【发布时间】:2020-07-27 22:27:26
【问题描述】:
问题参数: 你构建的函数需要传入
- 自变量(x)的当前值
- 因变量的当前值 (y)
- 自变量的步长 (h)
- 根据 x 和 y 计算导数的函数。
函数将返回 x+h 处的因变量 (y) 的值
我们得到了一个测试代码,当我的代码运行时,我得到了“列表索引超出范围”错误
我的代码是:
def rk4( x, y, h, derivs ):
# ... Note, y is a list, ynew is a list, derivs returns a list of derivatives
n = len( y )
k1 = derivs( x, y )
ym = [ ]
ye = [ ]
slope = [ ]
ynew = [ ]
for i in range( n ):
ym[ i ] = y[ i ] + k1[ i ] * h / 2
return ym
k2 = derivs( (x + h / 2), ym )
for i in range( n ):
ym[ i ] = y[ i ] + k2[ i ] * h / 2
return ym
k3 = derivs( (x + h / 2), ym )
for i in range( n ):
ye.append( y[ i ] + k3[ i ] * h )
return ye
k4 = derivs( (x + h), ye )
for i in range( n ):
slope.append( (k1[ i ] + 2 * (k2[ i ] + k3[ i ]) + k4[ i ]) / 6 )
ynew.append( y[ i ] + slope[ i ] * h )
return ynew
x = x + h
return ynew
测试代码:
if __name__ == '__main__':
# This is a spring/mass/damper system.
# The system oscillates and the oscillations should become smaller over time for positive stiffness and damping values
stiffness = 4; #
damping = 0.5;
def derivs(t, y):
return [y[1], -stiffness * y[0] - damping * y[1]]
y = [1, 4]
n = 50
tlow = 0
thigh = 10
h = (thigh - tlow) / (n - 1)
for ii in range ( n ):
t = tlow + ii * h
y = rk4 ( t, y, h, derivs )
【问题讨论】:
标签: python numerical-methods runge-kutta