从聚合函数中排除一些记录答案

【问题标题】：Exclude some records from aggregate function从聚合函数中排除一些记录
【发布时间】：2013-07-05 13:24:17
【问题描述】：

拥有这段 SQL 代码：

MIN([Price]) OVER (PARTITION BY [Brand], [Article]) AS MinPrice,

问题：如何从MIN() 中排除一些记录，其中 a.e. [Supplier] != 10?

【问题讨论】：

【解决方案1】：

将WHERE [Supplier] != 10 添加到您的查询中。

【讨论】：

我说的是查询。 SELECT MIN([Price]) OVER (PARTITION BY [Brand], [Article]) AS MinPrice FROM Table WHERE [Supplier] != 10
又出问题了，最好把我的代码显示出来：SELECT TOP 1000 p.* FROM (SELECT p.*, MIN([SDA_COST]) OVER (PARTITION BY [SDA_BRA_ID], [SDA_ART_ID]) AS MinPrice, MIN([SDA_COST]) OVER (PARTITION BY [SDA_BRA_ID], [SDA_ART_ID]) AS MinConcPrice FROM [autoparts_portal].[dbo].[CI_SUP_DATA] p ) p where [SDA_SUP_ID] = 10 AND ([SDA_COST] < 0.98 * MinConcPrice OR [SDA_COST] != MinPrice); GO
我只需要从每个组的 MIN 函数中排除指定供应商的记录或执行任何其他检查逻辑。
使用此代码：SELECT TOP 1000 p.* FROM (SELECT p.*, MIN([Price]) OVER (PARTITION BY [Brand], [Article]) AS MinPrice, (SELECT MIN([Price]) OVER (PARTITION BY [Brand], [Article]) FROM [autoparts_portal].[dbo].[CI_SUP_DATA] WHERE [Supplier] != 10) AS MinConcPrice FROM [autoparts_portal].[dbo].[CI_SUP_DATA] p ) p where [SDA_SUP_ID] = 10 AND ([Price] < 0.98 * MinConcPrice OR [Price] > MinPrice); GO

出现错误“嵌套查询返回多个值”
子查询 (SELECT MIN([Price]) OVER (PARTITION BY [Brand], [Article]) FROM [autoparts_portal].[dbo].[CI_SUP_DATA] WHERE [Supplier] != 10) 将返回不止一行。这就是它所抱怨的，我怀疑。包含在 SELECT 子句（与 FROM 子句相反）中的子查询必须只返回一个值。