为聚合列添加小计列

Question

这是我的交易、交易者和交易对手数据集：

TRADER_ID  | TRADER_NAME     | EXEC_BROKER | TRADE_AMOUNT  | TRADE_ID
    ABC123 | Jules Winnfield | GOLD        | 10000         | ASDADAD
    XDA241 | Jimmie Dimmick  | GOLD        | 12000         | ASSVASD
    ADC123 | Vincent Vega    | BARC        | 10000         | ZXCZCX
    ABC123 | Jules Winnfield | BARC        | 15000         | ASSXCQA
    ADC123 | Vincent Vega    | CRED        | 250000        | RFAQQA
    ABC123 | Jules Winnfield | CRED        | 5000          | ASDQ23A
    ABC123 | Jules Winnfield | GOLD        | 5000          | AVBDQ3A

我希望生成一份可重复的月度报告，让我可以查看在交易对手（EXEC_BROKER 字段）级别汇总的交易活动，并带有小计 - 如下所示：

TRADER_ID | TRADER_NAME | NO._OF_CCP_USED | CCP | TRADED_AMT_WITH_CCP | VALUE_OF_TOTAL_TRADES | TRADES_WITH_CCP | TOTAL_TRADES
    ABC123 | Jules Winnfield | 3 | GOLD | 15000 | 35000 | 2 | 4
    ABC123 | Jules Winnfield | 3 | BARC | 15000 | 35000 | 1 | 4
    ABC123 | Jules Winnfield | 3 | CRED | 5000 | 35000 | 1 | 4

...以此类推。

这个想法是汇总每个交易对手的交易数量（我已经使用计数函数完成了），以及使用 ccp 的交易金额总和，但我很难获得每个交易对手旁边的“小计”字段交易者，如上面我想要的输出所示 - 所以你可以在这里看到 Jules 总共与 3 个交易对手打交道，他们之间有 4 笔交易，总金额为 35000。

我尝试过使用聚合和 over by 函数的组合，但无济于事。

SELECT
     OT.TRADER_ID,
     OT.TRADER_NAME,
     OT.EXEC_BROKER,
     SUM(OT.TRADE_AMOUNT) AS VALUE_OF_TOTAL_TRADES,
     COUNT(OT.TRADE_ID) AS TOTAL_TRADES,
     COUNT(OT.EXEC_BROKER) OVER PARTITION BY (OT.TRADER_ID) AS NO._OF_CCP_USED, 
     SUM(OT.TRADE_AMOUNT) OVER PARTITION BY (OT.EXEC_BROKER) AS TRADED_AMT_WITH_CCP,
     COUNT(OT.TRADE_ID) OVER PARTITION BY (OT.EXEC_BROKER) AS TRADES_WITH_CCP

FROM dbo.ORDERS_TRADES OT

GROUP BY OT.TRADER_ID, OT.TRADER_NAME, OT.EXEC_BROKER, OT.TRADE_AMOUNT, OT.TRADE_ID

上面的代码运行但返回数百万行。当我按行删除分区时，我得到的结果减去我正在寻找的小计列。

有什么建议吗？非常感谢！

编辑：

为我提供了所需输出的最终代码：更新我的问题以提供此响应（感谢 Gordon Linoff），以便其他人受益：

SELECT
         OT.TRADER_ID,
         OT.TRADER_NAME,
         OT.EXEC_BROKER,
         RANK() OVER (PARTITION BY OT.TRADER_ID ORDER BY 
                SUM(OT.TRADE_AMOUNT) DESC) AS CCP_RANK,
         SUM(OT.TRADE_AMOUNT) AS TRADED_AMT_WITH_CCP,
         SUM(SUM(OT.TRADE_AMOUNT)) OVER (PARTITION BY OT.TRADER_ID) AS 
         VALUE_OF_TOTAL_TRADES,
         COUNT(*) OVER (PARTITION BY OT.TRADER_ID) AS NUM_OF_CCP_USED,
         SUM(COUNT(OT.TRADE_ID)) OVER (PARTITION BY OT.TRADER_ID) AS 
         TOTAL_TRADES
    
    FROM dbo.ORDERS_TRADES OT
    
    GROUP BY OT.TRADER_ID, OT.TRADER_NAME, OT.EXEC_BROKER

Answer 1

对命名法做一些假设，这是一个不使用任何花哨的解决方案，因此很容易维护，尽管它不是最有效的：

create table trades
(
    TRADER_ID varchar(10), 
    TRADER_NAME varchar(20), 
    CCP char(4), 
    TRADED_AMT decimal(10,2), 
    TRADE_ID varchar(10) primary key
);

insert trades
values
    ('ABC123', 'Jules Winnfield', 'GOLD', 10000 , 'ASDADAD'),
    ('XDA241', 'Jimmie Dimmick ', 'GOLD', 12000 , 'ASSVASD'),
    ('ADC123', 'Vincent Vega   ', 'BARC', 10000 , 'ZXCZCX'),
    ('ABC123', 'Jules Winnfield', 'BARC', 15000 , 'ASSXCQA'),
    ('ADC123', 'Vincent Vega   ', 'CRED', 250000, 'RFAQQA'),
    ('ABC123', 'Jules Winnfield', 'CRED', 5000  , 'ASDQ23A'),
    ('ABC123', 'Jules Winnfield', 'GOLD', 5000  , 'AVBDQ3A');

with trader_totals as 
(
    select   trader_id,
             distinct_ccps = count(distinct CCP),
             total_amt = sum(traded_amt),
             total_count = count(*)
    from     trades
    group by trader_id
)
select      trader_id               = tr.trader_id,
            trader_name             = trader_name,
            distinct_CCP_count      = tt.distinct_ccps,
            CCP                     = tr.CCP,
            this_CCP_traded_amt     = sum(traded_amt),
            total_traded_amt        = tt.total_amt,
            this_CCP_traded_count   = count(*),
            total_traded_count      = tt.total_count

from        trades          tr
join        trader_totals   tt on tt.trader_id = tr.trader_id
group by    tr.trader_id,
            tr.trader_name,
            tr.CCP,
            tt.distinct_ccps,
            tt.total_amt,
            tt.total_count

Answer 2

你似乎想要：

SELECT OT.TRADER_ID, OT.TRADER_NAME, OT.CCP,
       COUNT(*) OVER (PARTITION BY OT.TRADER_ID) as NUM_CCP,
       SUM(OT.TRADED_AMT) AS TRADED_AMT_WITH_CCP,
       SUM(SUM(OT.TRADED_AMT)) OVER (PARTITION BY OT.TRADER_ID) AS VALUE_OF_TOTAL_TRADES,
       COUNT(OT.TRADE_ID) AS CCP_TRADES,
       SUM(COUNT(OT.TRADE_ID)) OVER (PARTITION BY OT.TRADER_ID) AS TOTAL_TRADES
FROM ORDERS_TRADES OT
GROUP BY OT.TRADER_ID, OT.TRADER_NAME, OT.CCP;

我不确定您的查询与您想要的结果有什么关系。这些列与您的要求无关。

Here 是一个 dbfiddle。