多赛事锦标赛积分榜（任意数量的参赛作品）

Question

假设您有一个多项目比赛，参赛者可以尝试任意次数的任何项目。 （奇怪，我知道。）

如何为每项赛事提取想要的球员的最佳时间， 并为其分配一个位置？ （一二三...）

Data example:               Desired output:

Name | Event | Score        Name | Event | Score | Rank
--------------------        ----------------------------
Bob      1      50          Given input: "Bob"
Bob      1     100          Bob      1     100      1   
Bob      2      75          Bob      2      75      3
Bob      3      80          Bob      3      80      2
Bob      3      65      
                            Given input: "Jill"
Jill     2      75          Jill     2      90      1
Jill     2      90          Jill     3      60      3
Jill     3      60
                            Given input: "Chris"
Chris    1      70          Chris    1      70      2
Chris    2      50          Chris    2      85      2
Chris    2      85          Chris    3     100      1
Chris    3     100

这是我上一个问题的基础： Multi-event tournament standings

我觉得更好地理解了这个问题（谢谢！），但我无法弥合与这个版本问题的差距。

我有 SQL 5.x，所以我不能使用 Rank() 之类的东西。这也将处理成千上万的分数。

Answer 1

可以使用此查询获得所需的输出：

select
IF(event is NULL, CONCAT('Given input: "', name,'"'), name) as name,
IF(event is NULL, '', event) as event,
IF(event is NULL, '', max(score)) as score,
IF(event is NULL, '', (
  select count(s2.name) + 1
  from (
          select name, max(score) as score
          from scores es
          where es.event = s.event
          group by es.name
          order by score desc
        ) s2
  where s2.score > max(s.score)
)) as `rank`

from scores s
group by name, event with rollup
having name is not NULL
order by name, event;

并输出（如果在 mysql cli 中运行查询）：

+----------------------+-------+-------+------+
| name                 | event | score | rank |
+----------------------+-------+-------+------+
| Given input: "Bob"   |       |       |      |
| Bob                  | 1     | 100   | 1    |
| Bob                  | 2     | 75    | 3    |
| Bob                  | 3     | 80    | 2    |
| Given input: "Chris" |       |       |      |
| Chris                | 1     | 70    | 2    |
| Chris                | 2     | 85    | 2    |
| Chris                | 3     | 100   | 1    |
| Given input: "Jill"  |       |       |      |
| Jill                 | 2     | 90    | 1    |
| Jill                 | 3     | 60    | 3    |
+----------------------+-------+-------+------+
11 rows in set, 3 warnings (0.00 sec)

应该适用于任何 Mysql 5。

Answer 2

您可以通过采用max() 的事件聚合来获得每个事件的最高分。要模拟dense_rank()，您可以使用子查询计算高于或等于每个事件当前分数的分数。

对于特定的参赛者（这里是 Bob）：

SELECT d1.name,
       d1.event,
       max(d1.score) score,
       (SELECT count(*)
               FROM (SELECT d2.event,
                            max(d2.score) score
                            FROM data d2
                            GROUP BY d2.event,
                                     d2.name) x1
               WHERE x1.score >= max(d1.score)
                     AND x1.event = d1.event) rank
       FROM data d1
       WHERE d1.name = 'Bob'
       GROUP BY d1.event
       ORDER BY d1.event;

同时为所有人：

SELECT d1.name,
       d1.event,
       max(d1.score) score,
       (SELECT count(*)
               FROM (SELECT d2.event,
                            max(d2.score) score
                            FROM data d2
                            GROUP BY d2.event,
                                     d2.name) x1
               WHERE x1.score >= max(d1.score)
                     AND x1.event = d1.event) rank
       FROM data d1
       GROUP BY d1.name,
                d1.event
       ORDER BY d1.name,
                d1.event;

db<>fiddle

Answer 3

例如：

DROP TABLE IF EXISTS my_table;

CREATE TABLE my_table
(id SERIAL PRIMARY KEY
,name VARCHAR(12) NOT NULL
,event INT NOT NULL
,score INT NOT NULL
);

INSERT INTO my_table (name,event,score) VALUES
('Bob'  ,1, 50),
('Bob'  ,1,100),
('Bob'  ,2, 75),
('Bob'  ,3, 80),
('Bob'  ,3, 65),
('Jill' ,2, 75),
('Jill' ,2, 90),
('Jill' ,3, 60),
('Chris',1, 70),
('Chris',2, 50),
('Chris',2, 85),
('Chris',3,100);

SELECT a.*
     , FIND_IN_SET(a.score,b.scores) my_rank
  FROM my_table a -- it's possible that this really needs to be a repeat of the subquery below, so
                  -- ( SELECT m.* FROM my_table m JOIN (SELECT name,event,MAX(score) score FROM my_table 
                  -- GROUP BY name, event) n ON n.name = m.name AND n.event = m.event AND n.score = m.score) AS a
  JOIN
     (
SELECT x.event
     , GROUP_CONCAT(DISTINCT x.score ORDER BY x.score DESC) scores
  FROM my_table x 
  JOIN 
     ( SELECT name
            , event
            , MAX(score) score 
         FROM my_table 
        GROUP  
           BY name
            , event
      ) y 
     ON y.name = x.name 
    AND y.event = x.event 
    AND y.score = x.score
  GROUP 
     BY x.event
     ) b
    ON b.event = a.event
 WHERE FIND_IN_SET(a.score,b.scores) >0;
+----+-------+-------+-------+------+
| id | name  | event | score | rank |
+----+-------+-------+-------+------+
|  2 | Bob   |     1 |   100 |    1 |
|  3 | Bob   |     2 |    75 |    3 |
|  4 | Bob   |     3 |    80 |    2 |
|  6 | Jill  |     2 |    75 |    3 |
|  7 | Jill  |     2 |    90 |    1 |
|  8 | Jill  |     3 |    60 |    3 |
|  9 | Chris |     1 |    70 |    2 |
| 11 | Chris |     2 |    85 |    2 |
| 12 | Chris |     3 |   100 |    1 |
+----+-------+-------+-------+------+