【问题标题】:Twilio Video Chat JS Original user doesn't get participant track eventsTwilio Video Chat JS 原始用户没有获得参与者跟踪事件
【发布时间】:2023-03-27 20:26:02
【问题描述】:

我有一个 WebRTC Go 房间,1:1。我的目的是让每个客户监听静音和相机关闭事件。但是,只有第二个加入房间的用户才能获得事件。我从文档中获取了这个,但它并没有给出原始的或房间的第一个成员来获取后来的用户事件。

            Video.connect(token, { name: ROOM_NAME }).then((room) => {
            

           // remove local participant code for relevance.
           
            room.participants.forEach(participantConnected);
            room.on("participantConnected", participantConnected);

            room.participants.forEach(participant => {
                participant.on('trackSubscribed', track => {
                    track.on('disabled', () => {
                        console.log(track.kind);
                        if (track.kind === 'audio') {
                            console.log(`${participant.identity} disabled mic.`);
                        }
                        if (track.kind === 'video') {
                            console.log(`${participant.identity} disabled camera.`);
                        }
                    });

                    track.on('enabled', () => {
                        if (track.kind === 'audio') {
                            console.log(`${participant.identity} enabled mic.`);
                        }
                        if (track.kind === 'video') {
                            console.log(`${participant.identity} enabled camera.`);
                        }
                    });

                });
            });

            // removed disconnect code for relevance
        });




const participantConnected = (participant) => {
    const div = document.createElement('div');
    div.id = participant.sid;
    participant.on('trackSubscribed', track => trackSubscribed(div, track));
    participant.on('trackUnsubscribed', trackUnsubscribed);

    participant.tracks.forEach(publication => {
        if (publication.isSubscribed) {
            trackSubscribed(div, publication.track);
        }
    });

    participantsDiv.appendChild(div);
}


const trackSubscribed = (div, track) => {
    if (track.kind === 'video') {
        track.dimensions.width = '90%';
    }

    div.appendChild(track.attach());
}

const trackUnsubscribed = (track) => {
    track.detach().forEach(element => element.remove());
}

原始人(第一个加入房间的人)接收事件时缺少什么?

【问题讨论】:

    标签: javascript twilio twilio-api


    【解决方案1】:

    解决方案

    将以下代码添加到参与者连接方法中

    participant.on('trackSubscribed', track => {
                    track.on('disabled', () => {
                        console.log(track.kind);
                        if (track.kind === 'audio') {
                            console.log(`${participant.identity} disabled mic.`);
                        }
                        if (track.kind === 'video') {
                            console.log(`${participant.identity} disabled camera.`);
                        }
                    });
    
                    track.on('enabled', () => {
                        if (track.kind === 'audio') {
                            console.log(`${participant.identity} enabled mic.`);
                        }
                        if (track.kind === 'video') {
                            console.log(`${participant.identity} enabled camera.`);
                        }
                    });
    
                });
    

    【讨论】:

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