【问题标题】:Require a leading + in input需要一个前导 + 输入
【发布时间】:2017-02-17 00:47:09
【问题描述】:

如何更新此代码以使前导加号 + 字符成为必需?

<script type="text/javascript" language="javascript">

// Declaring required variables
var digits = "0123456789";
// non-digit characters which are allowed in phone numbers
var phoneNumberDelimiters = "()- ";
// characters which are allowed in international phone numbers
// (a leading + is OK)
var validWorldPhoneChars = phoneNumberDelimiters + "+";
// Minimum no of digits in an international phone no.
var minDigitsInIPhoneNumber = 10;

function isInteger(s)
{   var i;
    for (i = 0; i < s.length; i++)
    {   
        // Check that current character is number.
        var c = s.charAt(i);
        if (((c < "0") || (c > "9"))) return false;
    }
    // All characters are numbers.
    return true;
}
function trim(s)
{   var i;
    var returnString = "";
    // Search through string's characters one by one.
    // If character is not a whitespace, append to returnString.
    for (i = 0; i < s.length; i++)
    {   
        // Check that current character isn't whitespace.
        var c = s.charAt(i);
        if (c != " ") returnString += c;
    }
    return returnString;
}
function stripCharsInBag(s, bag)
{   var i;
    var returnString = "";
    // Search through string's characters one by one.
    // If character is not in bag, append to returnString.
    for (i = 0; i < s.length; i++)
    {   
        // Check that current character isn't whitespace.
        var c = s.charAt(i);
        if (bag.indexOf(c) == -1) returnString += c;
    }
    return returnString;
}

function checkInternationalPhone(strPhone){
    var bracket=3
    strPhone=trim(strPhone)
    if(strPhone.indexOf("+")>1) return false
    if(strPhone.indexOf("-")!=-1)bracket=bracket+1
    if(strPhone.indexOf("(")!=-1 && strPhone.indexOf("(")>bracket)return false
    var brchr=strPhone.indexOf("(")
    if(strPhone.indexOf("(")!=-1 && strPhone.charAt(brchr+2)!=")")return     false
    if(strPhone.indexOf("(")==-1 && strPhone.indexOf(")")!=-1)return false
    s=stripCharsInBag(strPhone,validWorldPhoneChars);
    return (isInteger(s) && s.length >= minDigitsInIPhoneNumber);
}

function ValidateForm(){
    var Phone=document.frm_cntctus.custom_phone

    if ((Phone.value==null)||(Phone.value=="")){
        alert("Please enter your phone number")
        Phone.focus()
        return false
    }
    if (checkInternationalPhone(Phone.value)==false){
        alert("Please enter a valid phone number.")
        Phone.value=""
        Phone.focus()
        return false
    }
    return true
 }
</script>

【问题讨论】:

    标签: javascript html validation phone-number


    【解决方案1】:

    您可以使用正则表达式来实现这一点。你的问题已经回答了。看看这些链接:

    Javascript Regex - What to use to validate a phone number?

    What regular expression will match valid international phone numbers?

    【讨论】:

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