FOSRestBundle：控制器必须返回给定的响应（Array()）

Question

我从 FOSRestBundle 开始。我已经添加了这个路由配置：

//Sermovi/Bundle/APIBundle/Resources/config/routing.yml    
sermovi_api_homepage:
        type: rest
        resource: Sermovi\Bundle\APIBundle\Controller\DefaultController

//app/config/routing.yml     
sermovi_api:
    type: rest
    prefix:   /api
    resource: "@SermoviAPIBundle/Resources/config/routing.yml"

还有这个 config.yml

fos_rest:
    routing_loader:
        default_format: json
    view:
        view_response_listener: true

sensio_framework_extra:
    view:
        annotations: false

还有这个控制器：

namespace Sermovi\Bundle\APIBundle\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use FOS\RestBundle\Controller\FOSRestController;
use Symfony\Component\HttpFoundation\Response;


class DefaultController extends FOSRestController
{
    public function getArticlesAction()
    {
        $em = $this->getDoctrine()->getManager();

        $entity = $em->getRepository('SermoviManagementBundle:Transaction')->find(776);

        return array(
            'entity' => $entity
        );
    }
}

我收到了这个错误：

[{"message":"控制器必须返回一个响应(Array(entity => 对象（Sermovi\Bundle\ManagementBundle\Entity\Transaction）） 给定)。","class":"LogicException","trace":[{"namespace":"","short_class":"","class":"","type":"","function" :"","file":"/home/tirengarfio/workspace/sermovi/app/bootstrap.php.cache","line":2855,"args":[]},{"namespace":"Symfony\Component \HttpKernel","short_class":"HttpKernel","class":"Symfony\Component\HttpKernel\HttpKernel","type":"->","function":"handleRaw","file":"/home /tirengarfio/workspace/sermovi/app/bootstrap.php.cache","line":2817,"args":[["object","Symfony\Component\HttpFoundation\Request"],["string","1 "]]},{"命名空间":"Symfony\Component\HttpKernel","short_class":"HttpKernel","class":"Symfony\Component\HttpKernel\HttpKernel","type":"->","函数":"句柄","文件":"/home/tirengarfio/workspace/sermovi/app/bootstrap.php.cache","line":2946,"args":[["object","Symfony\Component \HttpFoundation\Request"],["string","1"],["boolean",true]]},{"namespace":"Symfony\Component\HttpKernel\DependencyInjection","short_class":"ContainerAwareHttpKernel", "class":"Symfony\Component\HttpKernel\Dependen cyInjection\ContainerAwareHttpKernel","type":"->","function":"handle","file":"/home/tirengarfio/workspace/sermovi/app/bootstrap.php.cache","line":2247 ,"args":[["object","Symfony\Component\HttpFoundation\Request"],["string","1"],["boolean",true]]},{"namespace":"Symfony\ Component\HttpKernel","short_class":"Kernel","class":"Symfony\Component\HttpKernel\Kernel","type":"->","function":"handle","file":"/主页/tirengarfio/workspace/sermovi/web/app_dev.php","line":28,"args":[["object","Symfony\Component\HttpFoundation\Request"]]}]}]

编辑：

“可以”我在下面做这样的事情吗？或者因为 FOSRestBundle 正在使用 JMSSerializerBundle 我不应该这样做？

$serializedEntity = $this->container->get('serializer')->serialize($entity, 'json');
return new Response($serializedEntity);

Answer 1

有几种方法可以使用 FOSRestBundle 设置控制器。你这样做的方式，你必须返回一个视图。这是 github 上的一个 rest 控制器的链接，可能会对您有所帮助。 LiipHelloBundle 有一个例子。

另外，我发现在我的控制器中使用ClassResourceInterface 是最简单的。这样，我返回一个数组，它自己处理所有的序列化。它还使用您的控制器名称来生成必要的路由，因此我不必手动定义任何路由。这是我设置控制器的首选方式。请参阅文档条目here 了解其工作原理。

如果您最终使用了ClassResourceInterface，请务必为每个操作添加以下注释，这样您返回的数组就会被正确序列化：

use FOS\RestBundle\Controller\Annotations as Rest;
//.....

/**
* @Rest\View()
*/
public function cgetAction() {}

您甚至可以通过设置控制器的方式来做到这一点，但我之前没有尝试过。让我们知道您是否这样做并且可行。

更新

对于那些可能对使用 FOSRestBundle 而不使用 ClassResourceInterface 感兴趣的人，问题中控制器操作的问题是它不返回视图。这应该在行动中起作用：

class DefaultController extends FOSRestController
{
    public function getArticlesAction()
    {
        $em = $this->getDoctrine()->getManager();

        $entity = $em->getRepository('SermoviManagementBundle:Transaction')->find(776);
        $statusCode = 200;

        $view = $this->view($entity, $statusCode);
        return $this->handleView($view);
    }
}