"Name:%@ %@", firstName, lastName);

                 ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);

                 NSMutableArray *numbers = [NSMutableArray array];
                 for (CFIndex i = 0; i < ABMultiValueGetCount(phoneNumbers); i++) {
                     NSString *phoneNumber = (__bridge_transfer NSString *) ABMultiValueCopyValueAtIndex(phoneNumbers, i);
                     [numbers addObject:phoneNumber];
                 }

                 NSMutableDictionary *contact = [NSMutableDictionary dictionary];
                 [contact setObject:name forKey:@"name"];
                 [contact setObject:numbers forKey:@"numbers"];

                 [all_contacts addObject:contact];
             }
         });
     }
 });

Answer 9

在我的原始答案中，在此答案的末尾，我展示了如何在 9.0 之前的 iOS 版本中检索联系人，以解决此处其他答案所带来的一些问题。

但是，如果只支持 iOS 9 及更高版本，则应该使用Contacts 框架，避免使用旧的AddressBook 框架时出现的一些烦人的桥接问题。

因此，在 iOS 9 中，您将使用 Contacts 框架：

@import Contacts;

您还需要更新您的Info.plist，添加NSContactsUsageDescription 以解释您的应用需要访问联系人的原因。

然后执行如下操作：

CNAuthorizationStatus status = [CNContactStore authorizationStatusForEntityType:CNEntityTypeContacts];
if (status == CNAuthorizationStatusDenied || status == CNAuthorizationStatusRestricted) {
    UIAlertController *alert = [UIAlertController alertControllerWithTitle:@"Access to contacts." message:@"This app requires access to contacts because ..." preferredStyle:UIAlertControllerStyleActionSheet];
    [alert addAction:[UIAlertAction actionWithTitle:@"Go to Settings" style:UIAlertActionStyleDefault handler:^(UIAlertAction * _Nonnull action) {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString] options:@{} completionHandler:nil];
    }]];
    [alert addAction:[UIAlertAction actionWithTitle:@"Cancel" style:UIAlertActionStyleCancel handler:nil]];
    [self presentViewController:alert animated:TRUE completion:nil];
    return;
}

CNContactStore *store = [[CNContactStore alloc] init];
[store requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) {

    // make sure the user granted us access

    if (!granted) {
        dispatch_async(dispatch_get_main_queue(), ^{
            // user didn't grant access;
            // so, again, tell user here why app needs permissions in order  to do it's job;
            // this is dispatched to the main queue because this request could be running on background thread
        });
        return;
    }

    // build array of contacts

    NSMutableArray *contacts = [NSMutableArray array];

    NSError *fetchError;
    CNContactFetchRequest *request = [[CNContactFetchRequest alloc] initWithKeysToFetch:@[CNContactIdentifierKey, [CNContactFormatter descriptorForRequiredKeysForStyle:CNContactFormatterStyleFullName]]];

    BOOL success = [store enumerateContactsWithFetchRequest:request error:&fetchError usingBlock:^(CNContact *contact, BOOL *stop) {
        [contacts addObject:contact];
    }];
    if (!success) {
        NSLog(@"error = %@", fetchError);
    }

    // you can now do something with the list of contacts, for example, to show the names

    CNContactFormatter *formatter = [[CNContactFormatter alloc] init];

    for (CNContact *contact in contacts) {
        NSString *string = [formatter stringFromContact:contact];
        NSLog(@"contact = %@", string);
    }
}];

如果支持 iOS 9.0 之前的 iOS 版本，以下是我的回答。

--

对您的问题以及此处提供的许多答案的一些反应（未请求许可，未正确处理 ABAddressBookCreateWithOptions 错误或泄漏）：

1. 显然，导入AddressBook 框架：

   #import <AddressBook/AddressBook.h>
   

   或

   @import AddressBook;
   

2. 您必须请求应用程序访问联系人的权限。例如：

   ABAuthorizationStatus status = ABAddressBookGetAuthorizationStatus();
   
   if (status == kABAuthorizationStatusDenied || status == kABAuthorizationStatusRestricted) {
       // if you got here, user had previously denied/revoked permission for your
       // app to access the contacts and all you can do is handle this gracefully,
       // perhaps telling the user that they have to go to settings to grant access
       // to contacts
   
       [[[UIAlertView alloc] initWithTitle:nil message:@"This app requires access to your contacts to function properly. Please visit to the \"Privacy\" section in the iPhone Settings app." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil] show];
       return;
   }
   
   CFErrorRef error = NULL;
   ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);
   
   if (!addressBook) {
       NSLog(@"ABAddressBookCreateWithOptions error: %@", CFBridgingRelease(error));
       return;
   }
   
   ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
       if (error) {
           NSLog(@"ABAddressBookRequestAccessWithCompletion error: %@", CFBridgingRelease(error));
       }
   
       if (granted) {
           // if they gave you permission, then just carry on
   
           [self listPeopleInAddressBook:addressBook];
       } else {
           // however, if they didn't give you permission, handle it gracefully, for example...
   
           dispatch_async(dispatch_get_main_queue(), ^{
               // BTW, this is not on the main thread, so dispatch UI updates back to the main queue
   
               [[[UIAlertView alloc] initWithTitle:nil message:@"This app requires access to your contacts to function properly. Please visit to the \"Privacy\" section in the iPhone Settings app." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil] show];
           });
       }
   
       CFRelease(addressBook);
   });
   

3. 注意以上，我没有使用别人建议的模式：

   CFErrorRef *error = NULL;
   ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
   

   这是不正确的。正如您将在上面看到的，您想要：

   CFErrorRef error = NULL;
   ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);
   

   前一种模式不能正确捕捉错误，而后者会。如果error 不是NULL，请不要忘记CFRelease（或像我一样将所有权转让给ARC），否则您将泄露该对象。

4. 要遍历联系人，您需要：

   - (void)listPeopleInAddressBook:(ABAddressBookRef)addressBook
   {
       NSArray *allPeople = CFBridgingRelease(ABAddressBookCopyArrayOfAllPeople(addressBook));
       NSInteger numberOfPeople = [allPeople count];
   
       for (NSInteger i = 0; i < numberOfPeople; i++) {
           ABRecordRef person = (__bridge ABRecordRef)allPeople[i];
   
           NSString *firstName = CFBridgingRelease(ABRecordCopyValue(person, kABPersonFirstNameProperty));
           NSString *lastName  = CFBridgingRelease(ABRecordCopyValue(person, kABPersonLastNameProperty));
           NSLog(@"Name:%@ %@", firstName, lastName);
   
           ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
   
           CFIndex numberOfPhoneNumbers = ABMultiValueGetCount(phoneNumbers);
           for (CFIndex j = 0; j < numberOfPhoneNumbers; j++) {
               NSString *phoneNumber = CFBridgingRelease(ABMultiValueCopyValueAtIndex(phoneNumbers, j));
               NSLog(@"  phone:%@", phoneNumber);
           }
   
           CFRelease(phoneNumbers);
   
           NSLog(@"=============================================");
       }
   }
   

5. 我想提请您注意一个相当关键的细节，即"Create Rule"：

   Core Foundation 函数的名称表明您何时拥有返回的对象：

   • 名称中嵌入“Create”的对象创建函数；

   • 名称中嵌入了“Copy”的对象复制函数。

   如果您拥有一个对象，则您有责任在完成该对象后放弃所有权（使用 CFRelease）。

   这意味着您有责任释放名称中带有Create 或Copy 的任何Core Foundation 函数返回的任何对象。您可以显式调用CFRelease（就像我在上面使用addressBook 和phoneNumbers 所做的那样），或者，对于支持免费桥接的对象，您可以使用__bridge_transfer 或CFBridgingRelease 将所有权转移给ARC（正如我上面使用allPeople、lastName、firstName 和phoneNumber）。

   静态分析器（在 Xcode 中按 shift+command+B 或从“产品”菜单中选择“分析”）可以识别在许多情况下，您忽略了遵守此“创建规则”并且未能释放适当的对象。因此，每当编写这样的 Core Foundation 代码时，请始终通过静态分析器运行它，以确保您没有任何明显的泄漏。

Answer 10

这适用于 ios 7 和 ios 8，希望对您有所帮助......

