Google Directions Service API 3 向地图返回错误结果

Question

我正在使用 google Direction Service 查找以下两个地址的地图

var start = "2115 First Avenue SE Unit 1306, Cottage Grove Place, Cedar Rapids, IA, 52402";     //Set the source/ origin
var end = "6126 Rockwell Dr. Apt 128, Keystone Place, Cedar Rapids, IA, 52402";

通过谷歌地图直接选择它可以正常工作

链接：https://www.google.co.in/maps/dir/Keystone+Place-Blair's+Ferry,+6126+Rockwell+Drive+Northeast,+Cedar+Rapids,+IA+52402,+United+States/Cottage+Grove+Place,+2115+1st+Avenue+Southeast,+Cedar+Rapids,+IA+52402,+United+States/@42.0179234,-91.6739759,13z/data=!3m1!4b1!4m13!4m12!1m5!1m1!1s0x87e4f0459aacb105:0x63c416fc0edc61d6!2m2!1d-91.6475339!2d42.039779!1m5!1m1!1s0x87e4f0d795c1b96b:0xa1ccbbf6400b01aa!2m2!1d-91.6362972!2d41.9959428?hl=en

使用方向服务时，它的工作方式不同。 找到下面的例子

http://jsfiddle.net/MRHQ4/291/（致谢作者：Shreerang Patwardhan）

当我从源和目标中删除 Address2 时它工作正常

Answer 1

'Cottage Grove Place' 和 'Keystone Place' 不是地址2，这些是地名（或者你可以说地名），只需将它们移动到地址的开头（没有其他变化），如下所示，它是工作正常：

var start = "Cottage Grove Place, 2115 First Avenue SE Unit 1306, Cedar Rapids, IA, 52402";     //Set the source/ origin

var end = "Keystone Place, 6126 Rockwell Dr. Apt 128, Cedar Rapids, IA, 52402";  //Set the destination

我测试过，它工作正常，请检查，谢谢。

Answer 2

单元和公寓信息可能会导致地理编码器出现解析问题。如果可以，请尽量删除它们。将地址更改为

var start = "2115 First Avenue SE, Cedar Rapids, IA, 52402";     //Set the source/ origin
var end = "6126 Rockwell Dr, Cedar Rapids, IA, 52402";

您会发现它工作得更好。

Reduced Address Information

With Neighborhood Information

With Apt/Unit Information