如何以指定格式将数组的值输出到文本文件答案

【问题标题】：HOW TO output the values of an array to a text file in a specified format如何以指定格式将数组的值输出到文本文件
【发布时间】：2020-04-27 09:22:12
【问题描述】：

我正在使用 DBATools 模块 Invoke-DBQQuery（基于 Invoke-SQLCMD2）来查询 SQL 数据库。该查询将单个记录作为名为 $Results 的 PSObject 返回，如下所示...

FileName       : C12345
BADGENUMBER    : BADGENUMBER=12345
LASTNAME       : LASTNAME=SMITH
FIRSTNAME      : FIRSTNAME=JOHN
CIA            : CIA=YES
SOCIALSECURITY : SOCIALSECURITY=999999999
DACDATE        : DACDATE=07/16/2022
UIC            : UIC=42158

我需要将这个 PSObject 输出到一个 TXT 文件，只有值 no 字段标题每行一个字段。看起来像这样……

C12345
BADGENUMBER=12345
LASTNAME=SMITH
FIRSTNAME=JOHN
CIA=YES
SOCIALSECURITY=999999999
DACDATE=07/16/2022
UIC=42158

如何以我需要的格式生成测试文件？

$Results| Out-File c:\test.test.txt

产生我列出的第一个输出。

感谢任何人可以提供的任何帮助。

-标记-

【问题讨论】：

$Results.psobject.Properties.Value |Out-File test.txt
如果没有 BADGENUMBER= ，这不只是输出 12345 吗？
这不起作用...文件已创建但它是空的

标签： powershell formatting psobject dbatools

【解决方案1】：

这里有一些不同的角度来解决

$result = Invoke-DbaQuery -SqlInstance $sql -Query 'select * from MyTable' -As PSObject

# Simulate a 2 rows result
$result = [PSCustomObject]@{
    FileName       = 'C12345'
    BADGENUMBER    = 'BADGENUMBER=12345'
    LASTNAME       = 'LASTNAME=SMITH'
    FIRSTNAME      = 'FIRSTNAME=JOHN'
    CIA            = 'CIA=YES'
    SOCIALSECURITY = 'SOCIALSECURITY=999999999'
    DACDATE        = 'DACDATE=07/16/2022'
    UIC            = 'UIC=42158'
},[PSCustomObject]@{
    FileName       = 'C12345'
    BADGENUMBER    = 'BADGENUMBER=12345'
    LASTNAME       = 'LASTNAME=SMITH'
    FIRSTNAME      = 'FIRSTNAME=JOHN'
    CIA            = 'CIA=YES'
    SOCIALSECURITY = 'SOCIALSECURITY=999999999'
    DACDATE        = 'DACDATE=07/16/2022'
    UIC            = 'UIC=42158'
}
# Using RegEx -replace to remove the front part
($result | Out-String) -replace '(?m)^[\w\s]+:\s','' | Out-File C:\Temp\test1.txt

# Looping for every properties (they will get reordered by property name)
# I just saw Mathias suggestion and it would produce the same result
$result | Get-Member -Type NoteProperty | ForEach-Object {$result.($_.Name)} | Out-File C:\Temp\test2.txt

# Simplier solution
$output = foreach ($row in $result) {
    $row.FileName
    $row.BADGENUMBER
    $row.LASTNAME
    $row.FIRSTNAME
    $row.CIA
    $row.SOCIALSECURITY
    $row.DACDATE
    $row.UIC
    "" # you probably want to have an empty row seperating each record
}
$output | Out-File C:\Temp\test3.txt

【讨论】：