NSMutableArray *result = [[NSMutableArray alloc] init];
CFErrorRef *error = nil;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
__block BOOL accessGranted = NO;

if (ABAddressBookRequestAccessWithCompletion != NULL){
    dispatch_semaphore_t sema = dispatch_semaphore_create(0);

    ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
        accessGranted = granted;
        dispatch_semaphore_signal(sema);
    });
    dispatch_semaphore_wait(sema, DISPATCH_TIME_FOREVER);
}
else{
    accessGranted = YES;
}
if (accessGranted){
    // If the app is authorized to access the first time then add the contact
    ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
    CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
    CFIndex numberOfPeople = ABAddressBookGetPersonCount(addressBook);

    for (int i=0; i<numberOfPeople; i++){
        CFStringRef phone;
        ABRecordRef person = CFArrayGetValueAtIndex(allPeople, i);
        CFStringRef firstName = ABRecordCopyValue(person, kABPersonFirstNameProperty);
        CFStringRef lastName = ABRecordCopyValue(person, kABPersonLastNameProperty);
        NSString *userName = @"NoName";

        userName = [NSString stringWithFormat:@"%@ %@", firstName, lastName];
        userName = [userName stringByReplacingOccurrencesOfString:@"(null)" withString:@""];

        ABMutableMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
        CFIndex phoneNumberCount = ABMultiValueGetCount( phoneNumbers );

        phone = nil;

        for ( CFIndex ind= 0; ind<phoneNumberCount; ind++ ){
            CFStringRef phoneNumberLabel = ABMultiValueCopyLabelAtIndex( phoneNumbers, ind);
            CFStringRef phoneNumberValue = ABMultiValueCopyValueAtIndex( phoneNumbers, ind);

            // converts "_$!<Work>!$_" to "work" and "_$!<Mobile>!$_" to "mobile"
            // Find the ones you want here
            if (phoneNumberLabel != nil){
                NSStringCompareOptions  compareOptions = NSCaseInsensitiveSearch;
                if(CFStringCompare(phoneNumberLabel, CFSTR("mobile"),compareOptions)){
                    phone = phoneNumberValue;
                }
                phone = phoneNumberValue;

                NSStringCompareOptions  compareOptionss = NSCaseInsensitiveSearch;
                if(!CFStringCompare(phone, CFSTR("1-800-MY-APPLE"),compareOptionss)){
                    continue;
                }
                NSMutableArray *theKeys = [NSMutableArray arrayWithObjects:@"name", @"small_name",@"phone", @"checked", nil];
                NSMutableArray *theObjects = [NSMutableArray arrayWithObjects:userName, [userName lowercaseString],phone, @"NO", nil];
                NSMutableDictionary *theDict = [NSMutableDictionary dictionaryWithObjects:theObjects forKeys:theKeys];
                if (![[functions formatNumber:(__bridge NSString *)(phone)] isEqualToString:[[NSUserDefaults standardUserDefaults]valueForKey:@"phoneNumber"]]){
                    [result addObject:theDict];
                }
            }
        }
    }
}
//sort array
NSSortDescriptor * descriptor = [[NSSortDescriptor alloc] initWithKey:@"small_name"
                                                            ascending:YES]; // 1
NSArray * sortedArray = [result sortedArrayUsingDescriptors:[NSArray arrayWithObject:descriptor]];

Answer 11

Swift 版本：

override func viewDidLoad() {
    super.viewDidLoad()

    var error: Unmanaged<CFErrorRef>?

    var addressBook: ABAddressBook = ABAddressBookCreateWithOptions(nil, &error).takeRetainedValue()


    if ABAddressBookGetAuthorizationStatus() == ABAuthorizationStatus.NotDetermined {
        ABAddressBookRequestAccessWithCompletion(addressBook,  {

            (granted:Bool, error:CFErrorRef!) -> Void in

            self.populateFrom(addressBook: addressBook)

        })
    }
    else if ABAddressBookGetAuthorizationStatus() == ABAuthorizationStatus.Authorized {

        self.populateFrom(addressBook: addressBook)

