【发布时间】:2021-03-10 16:34:31
【问题描述】:
我在 Oracle SQL 19 中有下表:
+---------+-----------+---------------------+
| job_num | job_stage | timestamp |
+---------+-----------+---------------------+
| job_1 | waiting | 2020-01-28 11:51:00 |
| job_1 | waiting | 2020-01-28 11:52:00 |
| job_1 | waiting | 2020-01-28 11:53:00 |
| job_1 | running | 2020-01-28 11:54:00 |
| job_1 | running | 2020-01-28 11:55:00 |
| job_1 | running | 2020-01-28 11:56:00 |
| job_1 | running | 2020-01-28 11:57:00 |
| job_1 | finishing | 2020-01-28 11:58:00 |
| job_1 | finishing | 2020-01-28 11:59:00 |
| job_2 | waiting | 2020-01-28 11:52:00 |
| job_2 | waiting | 2020-01-28 11:53:00 |
| job_2 | waiting | 2020-01-28 11:54:00 |
| job_2 | waiting | 2020-01-28 11:55:00 |
| job_2 | waiting | 2020-01-28 11:56:00 |
| job_2 | running | 2020-01-28 11:57:00 |
| job_2 | running | 2020-01-28 11:58:00 |
| job_2 | running | 2020-01-28 11:59:00 |
| job_2 | running | 2020-01-28 12:00:00 |
| job_2 | finishing | 2020-01-28 12:01:00 |
| job_2 | finishing | 2020-01-28 12:02:00 |
| job_2 | finishing | 2020-01-28 12:03:00 |
| job_2 | finishing | 2020-01-28 12:04:00 |
+---------+-----------+---------------------+
我想通过以下方式旋转它:
+---------+---------------------+---------------------+---------------------+---------------------+---------------------+---------------------+
| job_num | min_waiting | max_waiting | min_running | max_running | min_finishing | max_finishing |
+---------+---------------------+---------------------+---------------------+---------------------+---------------------+---------------------+
| job_1 | 2020-01-28 11:51:00 | 2020-01-28 11:53:00 | 2020-01-28 11:54:00 | 2020-01-28 11:57:00 | 2020-01-28 11:58:00 | 2020-01-28 11:59:00 |
| job_2 | 2020-01-28 11:52:00 | 2020-01-28 11:56:00 | 2020-01-28 11:57:00 | 2020-01-28 12:00:00 | 2020-01-28 12:01:00 | 2020-01-28 12:04:00 |
+---------+---------------------+---------------------+---------------------+---------------------+---------------------+---------------------+
更具体地说,对于每个job_num,对于每个job_stage,我想获取最小时间戳和最大时间戳。然后,我想显示每个job_num 的最小和最大时间戳。
谁能告诉我如何在 Oracle SQL 19 中有效地做到这一点?任何帮助将不胜感激!
我在 SQL 中有以下表格供您参考:
未透视表如下:
with t1 as (
select 'job_1' as job_num
, 'waiting' as job_stage
, to_date('1/28/2020 11:51', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_1' as job_num
, 'waiting' as job_stage
, to_date('1/28/2020 11:52', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_1' as job_num
, 'waiting' as job_stage
, to_date('1/28/2020 11:53', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_1' as job_num
, 'running' as job_stage
, to_date('1/28/2020 11:54', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_1' as job_num
, 'running' as job_stage
, to_date('1/28/2020 11:55', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_1' as job_num
, 'running' as job_stage
, to_date('1/28/2020 11:56', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_1' as job_num
, 'running' as job_stage
, to_date('1/28/2020 11:57', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_1' as job_num
, 'finishing' as job_stage
, to_date('1/28/2020 11:58', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_1' as job_num
, 'finishing' as job_stage
, to_date('1/28/2020 11:59', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'waiting' as job_stage
, to_date('1/28/2020 11:52', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'waiting' as job_stage
, to_date('1/28/2020 11:53', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'waiting' as job_stage
, to_date('1/28/2020 11:54', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'waiting' as job_stage
, to_date('1/28/2020 11:55', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'waiting' as job_stage
, to_date('1/28/2020 11:56', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'running' as job_stage
, to_date('1/28/2020 11:57', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'running' as job_stage
, to_date('1/28/2020 11:58', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'running' as job_stage
, to_date('1/28/2020 11:59', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'running' as job_stage
, to_date('1/28/2020 12:00', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'finishing' as job_stage
, to_date('1/28/2020 12:01', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'finishing' as job_stage
, to_date('1/28/2020 12:02', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'finishing' as job_stage
, to_date('1/28/2020 12:03', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
union
select 'job_2' as job_num
, 'finishing' as job_stage
, to_date('1/28/2020 12:04', 'MM/DD/YYYY HH24:MI') as timestamp
from dual
)
select *
from t1
order by job_num
, timestamp
透视表如下:
with t1 as (
select 'job_1' as job_num
, to_date('1/28/2020 11:51', 'MM/DD/YYYY HH24:MI') as min_waiting
, to_date('1/28/2020 11:53', 'MM/DD/YYYY HH24:MI') as max_waiting
, to_date('1/28/2020 11:54', 'MM/DD/YYYY HH24:MI') as min_running
, to_date('1/28/2020 11:57', 'MM/DD/YYYY HH24:MI') as max_running
, to_date('1/28/2020 11:58', 'MM/DD/YYYY HH24:MI') as min_finishing
, to_date('1/28/2020 11:59', 'MM/DD/YYYY HH24:MI') as max_finishing
from dual
union
select 'job_2' as job_num
, to_date('1/28/2020 11:52', 'MM/DD/YYYY HH24:MI') as min_waiting
, to_date('1/28/2020 11:56', 'MM/DD/YYYY HH24:MI') as max_waiting
, to_date('1/28/2020 11:57', 'MM/DD/YYYY HH24:MI') as min_running
, to_date('1/28/2020 12:00', 'MM/DD/YYYY HH24:MI') as max_running
, to_date('1/28/2020 12:01', 'MM/DD/YYYY HH24:MI') as min_finishing
, to_date('1/28/2020 12:04', 'MM/DD/YYYY HH24:MI') as max_finishing
from dual
)
select *
from t1
order by job_num
【问题讨论】:
-
几个问题/建议:首先,“timestamp”是Oracle关键字;即使在某些情况下将其用作列名不会引发错误,但至少会令人困惑。使用其他东西,要么 ts 要么可能 timestamp_ (带下划线)。其次,为什么要对名为 TIMESTAMP 的列使用 TO_DATE?实际表中的实际数据类型是什么 - DATE 或 TIMESTAMP?不要使用与列的数据类型直接矛盾的列名。