【发布时间】:2014-07-14 08:49:39
【问题描述】:
这是我第一次接触 Python 下的 ZMQ,我希望服务器在收到客户端的请求时发送多行。 我在服务器端 ZMQ 提供的示例中添加的代码是:
with open("test.txt", 'r') as f:
for line in f:
socket.send_string(line.rstrip("\n"))
问题是如何让服务器发送所有行或如何让客户端在服务器之前不发送请求
完成从test.txt发送所有行
客户
import zmq
context = zmq.Context()
print("Connecting to hello world server")
socket = context.socket(zmq.REQ)
socket.connect("tcp://localhost:5555")
for request in range(10):
print("Sending request %s" % request)
socket.send(b"Hello")
message = socket.recv()
print("Received reply %s [ %s ]" % (request, message))
服务器
import time
import zmq
context = zmq.Context()
socket = context.socket(zmq.REP)
socket.bind("tcp://*:5555")
while True:
# Wait for next request from client
message = socket.recv()
print("Received request: %s" % message)
# Do some 'work'
time.sleep(1)
# Send reply back to client
with open("test.txt", 'r') as f:
for line in f:
socket.send_string(line.rstrip("\n"))
客户端日志
Connecting to hello wolrd server
Sending request 0
Received reply 0 [ This is test line 1 ]
Sending request 1
这是它停止的地方,因为服务器生成了如下所示的错误:
服务器日志
line 324, in send_string
return self.send(u.encode(encoding), flags=flags, copy=copy)
File "socket.pyx", line 571, in zmq.backend.cython.socket.Socket.send (zmq/backend/cython/socket.c:5319)
File "socket.pyx", line 618, in zmq.backend.cython.socket.Socket.send (zmq/backend/cython/socket.c:5086)
File "socket.pyx", line 181, in zmq.backend.cython.socket._send_copy (zmq/backend/cython/socket.c:2081)
File "checkrc.pxd", line 21, in zmq.backend.cython.checkrc._check_rc (zmq/backend/cython/socket.c:6032)
zmq.error.ZMQError: Operation cannot be accomplished in current state
Process finished with exit code 1
test.txt
This is test line 1
This is test line 2
This is test line 3
This is test line 4
This is test line 5
【问题讨论】: