如何从android中的联系人列表中删除重复的联系人答案

【问题标题】：how to remove duplicate contact from contact list in android如何从android中的联系人列表中删除重复的联系人
【发布时间】：2013-11-18 17:40:03
【问题描述】：

请看一下：-

 public static ArrayList<ContactsEntityBean> getContactDetails(
            Context mContext) {
        ArrayList<ContactsEntityBean> contactList = new ArrayList<ContactsEntityBean>();
        ContentResolver cr = mContext.getContentResolver();
        Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
                null, null, null);
        if (cur.getCount() > 0) {
            while (cur.moveToNext()) {
                String id = cur.getString(cur
                        .getColumnIndex(ContactsContract.Contacts._ID));
                Cursor cur1 = cr.query(
                        ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                        null, ContactsContract.CommonDataKinds.Email.CONTACT_ID
                                + " = ?", new String[] {
                            id
                        }, null);
                while (cur1.moveToNext()) {
                    ContactsEntityBean contactsEntityBean = new ContactsEntityBean();
                    // to get the contact names
                    String name = cur1
                            .getString(cur1
                                    .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));

                    // Log.e("Name :", name);
                    String email = cur1
                            .getString(cur1
                                    .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));

                    // Log.e("Email", email);
                    contactsEntityBean.setName(name);
                    contactsEntityBean.setEmail(email);
                    if (email != null) {
                        contactList.add(contactsEntityBean);
                    }
                }
                cur1.close();
            }
        }
        return contactList;
    }

这个方法是从同一个用户返回多个联系人假设如果我为同一个用户存储了 abc@gmail.com,abc@gmail.com 所以它返回 abc@gmail.com& abc@gmail.com 但我只想要一条记录 abc@gmail.com

 public static ArrayList<SearchEntityBean> getContactEmailDetails(
            Context mContext) {
        ArrayList<SearchEntityBean> contactList = new ArrayList<SearchEntityBean>();


        try {
            ContentResolver cr = mContext.getContentResolver();
            Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
                    null, null, null);
            if (cur.getCount() > 0) {
                while (cur.moveToNext()) {
                    String email = "";
                    String id = cur.getString(cur
                            .getColumnIndex(ContactsContract.Contacts._ID));

                    Cursor cur1 = cr.query(
                            ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                            null,
                            ContactsContract.CommonDataKinds.Email.CONTACT_ID
                                    + " = ?", new String[] {
                                id
                            }, null);
                    SearchEntityBean contactsEntityBean = new SearchEntityBean();
                    while (cur1.moveToNext()) {

                        // to get the contact names

                        String name = cur1
                                .getString(cur1
                                        .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                        String image = cur1
                                .getString(cur1
                                        .getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_ID));
                        String mail = cur1
                                .getString(cur1
                                        .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));

                        if (mail != null) {
                            if (!mail.equalsIgnoreCase(LoginPreferenceClass
                                    .getEmailID(mContext)))
                                email = email + mail + ",";
                        }
                        // Log.e("rohit", "Contact  Email :" + email);
                        contactsEntityBean.setName(name);
                        contactsEntityBean.setImage(image);

                    }

                    if (email != null) {

                        if (email.length() > 0) {

                            if (email.split(",").length > 1) {

                                contactsEntityBean.setMutipleEmail(true);

                            }

                            contactsEntityBean.setUserType("2");
                            contactsEntityBean.setContactId(id);
                            contactsEntityBean.setEmail(email);
                            contactList.add(contactsEntityBean);
                        }
                    }
                    cur1.close();
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
        HashSet<SearchEntityBean> hs = new HashSet<SearchEntityBean>();
        hs.addAll(contactList);
        contactList.clear();
        contactList.addAll(hs);
        return contactList;
    }

【问题讨论】：

您想从联系人数据库或您的 arralist 中删除它。??
来自我的数组列表而不是来自联系人列表
contactsEntityBean 代码添加到这里
好的。添加了处理电子邮件的代码...您可以对电话、地址使用相同的逻辑（因为一个用户可以拥有更多电话和地址）..查看我的答案..
@YogeshTatwal 更新答案检查它..

标签： android contacts

【解决方案1】：

你应该像下面这样修改你的ContactsEntityBean

public class ContactsEntityBean {
    private HashSet<String> emails = new HashSet<String>(); 

    public void setEmail(String email) {
        if (email == null)
            return; 
        this.emails.add(email.trim()); 
    }

    public HashSet<String> getEmails() {
        return this.emails; 
    }
}

将关心重复的电子邮件...您可以对地址、电话等使用相同的逻辑。

用下面的代码替换你的ContactsEntityBean

public class ContactsEntityBean {
    private HashSet<String> emails;
    private HashSet<String> phones;
    private HashSet<String> addresses;
    private String contactId;
    private boolean checked = false;

    public ContactsEntityBean() {
        this.emails = new HashSet<String>();
        this.phones = new HashSet<String>();
        this.addresses = new HashSet<String>();
    }

    public HashSet<String> getPhones() {
        return phones;
    }

    public void setPhones(String phone) {
        if (phone == null)
            return;
        this.phones.add(phone.trim());
    }

    public HashSet<String> getAddresses() {
        return addresses;
    }

    public void setAddresses(String address) {
        if (address == null)
            return;
        this.addresses.add(address.trim());
    }

    public void setEmails(String email) {
        if (email == null)
            return;
        this.emails.add(email.trim());
    }

    public HashSet<String> getEmails() {
        return emails;
    }

    public String getContactId() {
        return contactId;
    }

    public void setContactId(String contactId) {
        this.contactId = contactId;
    }

    public boolean isChecked() {
        return checked;
    }

    public void setChecked(boolean checked) {
        this.checked = checked;
    }
}

而且不需要关心重复。这将关心所有的事情..

