MYSQL 使用 GROUP BY 到 SUM timediff 得到总打开时间

Question

我有多个表，我必须将它们连接在一起才能计算出票已打开多长时间，我正在使用以下查询（我知道很复杂！）：

SELECT DISTINCT u_db.environments.name AS Env_name, TIMEDIFF(u_db.tickets.close_date, u_db.tickets.created_date) AS Total_open_time 
FROM u_db.tickets
INNER JOIN u_db.ticket_units
ON u_db.tickets.id = u_db.ticket_units.ticket_id
INNER JOIN u_db.units
ON u_db.ticket_units.unit_id = u_db.units.id
INNER JOIN u_db.locations
ON u_db.units.location_id = u_db.locations.id
INNER JOIN u_db.location_groups
ON u_db.locations.locations_group_id = u_db.location_groups.id
INNER JOIN u_db.environments
ON u_db.location_groups.environment = u_db.environments.id
WHERE u_db.tickets.created_date >= '2021-09-01 00:00:00'
AND u_db.tickets.created_date < '2021-10-01 00:00:00'
AND u_db.location_groups.id IN (50,17,46,45,48,49)
AND u_db.tickets.id IN (132357,132361,132372,132473);

注意：close_date 和 created_date 存储为 TIMESTAMP。

这会生成以下输出：

Env_name Total_open_time
GA       27:38:59
GA       01:43:51
GR       04:32:58
GR       49:39:19

但是，我想按 Env_name 分组并对每个组的 Total_open_times 求和，所以我想要的输出是：

Env_name Total_open_time
GA       29:22:50
GR       54:12:17

当我按 Env_name 分组时，我似乎无法得到总和的时间，任何关于如何实现这一点的建议将不胜感激！

Answer 1

猜你可以以秒为单位求和，然后将秒转换为时间

SELECT u_db.environments.name AS Env_name, SEC_TO_TIME(SUM(TIMESTAMPDIFF(SECOND, u_db.tickets.created_date, u_db.tickets.close_date))) AS Total_open_time 
FROM u_db.tickets
INNER JOIN u_db.ticket_units
ON u_db.tickets.id = u_db.ticket_units.ticket_id
INNER JOIN u_db.units
ON u_db.ticket_units.unit_id = u_db.units.id
INNER JOIN u_db.locations
ON u_db.units.location_id = u_db.locations.id
INNER JOIN u_db.location_groups
ON u_db.locations.locations_group_id = u_db.location_groups.id
INNER JOIN u_db.environments
ON u_db.location_groups.environment = u_db.environments.id
WHERE u_db.tickets.created_date >= '2021-09-01 00:00:00'
AND u_db.tickets.created_date < '2021-10-01 00:00:00'
AND u_db.location_groups.id IN (50,17,46,45,48,49)
AND u_db.tickets.id IN (132357,132361,132372,132473)
GROUP BY Env_name