生成两个日期之间的日期列表并将列表保存在数据库中

Question

对于我目前遇到的问题，我需要一些帮助。我需要使用列表中的第一个和最后一个日期生成日期列表，然后将生成的日期列表保存在数据库表中。最好的方法是什么？

到目前为止我的代码：

<?php

    $apartment = (isset($_POST['apartment']) ? $_POST['apartment'] : null);
    $name = (isset($_POST['name']) ? $_POST['name'] : null);
    $surname = (isset($_POST['surname']) ? $_POST['surname'] : null);
    $email = (isset($_POST['email']) ? $_POST['email'] : null);
    $address = (isset($_POST['address']) ? $_POST['address'] : null);
    $mobile = (isset($_POST['mobile']) ? $_POST['mobile'] : null);
    $pax = (isset($_POST['pax']) ? $_POST['pax'] : null);
    $address = (isset($_POST['address']) ? $_POST['address'] : null);
    $remarks = (isset($_POST['remarks']) ? $_POST['remarks'] : null);
    $day_from = (isset($_POST['day_from']) ? $_POST['day_from'] : null);
    $month_from = (isset($_POST['month_from']) ? $_POST['month_from'] : null);
    $year_from = (isset($_POST['year_from']) ? $_POST['year_from'] : null);
    $booking_from = $year_from."-".$month_from."-".$day_from;
    $day_to = (isset($_POST['day_to']) ? $_POST['day_to'] : null);
    $month_to = (isset($_POST['month_to']) ? $_POST['month_to'] : null);
    $year_to = (isset($_POST['year_to']) ? $_POST['year_to'] : null);
    $booking_to = $year_to."-".$month_to."-".$day_to;
    $no_of_nights = abs(strtotime($booking_to) - strtotime($booking_from));     
    $days = floor($no_of_nights / (60*60*24));

   include 'connect.php';

 if (!$conn->autocommit(FALSE)) {
    printf("Errormessage: %s\n", $conn->error);
 }

 if (!$conn->query("INSERT INTO client_details (clientID, name, email, address, mobile) VALUES ('', '$name $surname', '$email', '$address', '$mobile')")) {
     printf("Errormessage: %s\n", $conn->error);
 }

 if (!$conn->query("INSERT INTO bookings (bookingID, apartmentID, clientID, date_from, date_to, nights, pax, remarks) VALUES ('', '$apartment', LAST_INSERT_ID(), '$booking_from', '$booking_to', '$days', '$pax', '$remarks')")) {
     printf("Errormessage: %s\n", $conn->error);
 }

function dateArray($booking_from, $booking_to) {
    echo "yo";

    $aryRange = array();

     $iDateFrom=mktime(1,0,0,substr($booking_from,5,2),     substr($booking_from,8,2),substr($booking_from,0,4));
    $iDateTo=mktime(1,0,0,substr($booking_to,5,2),     substr($booking_to,8,2),substr($booking_to,0,4));

if ($iDateTo>=$iDateFrom) {
    array_push($aryRange, date('Y-m-d', $iDateFrom));
    {
        while ($iDateFrom<$iDateTo)
        {
            $iDateFrom+=86400; // add 24 hours
        array_push($aryRange,date('Y-m-d',$iDateFrom));
        }
    }
    return $aryRange;
    }



dateArray($booking_from, $booking_to);

  if (!$conn->query("INSERT INTO room_nights (bookingID, apartmentID, dates) VALUES (LAST_INSERT_ID(), '$apartment', '$dates['dates']')")) {
     printf("Errormessage: %s\n", $conn->error);
 }


 if (!$conn->commit()) {
     printf("Errormessage: %s\n", $conn->error);
 }
 $conn->close();
}

?>

Answer 1

出现此错误的原因是您调用函数daterange 而不保存它返回的结果。所以不要这样称呼它：

daterange($booking_from, $booking_to, $step = '+1 day', $output_format = 'y-m-d');

