MQL 到 Pine 脚本的转换产生不同的结果答案

【问题标题】：MQL to Pine Script conversion yields different resultsMQL 到 Pine 脚本的转换产生不同的结果
【发布时间】：2022-01-04 19:42:53
【问题描述】：

我正在尝试将 MQL4 指标转换为 Pine 脚本，但它会产生完全不同的输出；指标值不匹配。与 PineScript 相比，MQL4 指标线更平滑

MQL4 指标代码是

#property indicator_separate_window
#property indicator_buffers 1
#property indicator_color1 Crimson
#property indicator_width1 2

extern int period = 20;

double Signal_Buffer[];

int init() {
  IndicatorDigits( Digits + 4 );
  IndicatorShortName("Indi (" + string(period) + ")");
  SetIndexBuffer(0, Signal_Buffer);
  SetIndexStyle(0, DRAW_LINE);
  SetIndexLabel(0, "Indi (" + string(period) + ")");
  return (0);
}


int start() {
  int bars_loaded = IndicatorCounted();
  if (bars_loaded > 0) bars_loaded--;
  int total_bars = Bars - bars_loaded;

  double current_high    = 0;
  double current_low     = 0;
  double high_low_median = 0;
  double signal          = 0;
  double a = 0;
  double b = 0;
  for (int i = 0; i < total_bars; i++) {
    current_high     = High[iHighest(Symbol(), Period(), MODE_HIGH, period, i)];
    current_low      = Low[iLowest(Symbol(), Period(), MODE_LOW, period, i)];
    high_low_median  = (High[i] + Low[i]) / 2.0;
    a                = 0.66 * ( (high_low_median - current_low) / (current_high - current_low) - 0.5 ) + 0.67 * b;
    a                = MathMin( MathMax( a, -0.999 ), 0.999 );
    Signal_Buffer[i] = MathLog( ( a + 1.0 ) / ( 1 - a ) ) / 2.0 + signal / 2.0;
    b                = a;
    signal           = Signal_Buffer[i];
  }
  return (0);
}

Pine 脚本代码是

//@version=5
indicator(title='Indi', shorttitle='Indi')

per = input.int( defval=20, title='Period', minval=1 )

a = 0.0
b = 0.0
signal = 0.0

h = ta.highest( high, per )
l = ta.lowest( low, per )
m = hl2

a := 0.66 * ( (m - l) / (h - l) - 0.5 ) + 0.67 * b
a := math.min( math.max( a, -0.999 ), 0.999 )
signal := math.log( ( a + 1.0 ) / ( 1 - a ) ) / 2.0 + signal / 2.0
b := a

plot( signal )

【问题讨论】：

标签： pine-script mql4 mql pine-script-v4 pinescript-v5

【解决方案1】：

我认为您可能需要在这一行中将 b 替换为 nz(a[1] ：

a                = 0.66 * ( (high_low_median - current_low) / (current_high - current_low) - 0.5 ) + 0.67 * b;

到

a                = 0.66 * ( (high_low_median - current_low) / (current_high - current_low) - 0.5 ) + 0.67 * nz(a[1]);

【讨论】：