php 将某些东西爆炸成数组，但使用介于两者之间的值

Question

我有一个字符串我想清理并放入一个数组中，这样我就可以在 mysql 中搜索它。

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// Here's one example of what the string might have:
$string1 = "(1) *value1* *value2*; (2) *value3* *value4* *value5*; (3) *value6*";
// And here's another possibility:
$string2 = "*value1* *value2* *value3* *value4*";

// I want to remove all the "(#)" stuff, and explode all the values into an array
// This is what I have so far:
// $string can be like the examples $string1 or $string2

$string_clean = str_replace("* *","",trim(preg_replace("/\((\d)\)/i", "", $string)));
$my_array = explode('*', trim($string_clean, '*'));

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但是，这就是我得到的：

Array ( [0] => value1 [1] => [2] => value2 [3] => [4] => value3 [5] => [6] => value4 [7] => [8] => value5 ) 

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我想我可以找到一个函数来从数组中删除所有空项，但我想知道是否有更有效的方法来做到这一点？

Answer 1

你需要preg_match_all():

preg_match_all('#\*([^*]+)\*#', $string, $matches);
$result = $matches[1];
// $result is array('value1', 'value2', ...)

这将找到所有*something* 并返回* 之间的字符串。