    }

}

func populateFrom(#addressBook:ABAddressBook){
    let allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook).takeRetainedValue()
    let nPeople = ABAddressBookGetPersonCount(addressBook)
    for index in 0..<nPeople{
        let person: ABRecordRef = Unmanaged<ABRecordRef>.fromOpaque(COpaquePointer(CFArrayGetValueAtIndex(allPeople, index))).takeUnretainedValue()
        let firstName: String = ABRecordCopyValue(person, kABPersonFirstNameProperty).takeUnretainedValue() as? String
        println("\(firstName.debugDescription)")


    }

}

Answer 12

这是使用表格视图获取所有联系人的完整演示。

import UIKit
import ContactsUI
import AddressBook
import Contacts

class ShowContactsVC: UIViewController,CNContactPickerDelegate,UITableViewDelegate,UITableViewDataSource
{



@IBOutlet weak var tableView: UITableView!
let peoplePicker = CNContactPickerViewController()
let appDelegate = UIApplication.sharedApplication().delegate as! AppDelegate
var contacts = [CNContact]()
var option : Int = 0
var userAccessGranted : Bool = false
var dataArray : NSMutableArray?




override func viewDidLoad()
{
    super.viewDidLoad()

    peoplePicker.delegate = self

    self.checkIfUserAccessGranted()

    self.tableView.delegate = self
    self.tableView.dataSource = self


    navigationController!.navigationBar.barTintColor = UIColor.grayColor()


              if(self.userAccessGranted)
      {
         self.tableView.hidden = false
        fetchContacts()

    }

}

func numberOfSectionsInTableView(tableView: UITableView) -> Int
{
    return 1
}

func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int
{
    if dataArray == nil {
        return 0;
    }
    else{


    return dataArray!.count
}
}

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell
{
    let cell = tableView.dequeueReusableCellWithIdentifier("TableCell", forIndexPath: indexPath) as! ContactsTableViewCell



    let data = dataArray![indexPath.row] as! Data;
    cell.lblName.text = data.name
    cell.imgContact.image = data.image
    return cell
}

func tableView(tableView: UITableView, willDisplayCell cell: UITableViewCell, forRowAtIndexPath indexPath: NSIndexPath)
{
    cell.backgroundColor = UIColor.cyanColor()

}




func checkIfUserAccessGranted()
{
    appDelegate.requestForAccess { (accessGranted) -> Void in
        if accessGranted {
            self.userAccessGranted = true;
        }else{
            self.userAccessGranted = false;
        }
    }
}





func fetchContacts()
{

    dataArray = NSMutableArray()

    let toFetch = [CNContactGivenNameKey, CNContactImageDataKey, CNContactFamilyNameKey, CNContactImageDataAvailableKey]
    let request = CNContactFetchRequest(keysToFetch: toFetch)

    do{
        try appDelegate.contactStore.enumerateContactsWithFetchRequest(request) {
            contact, stop in
            print(contact.givenName)
            print(contact.familyName)
            print(contact.identifier)

            var userImage : UIImage;
            // See if we can get image data
            if let imageData = contact.imageData {
                //If so create the image
                userImage = UIImage(data: imageData)!
            }else{
                userImage = UIImage(named: "no_contact_image")!
            }

            let data = Data(name: contact.givenName, image: userImage)
            self.dataArray?.addObject(data)

        }
    } catch let err{
        print(err)

    }

    self.tableView.reloadData()

}

func contactPickerDidCancel(picker: CNContactPickerViewController)
{
    picker.dismissViewControllerAnimated(true, completion: nil)
    self.navigationController?.popToRootViewControllerAnimated(true)
}



override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}



}




import UIKit

class Data {


    let name : String
    let image : UIImage

    init(name : String, image : UIImage) {
        self.image = image
        self.name = name
    }

}

Answer 13

如果你想按字母顺序排序，你可以使用下面的代码。

 CFErrorRef *error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
CFIndex numberOfPeople = ABAddressBookGetPersonCount(addressBook);

CFMutableArrayRef peopleMutable = CFArrayCreateMutableCopy(kCFAllocatorDefault,
                                                           CFArrayGetCount(allPeople),
                                                           allPeople);

CFArraySortValues(peopleMutable,
                  CFRangeMake(0, CFArrayGetCount(peopleMutable)),
                  (CFComparatorFunction) ABPersonComparePeopleByName,
                  kABPersonSortByFirstName);