【讨论】：

请详细说明如何删除重复的联系人
@YogeshTatwal 添加了 ContactsEntityBean 类的代码。使用这个。这将关心所有重复项
你是如何在你的代码中调用setter的（正如你所说的它不起作用..）你能显示代码吗/
我已经更新了我的问题，请看一下谢谢你的重播。
你能回答这个类似的问题吗？ stackoverflow.com/questions/25801533/…

【解决方案2】：

这是我的工作

private void getContactDetails(ContentResolver contentResolver) {

        Cursor phones = contentResolver.query(
                ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null,
                null, null);
        HashSet<String> mobileNoSet = new HashSet<String>();

        while (phones.moveToNext()) {
            String name = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
            String phoneNumber = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
            String email = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Email.ADDRESS));
            String imagUri = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Photo.PHOTO_URI));
            long id = phones.getColumnIndex(ContactsContract.Contacts._ID);

            if (!mobileNoSet.contains(phoneNumber)) {
                arrayContacts.add(new Contact(name, phoneNumber, email,
                        imagUri, id));
                mobileNoSet.add(phoneNumber);
            }
        }

        adapterContact = new AdapterContact(getActivity(), arrayContacts);
        listContact.setAdapter(adapterContact);
    }

【讨论】：

它仍然显示重复。显示重复的数字，其中包含空格。

【解决方案3】：

将您的联系人保存在 ArrayList 中，然后从列表中删除重复项。删除重复元素的最简单方法是将内容添加到 Set（不允许重复），然后将 Set 添加回 ArrayList。

像这样使用HashSet。

ArrayList al = new ArrayList();
// add elements to al, including duplicates
HashSet hs = new HashSet();
hs.addAll(al);
al.clear();
al.addAll(hs);

【讨论】：

集合的输出是什么？
你能回答这个类似的问题吗？ stackoverflow.com/questions/25801533/…

【解决方案4】：

通过像这样改变你的方法，你可以获得唯一一个不重复的联系人..

public static ArrayList<ContactsEntityBean> getContactDetails(Context mContext) {
    ArrayList<ContactsEntityBean> contactList = new ArrayList<ContactsEntityBean>();
    ContentResolver cr = mContext.getContentResolver();
    Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
            null, null, null);
    HashMap<String, String> data = new HashMap<String, String>();
    if (cur.getCount() > 0) {
        while (cur.moveToNext()) {
            String id = cur.getString(cur
                    .getColumnIndex(ContactsContract.Contacts._ID));
            Cursor cur1 = cr.query(
                    ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                    null, ContactsContract.CommonDataKinds.Email.CONTACT_ID
                            + " = ?", new String[] { id }, null);
            while (cur1.moveToNext()) {
                ContactsEntityBean contactsEntityBean = new ContactsEntityBean();
                // to get the contact names
                String name = cur1
                        .getString(cur1
                                .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));

                // Log.e("Name :", name);
                String email = cur1
                        .getString(cur1
                                .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
                if (!data.containsValue(email)) {
                    // Log.e("Email", email);
                    contactsEntityBean.setName(name);
                    contactsEntityBean.setEmail(email);
                   data.put(name, email);
                    if (email != null) {
                        contactList.add(contactsEntityBean);
                    }
                }


            }
            cur1.close();
        }
    }
    return contactList;
}

【讨论】：

请检查一次。
你能回答这个类似的问题吗？ stackoverflow.com/questions/25801533/…

【解决方案5】：

使用 HashMap，因为 HashMap 不允许重复键

声明一个全局变量

// Hash Maps
Map<String, String> nameEmailMap = new HashMap<String, String>();

在循环中将数据添加到 HashMap

// Enter Into Hash Map
nameEmailMap.put(email, name);

在循环之外获取日志

// Get The Contents of Hash Map in Log
        for (Map.Entry<String, String> entry : namePhoneMap.entrySet()) {
            String key = entry.getKey();
            Log.d(TAG, "Phone :" + key);
            String value = entry.getValue();
            Log.d(TAG, "Name :" + value);
        }

有关如何检索不重复联系人的完整答案，请参阅https://stackoverflow.com/a/54227282/3904109（适用于电子邮件）和https://stackoverflow.com/a/54228199/3904109（适用于电话）

【讨论】：

【解决方案6】：

此解决方案将：

删除重复项
删除所有不必要的开头，即目前只允许以 03、92 和 +92 开头的数字

显示所有同名的电话号码，例如 John 有 2 个号码。

 fun fetchContacts(): List<UserObject> {\
          val contacts: ArrayList<UserObject> = ArrayList()
          val mobileNoSet = HashSet<String>()
          val cursor= requiredContext()?.contentResolver?.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,arrayOf(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,ContactsContract.CommonDataKinds.Phone.NUMBER,ContactsContract.CommonDataKinds.Phone.PHOTO_URI),null,null,"DISPLAY_NAME ASC")

    while (cursor!!.moveToNext()) {
         val index = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME)
         val numberIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)
         val photoIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_URI)
         val strName = cursor.getString(index)
         var number = cursor.getString(numberIndex)
         number = number.replace(" ", "")
         val photo = cursor.getString(photoIndex)
         if ((number.startsWith("03") || number.startsWith("92")||number.startsWith("+92")) && !mobileNoSet.contains(number)) {
                contacts.add(UserObject(photo,strName,number))mobileNoSet.add(number)
            }
     }
    return contacts
  }

【讨论】：

【解决方案7】：

在您的 ArrayList 中添加联系电子邮件后，将 continue 放在后面，然后使用 HashSet 而不是 ArrayList

if (email != null) {
    contactList.add(contactsEntityBean);
    continue;
}

【讨论】：

你能回答这个类似的问题吗？ stackoverflow.com/questions/25801533/…