GET json 嵌套对象属性。 [来自查询]

Question

我正在尝试查询“UserType”对象，并获取属性“name” 所以整个 JSON 对象是 User: 并且 api 调用应该是这样的： api/user?userTypeName=randomUserTypeName

我可以在其中搜索特定的 userTypeName，并返回名称。

API 调用：

这里我想使用 FromQuery，以便能够搜索 userTypeName 并检查 userTypeName 是否等于输入的名称。

// GET: /api/User/userTypeName
[HttpGet("{userTypeName}")]
public async Task<ActionResult<IEnumerable<User>>> GetAsync(([FromQuery(Name = "userTypeName")]string userTypeName) {
    var result = await ctx.User
        .Include(x => x.UserType)
        .Where(x => x.UserType.Name.ToLower() == UserTypeName.ToLower())
        .ToListAsync();

    if (result == null) return BadRequest();

    return result;
}

对象如下所示：

{
    "id": 9,
    "userTypeId": 1,
    "userType": {
    "id": 1,
    "name": "randomUserTypeName",
    "users": 
    [
        {
            "id": 11,
            "userTypeId": 1,
            "userUrl": "https://userurl",
            "username": "eee",
            "password": "eee",
        }
    ]
}

Answer 1

如果你想通过/api/User/userTypeName这样的请求从Route访问userTypeName，你的操作应该是这样的

[HttpGet("{userTypeName}")]
public async Task<ActionResult<IEnumerable<User>>> GetAsync(string userTypeName) {
    var result = await ctx.User
        .Include(x => x.UserType)
        .Where(x => x.UserType.Name.ToLower() == UserTypeName.ToLower())
        .ToListAsync();

    if (result == null) return BadRequest();

    return result;
}

如果你想从查询中访问userTypeName api/user?userTypeName=randomUserTypeName，你的操作应该是这样的

[HttpGet]
public async Task<ActionResult<IEnumerable<User>>> GetAsync([FromQuery(Name = "userTypeName")]string userTypeName) {
    var result = await ctx.User
        .Include(x => x.UserType)
        .Where(x => x.UserType.Name.ToLower() == UserTypeName.ToLower())
        .ToListAsync();

    if (result == null) return BadRequest();

    return result;
}