你好
我知道票是前一阵子开的，但我一直在寻找这个完整的代码，我只在网上找到了它的一部分，但没有一个完全有效的，所以在这里是。 我希望它可以帮助一些人。
我看到了您的帖子，并且使用 here 找到的大部分信息，我遇到了完全相同的问题 - w3schools 以下代码的主要作者。
这是如何做到的，有两种方法：
1-您的上传表单或函数在接收文件的服务器上
// the index.php file on the server
<br><br>
<?php /* includes */ require_once 'upload.php'; ?>
<!DOCTYPE html>
<html><body> Formulaire de téléchargement d'une image <br><br>
<form action="upload.php" method="POST" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload Image" name="submit">
</form>
</body> </html>
upload.php 文件，在本例中位于同一目录中
<?php
// writing in a sublfolder called image
$target_dir = "image/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
$check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
if($check !== false) {
echo "File is an image - " . $check["mime"] . ".";
$uploadOk = 1;
} else {
echo "File is not an image.";
$uploadOk = 0;
}
}
if ($uploadOk == 0) {
echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
// give a name and direction to the image - i changed the name to test.jpg...
$uploadfile = $_SERVER['DOCUMENT_ROOT'].$target_dir.'test.jpg';
echo "<br><br>";
echo $uploadfile;
echo "<br><br>";
if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $uploadfile)) {
echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
} else {
echo "Sorry, there was an error uploading your file.";
}
}
?>
2- 第二个选项，如果您的网络服务器与接收文件的服务器不同，这里您需要在每台服务器上有两个文件：
发送文件的服务器（你的网络服务器）：send.php
<?php
// I uploaded a file called sample2.jpeg from on server to another
// again you can make functions out of this
$target_url = 'http://192.168.56.103/receive.php';
//This needs to be the full path to the file you want to send.
$file_name_with_full_path = realpath('./sample2.jpeg');
/* curl will accept an array here too.
* Many examples I found showed a url-encoded string instead.
* Take note that the 'key' in the array will be the key that shows up in the
* $_FILES array of the accept script
*/
//$post = array('extra_info' => '123456','file_contents'=>'@'.$file_name_with_full_path);
$post = array('file_contents' => new CurlFile($file_name_with_full_path, 'text/plain' /* MIME-Type */,'' /*directory*/));
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$target_url);
curl_setopt($ch, CURLOPT_POST,1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
$result=curl_exec ($ch);
curl_close ($ch);
echo $result;
?>
和接收服务器端的文件：receive.php
<?php
// you can chage the destination path
$uploaddir = realpath('./') . '/';
$uploadfile = $uploaddir . basename($_FILES['file_contents']['name']);
echo "<br><br>";
print_r ($uploadfile);
echo "<br><br>";
echo '<pre>';
if (move_uploaded_file($_FILES['file_contents']['tmp_name'], $uploadfile)) {
echo "File is valid, and was successfully uploaded.\n";
} else {
echo "Possible file upload attack!\n";
}
echo 'Here is some more debugging info:';
print_r($_FILES);
echo "\n<hr />\n";
print_r($_POST);
print "</pr" . "e>\n";
?>
<br><br>Sources and references to other codes :
<br>http://stackoverflow.com/questions/12667797/using-curl-to-upload-post-data-with-files
<br>http://stackoverflow.com/questions/15200632/how-to-upload-file-using-curl-with-php
<br>http://code.stephenmorley.org/php/sending-files-using-curl/
<br>http://www.w3schools.com/php/php_file_upload.asp
再次感谢 99% 代码的真正作者，修复了人们在 stackoverflow 论坛上的评论：derakkilgo 和 W3SCHOOLS。