Tkinter StringVar 发送邮件错误 SMTPlib答案

【问题标题】：Tkinter StringVar Send mail error SMTPlibTkinter StringVar 发送邮件错误 SMTPlib
【发布时间】：2016-01-13 10:47:24
【问题描述】：

我正在制作一个 Tkinter 应用程序来发送一封简短的电子邮件。

完整代码：

from Tkinter import *
from smtplib import *
from time import sleep
root=Tk()
root.wm_title("Gmail short message sender")

w = 500 # width for the Tk root
h = 500 # height for the Tk root

# get screen width and height
ws = root.winfo_screenwidth() # width of the screen
hs = root.winfo_screenheight() # height of the screen

# calculate x and y coordinates for the Tk root window
x = (ws/2) - (w/2)
y = (hs/2) - (h/2)

# set the dimensions of the screen
# and where it is placed
root.geometry('%dx%d+%d+%d' % (w, h, x, y))

def send():
    e1_var.get()
    e2_var.get()
    e3_var.get()
    try:
        smtpObj = SMTP('smtp.gmail.com', "587")
        smtpObj.ehlo()
        smtpObj.starttls()
        smtpObj.ehlo()
        smtpObj.login("123@gmail.com", "password")
        smtpObj.sendmail(sender1, receivers1, msg1)
        l1=Label(text="Sent").grid()
        sleep(1)
        l1.destroy()
    except SMTPException:
        l2=Label(text="Error").grid()
        raise



e1_var=StringVar()
e2_var=StringVar()
e3_var=StringVar()

sender = e1_var
receivers = [e2_var]
msg = e3_var
sender1 = '%s' % (sender)
receivers1 = '[%s]'% (receivers)
msg1 = '%s' % (msg)

e1=Entry(root, textvariable=e1_var).grid()
e2=Entry(root, textvariable=e2_var).grid()
e3=Entry(root, textvariable=e3_var).grid()
b1=Button(text="Send", command=send).grid()

root.mainloop()

问题：

问题出在我的StringVar 实例上。首先，StringVar 实例出现此错误。

Exception in Tkinter callback
Traceback (most recent call last):
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-tk/Tkinter.py", line 1536, in __call__
    return self.func(*args)
  File "Desktop/Python Scripts/Email.py", line 32, in send
    smtpObj.sendmail(sender1, receivers1, msg1)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/smtplib.py", line 724, in sendmail
    esmtp_opts.append("size=%d" % len(msg))
AttributeError: StringVar instance has no attribute '__len__'

但我通过添加此部分来解决此问题，

sender1 = sender
receivers1 = receivers
msg1 = msg

并将smtpObj.sendmail(sender, receivers, msg) 更改为smtpObj.sendmail(sender1, receivers1, msg1)。我现在收到此错误。

Exception in Tkinter callback
Traceback (most recent call last):
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-tk/Tkinter.py", line 1536, in __call__
    return self.func(*args)
  File "Desktop/Python Scripts/Email.py", line 32, in send
    smtpObj.sendmail(sender1, receivers1, msg1)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/smtplib.py", line 742, in sendmail
    raise SMTPRecipientsRefused(senderrs)
SMTPRecipientsRefused: {'[[<Tkinter.StringVar instance at 0x103e8be60>]]': (555, '5.5.2 Syntax error. yi8sm12824416pab.22 - gsmtp')}

这是因为引号引起的语法错误吗？如果是这样，我该如何解决第一个错误？

【问题讨论】：

标签： python python-2.7 tkinter smtplib

【解决方案1】：

这个（和其他类似的代码）不正确：

sender = e1_var
receivers = [e2_var]
msg = e3_var

你需要把它改成这样：

sender = e1_var.get()
receivers = [e2_var.get()]
msg = e3_var.get()

不过，这不是您唯一的问题。此代码在用户有机会输入任何内容之前运行，因此结果都是空字符串。您需要等待调用.get() 方法，直到您准备好使用它们（奇怪的是，您已经在send 内部这样做了）。

【讨论】：