您应该添加$dates 变量来存储函数的返回结果并在以后使用它。

$dates = daterange($booking_from, $booking_to, $step = '+1 day', $output_format = 'y-m-d');

编辑：

以下代码：

<?php    
function daterange($booking_from, $booking_to, $step = '+1 day', $output_format = 'Y-m-d') {
      $dates = array();
      $first = strtotime($booking_from);
      $last = strtotime($booking_to);

      while ($first <= $last) {
        $dates[] = date($output_format, $first);
        $first = strtotime($step, $first);
      }

      return $dates;
    }

    $dates = daterange('2015-08-01', '2015-08-10');

    print_r($dates);
?>

返回存储在$dates 参数中的日期数组：

Array
(
    [0] => 2015-08-01
    [1] => 2015-08-02
    [2] => 2015-08-03
    [3] => 2015-08-04
    [4] => 2015-08-05
    [5] => 2015-08-06
    [6] => 2015-08-07
    [7] => 2015-08-08
    [8] => 2015-08-09
    [9] => 2015-08-10
)

Here 是一个沙盒，您可以在其中查看结果。

请注意，$output_format 应为'Y-m-d'，以便获取yyyy-mm-dd 格式的日期。

您不能将数组存储到 DATE 字段中。即使你想存储一个数组，你也应该使用 PHP 的serialize 函数并将它存储在数据库的一个 BLOB 字段中。 (See the documentation)

因此，如果您想存储日期范围，您将需要在数据库中至少有两个字段，例如date_from 和 date_to。在这种情况下，INSERT 语句应如下所示：

$conn->query("INSERT INTO room_nights (bookingID, apartmentID, date_from, date_to) VALUES (LAST_INSERT_ID(), '$apartment', '$dates[0]', '". $dates[count($dates) - 1] ."')");

附：我还看到您将 $booking_from 和 $booking_to 参数从字符串多次转换为日期 - 一次在 daterange 函数定义之前，一次在同一个函数中。

Answer 2

这是我对这个问题的解决方案。

第 1 步：创建一个包含日期的数组
Step2：遍历数组，在数据库表中插入日期；

<?php
$day_from = (isset($_POST['day_from']) ? $_POST['day_from'] : null);
$month_from = (isset($_POST['month_from']) ? $_POST['month_from'] : null);
$year_from = (isset($_POST['year_from']) ? $_POST['year_from'] : null);
$booking_from = $year_from."-".$month_from."-".$day_from;
$day_to = (isset($_POST['day_to']) ? $_POST['day_to'] : null);
$month_to = (isset($_POST['month_to']) ? $_POST['month_to'] : null);
$year_to = (isset($_POST['year_to']) ? $_POST['year_to'] : null);
$booking_to = $year_to."-".$month_to."-".$day_to;
$no_of_nights = abs(strtotime($booking_to) - strtotime($booking_from));     
$days = floor($no_of_nights / (60*60*24));

// create array with dates 
function daterange($booking_from, $booking_to, $step = '+1 day', $output_format = 'Y-m-d') {
 $dates = array();
 $first = new DateTime($booking_from);
 $last = new DateTime($booking_to);
 $interval = DateInterval::createFromDateString($step);
 $period = new DatePeriod($first, $interval, $last);

 foreach ($period as $date) {
  $dates[] = $date->format($output_format);
  }

   return $dates;
 }

 $dates = daterange($booking_from, $booking_to);

  print_r($dates);

  include 'connect.php';

  if (!$conn->autocommit(FALSE)) {
  printf("Errormessage: %s\n", $conn->error);
  }

  // loop thru dates and save in database table
  foreach ($dates as $date) {
  if (!$conn->query("INSERT INTO room_nights (bookingID, apartmentID, dates) VALUES (LAST_INSERT_ID(), '$apartment', '$date')")) {
  printf("Errormessage: %s\n", $conn->error);
 }
   }

 if (!$conn->commit()) {
 printf("Errormessage: %s\n", $conn->error);
}
$conn->close();

 ?>