SQL - 使用 MAX 函数按问题分组两列

Question

SELECT artist.name, recording.name, MAX(recording.length)
FROM recording 
INNER JOIN (artist_credit 
            INNER JOIN (artist_credit_name 
                        INNER JOIN artist 
                                ON artist_credit_name.artist_credit=artist.id)
                    ON artist_credit_name.artist_credit=artist_credit.id)
        ON recording.artist_credit=artist_credit.id
WHERE artist.gender=1 
  AND recording.length <= (SELECT MAX(recording.length) FROM recording)
GROUP BY artist.name, recording.name
ORDER BY artist.name

我们在学校使用 MusicBrainz 数据库，但我们在使用“GROUP BY”时遇到了问题，因为我们有两列（它适用于一列，但不是两列）。我们希望结果只显示一位录制时间第二长的艺术家，但代码显示同一艺术家每首歌曲的所有录制时间。 有什么建议？谢谢。

Answer 1

您无需仔细查看连接条件进行多次连接。它们可以减少到只有一个连接，如下所示。

SELECT DISTINCT B.name, A.name, A.length
FROM recording A JOIN artist B
ON A.artist_credit=B.id
WHERE B.gender=1
AND A.length=(SELECT C.length FROM recording C    
              WHERE C.artist_credit=B.artist_credit 
              ORDER BY C.length LIMIT 1, 1)
ORDER BY B.name;

见Using MySQL LIMIT to get the nth highest value

Answer 2

正如其他人所指出的，可以减少连接语句。 AND语句中的运算符似乎也有问题；它应该是 What is the simplest SQL Query to find the second largest value?）。

我建议尝试以下方法：

SELECT artist.name, recording.name, MAX(recording.length)
FROM recording 
JOIN artist ON recording.artist_credit = artist.id
WHERE 
    artist.gender=1 
    AND 
    recording.length < (SELECT MAX(recording.length) FROM recording)
GROUP BY artist.name
ORDER BY artist.name