来自生物识别设备的考勤记录答案

【问题标题】：Attendance record from bio-metric device来自生物识别设备的考勤记录
【发布时间】：2017-07-04 08:53:36
【问题描述】：

这是我的数据

|Id     |EmpCode    |CheckInCheckOutDate        |WorkDate                   |InOutMode  
|247    |51         |2017-02-13 20:08:52.000    |2017-02-13 20:08:52.000    |0          
|392    |51         |2017-02-13 22:38:51.000    |2017-02-13 22:38:51.000    |1          
|405    |51         |2017-02-13 22:59:18.000    |2017-02-13 22:59:18.000    |0          
|415    |51         |2017-02-13 23:18:17.000    |2017-02-13 23:18:17.000    |1          
|423    |51         |2017-02-13 23:33:44.000    |2017-02-13 23:33:44.000    |0          
|456    |51         |2017-02-14 01:30:15.000    |2017-02-13 01:30:15.000    |1          
|463    |51         |2017-02-14 02:52:02.000    |2017-02-13 02:52:02.000    |0          
|483    |51         |2017-02-14 05:11:54.000    |2017-02-13 05:11:54.000    |1          
|1034   |51         |2017-02-14 20:09:23.000    |2017-02-14 20:09:23.000    |0          
|1172   |51         |2017-02-14 21:59:23.000    |2017-02-14 21:59:23.000    |1          
|1217   |51         |2017-02-14 22:30:28.000    |2017-02-14 22:30:28.000    |0          
|1238   |51         |2017-02-14 22:49:51.000    |2017-02-14 22:49:51.000    |1          
|1257   |51         |2017-02-14 23:19:10.000    |2017-02-14 23:19:10.000    |0          
|1315   |51         |2017-02-15 05:04:16.000    |2017-02-14 05:04:16.000    |1          
|1323   |51         |2017-02-15 05:05:17.000    |2017-02-14 05:05:17.000    |0          
|1329   |51         |2017-02-15 05:08:17.000    |2017-02-14 05:08:17.000    |1
|1330   |51         |2017-02-15 05:08:18.000    |2017-02-14 05:08:18.000    |1

我用过这段代码：

SELECT EmpCode,
        CAST(I.CheckInCheckOutDate AS DATE) AS [Date],
        CAST(I.WorkDate AS DATE) AS WorkDate,
        CONVERT(VARCHAR(10), I.WorkDate, 108) AS CheckIn,
        CONVERT(VARCHAR(10), O.WorkDate, 108) AS CheckOut,
       CAST(DATEDIFF(second,I.WorkDate,O.WorkDate)/3600.0 AS DECIMAL(18,9)) [TotalHours]
FROM tblAttendance I
OUTER APPLY (
                SELECT TOP 1 WorkDate,inOutMode FROM tblAttendance t
                WHERE t.EmpCode = I.EmpCode AND t.WorkDate > I.WorkDate
                ORDER BY t.WorkDate
            ) O

WHERE I.inOutMode = 0
AND O.inOutMode = 1 and I.empCode=51

代码的结果是：

|EmpCode|Date|      |WorkDate   |CheckIn    |CheckOut   |TotalHours
|51     |2017-02-13 |2017-02-13 |20:08:52   |22:38:51   |2.499722000
|51     |2017-02-13 |2017-02-13 |22:59:18   |23:18:17   |0.316388000
|51     |2017-02-13 |2017-02-13 |23:33:44   |05:04:16   |5.508888000
|51     |2017-02-14 |2017-02-13 |02:52:02   |05:11:54   |2.331111000
|51     |2017-02-14 |2017-02-14 |20:09:23   |21:59:23   |1.833333000
|51     |2017-02-14 |2017-02-14 |22:30:28   |22:49:51   |0.323055000
|51     |2017-02-15 |2017-02-14 |05:05:17   |05:08:17   |0.050000000

每当我添加 TotalHours hours Group By WorkDate 时，它都会给出错误的答案。

【问题讨论】：

这里的人肯定喜欢点击关闭按钮。在我看来，OP 已经为这个（他们的第一个）问题付出了努力。我们需要帮助 OP 改进问题，而不是仅仅投票关闭它。
Whenever I am adding TotalHours hours Group By WorkDate, it is giving incorrect answer. 这没有帮助。请添加您的预期结果和实际结果
也看这里来改进问题：spaghettidba.com/2015/04/24/…

标签： sql-server sql-server-2008 sql-server-2005 sql-server-2008-r2 sql-server-ce

【解决方案1】：

也许您需要添加一个明确的总和： http://www.w3resource.com/sql/aggregate-functions/sum-with-group-by.php:

SELECT TOP 1 WorkDate, inOutMode, SUM (TotalHours) FROM tblAttendance t

WHERE t.EmpCode = I.EmpCode AND t.WorkDate > I.WorkDate
GROUP BY WorkDate, inOutMode

ORDER BY t.WorkDate

（未经测试，如果这没有帮助，很抱歉 - 我知道的 SQL 非常有限：P）

【讨论】：

至少您的 SUM 需要是查询中的一列。正如发布的那样，它是无效的语法，因为 SUM 只是漂浮在无处可去的地方。
@SeanLange 预计它不会起作用，但您发表的评论让我至少尝试提供帮助。