【问题标题】:Cannot retrieve data in ascending order无法按升序检索数据
【发布时间】:2018-09-24 16:51:39
【问题描述】:

我想按升序检索数据,但收到的数据以某种方式按降序添加到 recyclerview。

Firebase 数据库:

我在做什么:

    DatabaseReference mDatabase = FirebaseDatabase.getInstance().getReference().child("/Teacher");

    Query query = mDatabase.orderByChild("rating");

    FirebaseRecyclerOptions<Teacher> options =
            new FirebaseRecyclerOptions.Builder<Teacher>()
                    .setQuery(query, Teacher.class)
                    .build();

    FirebaseRecyclerAdapter adapter = new FirebaseRecyclerAdapter<Teacher, TeacherViewHolder>(options) {
        @NonNull
        @Override
        public TeacherViewHolder onCreateViewHolder(@NonNull ViewGroup parent, int viewType) {
            View view = LayoutInflater.from(parent.getContext())
                    .inflate(R.layout.teacher_list_item, parent, false);

            return new TeacherViewHolder(view);

        }

        @Override
        protected void onBindViewHolder(@NonNull final TeacherViewHolder holder, int position, @NonNull final Teacher model) {

           // some stuff here

        }
    };

【问题讨论】:

    标签: android firebase firebase-realtime-database firebaseui


    【解决方案1】:

    由于您无法使用 RTDB 本地执行此操作,您可能需要执行以下操作:

    LinearLayoutManager layoutManager = new LinearLayoutManager(context);
    layoutManager.setReverseLayout(true);
    layoutManager.setStackFromEnd(true);
    recyclerView.setLayoutManager(layoutManager);
    

    更多详情请见https://stackoverflow.com/a/27727398/4548500

    【讨论】:

      【解决方案2】:

      要获得排序和过滤的结果,您必须将查询传递给 FirebaseRecyclerAdapter 构造函数:

      public MyFireAdapterDiasFiestaRecyclerView(
          Class<DiaFiestaMeta> modelClass, 
          int modelLayout, 
          Class<MyFireViewHolder> viewHolderClass, 
          Query query) {
          ...
      

      然后使用排序和过滤的查询调用它:

      adapter = new MyFireAdapterDiasFiestaRecyclerView(
         DiaFiestaMeta.class,
         layout_that_you_use,
         MyFireViewHolder.class,
         ref.orderByChild("property_to_sort_and_filter_on").equalTo("value_to_filter_on")
      );
      

      【讨论】:

        猜你喜欢
        • 1970-01-01
        • 1970-01-01
        • 1970-01-01
        • 2018-11-15
        • 2013-11-16
        • 2020-07-07
        • 1970-01-01
        相关资源
        最近更新 更多