【问题标题】:SQL server select distinct rows using most recent value onlySQL Server 仅使用最近的值选择不同的行
【发布时间】:2011-03-27 10:55:56
【问题描述】:

我有一个包含以下列的表格

  • 身份证
  • 外键ID
  • 属性名
  • 属性值
  • 已创建

部分数据可能如下所示:

1, 1, 'EmailPreference', 'Text', 1/1/2010
2, 1, 'EmailPreference', 'Html', 1/3/2010
3, 1, 'EmailPreference', 'Text', 1/10/2010
4, 2, 'EmailPreference', 'Text', 1/2/2010
5, 2, 'EmailPreference', 'Html', 1/8/2010

我想运行一个查询,为每个不同的 ForeignKeyId 和 AttributeName 提取 AttributeValue 列的最新值,并使用 Created 列来确定最新值。示例输出为:

ForeignKeyId AttributeName    AttributeValue Created
-------------------------------------------------------
1           'EmailPreference' 'Text'         1/10/2010
2           'EmailPreference' 'Html'         1/8/2010

如何使用 SQL Server 2005 做到这一点?

【问题讨论】:

  • EmailPreference/Text/ 1/10/2010 的值不应该是 3,而不是 1?
  • 不,输出的第一列是外键id,不是行id

标签: sql sql-server sql-server-2005 tsql greatest-n-per-group


【解决方案1】:

一种方式

select t1.* from (select ForeignKeyId,AttributeName, max(Created) AS MaxCreated
from  YourTable
group by ForeignKeyId,AttributeName) t2
join YourTable t1 on t2.ForeignKeyId = t1.ForeignKeyId
and t2.AttributeName = t1.AttributeName
and t2.MaxCreated = t1.Created

另请参阅Including an Aggregated Column's Related Values,了解执行此类查询的 5 种不同方式

【讨论】:

  • 如果 created/MaxCreated 不是唯一的,那么您仍然会得到多个结果。可以避免吗?
【解决方案2】:

用途:

SELECT x.foreignkeyid,
       x.attributename,
       x.attributevalue,
       x.created
  FROM (SELECT t.foreignkeyid,
               t.attributename,
               t.attributevalue,
               t.created,
               ROW_NUMBER() OVER (PARTITION BY t.foreignkeyid, t.attributename 
                                      ORDER BY t.created DESC) AS rank
          FROM TABLE t) x
 WHERE x.rank = 1

使用 CTE:

WITH summary AS (
    SELECT t.foreignkeyid,
           t.attributename,
           t.attributevalue,
           t.created,
           ROW_NUMBER() OVER (PARTITION BY t.foreignkeyid, t.attributename 
                                  ORDER BY t.created DESC) AS rank
      FROM TABLE t)
SELECT x.foreignkeyid,
       x.attributename,
       x.attributevalue,
       x.created
  FROM summary x
 WHERE x.rank = 1

还有:

SELECT t.foreignkeyid,
       t.attributename,
       t.attributevalue,
       t.created
  FROM TABLE t
  JOIN (SELECT x.foreignkeyid,
               x.attributename,
               MAX(x.created) AS max_created
          FROM TABLE x
      GROUP BY x.foreignkeyid, x.attributename) y ON y.foreignkeyid = t.foreignkeyid
                                                 AND y.attributename = t.attributename
                                                 AND y.max_created = t.created

【讨论】:

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