【发布时间】：2020-11-19 07:05:35
【问题描述】：
作为新手，我真的很努力解决如何解决在结构数组的数组中计算元素的问题。我尝试了几种不同的方法，但都没有得到我需要的结果。
所以我有一个名为 Card 的结构，定义如下：
struct Card: Hashable {
var dateGroup: DateGroup
var countryGroup: CountryGroup
var icon1: IconGroup
var icon2: IconGroup
init(dateGroup: DateGroup, countryGroup: CountryGroup, icon1: IconGroup, icon2: IconGroup) {
self.dateGroup = dateGroup
self.countryGroup = countryGroup
self.icon1 = icon1
self.icon2 = icon2
}
}
作为参考，Card 的元素使用以下代码定义为枚举：
enum DateGroup: String {
case DG1, DG2, DG3
static let allValues = [DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG1, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG2, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3, DG3]
}
enum CountryGroup: String {
case IT, NE, FS, US
static let allValues = [IT, IT, IT, IT, IT, IT, IT, IT, NE, NE, IT, NE, NE, NE, IT, IT, IT, NE, IT, NE, IT, IT, IT, NE, IT, IT, IT, IT, NE, IT, NE, NE, FS, FS, NE, IT, IT, NE, NE, IT, IT, NE, FS, FS, FS, NE, FS, NE, NE, NE, NE, FS, NE, NE, FS, NE, IT, NE, NE, FS, FS, NE, IT, NE, FS, NE, NE, NE, NE, FS, FS, FS, FS, FS, US, FS, FS, FS, FS, NE, FS, FS, FS, NE, US, IT]
}
enum IconGroup: String {
case Portrait, People, Still, Scape, Setting
static let allValues1 = [Portrait, People, People, Portrait, Portrait, People, People, People, People, Portrait, People, Portrait, People, People, People, Portrait, People, Portrait, People, Portrait, Portrait, People, People, Portrait, People, People, Portrait, People, Portrait, People, Portrait, People, Portrait, People, People, People, People, Still, People, Portrait, People, Portrait, Still, People, People, People, Portrait, Still, People, Portrait, Portrait, People, Still, Still, People, Still, People, Portrait, Portrait, People, People, People, People, Portrait, Portrait, People, Scape, Scape, Setting, People, People, Still, People, Still, Setting, Scape, People, People, People, Still, Still, Portrait, People, Portrait, People, People]
static let allValues2 = [Setting, Setting, Setting, Setting, Setting, Setting, Setting, Scape, Setting, Setting, Scape, Scape, Setting, Setting, Scape, Scape, Setting, Scape, Setting, Scape, Scape, Scape, Scape, Setting, Scape, Scape, Setting, Scape, Setting, Setting, Portrait, Setting, Setting, Setting, Scape, Portrait, Setting, Still, Scape, Setting, Scape, Setting, Still, Scape, Scape, Scape, Setting, Still, Scape, Portrait, Setting, Setting, Still, Still, Scape, Still, Scape, Portrait, Scape, Setting, Scape, Setting, Scape, Setting, Setting, Scape, Scape, Scape, Scape, Scape, Scape, Still, Scape, Still, Still, Scape, Setting, Setting, Scape, Still, Still, Setting, Setting, Setting, Setting, Setting]
}
我创建了一个名为 DeckOfCards 的类和函数来洗牌并向定义数量的玩家发牌。我最终完成了所有工作，并通过在控制台中打印结果进行了检查，所有这些都检查出来了。
所以每个玩家有 10 张牌，并被定义为一个 Card 类型的数组（顺便说一句，玩家也存储在一个名为 newGame 的数组中）。所以 newGame[0] 是玩家 1 并且 newGame[0][0] 是玩家手中的第一张牌。因此，例如，我可以通过 newgame[0][0].dateGroup 引用该卡的 dateGroup。
我想要实现的是检查玩家是否有一组 5 张或更多卡片，其中两个卡片元素相同。我首先尝试计算玩家手中的卡片元素。例如，卡片中有多少有 DG1 的 dateGroup，有多少是 DG2 等，有多少是 countryGroup IT 等等。
我尝试使用joined()，然后进行计数，但没有奏效。我正在考虑返回一个数组，其中包含每种可能的元素类型的计数，并从这个非常骨架的代码开始：
func createIconCount(playerHand: [Card] ) -> [String : Int] {
var counts: [String: Int] = [:]
//insert counting code here
return counts
}
所以我会得到一个数组，比如 [DG1: 3, DG2: 3, .... IT: 4, NE: 5, .... Portrait: 6, People: 4, .....]
帮助！有什么想法吗？
罗伯
【问题讨论】：
-
澄清一下，如果玩家有 3 张牌，分别是 (DG1, IT)、(DG1, NE) 和 (DG2, IT)，那么匹配的牌数（2 个元素相同）为零? （为简洁起见，我跳过了图标组）。 icon1 和 icon2 也是分开比较的，也就是说，如果一个玩家有 2 张牌，其中 icon1 = 人，另一张牌 icon2 = 人，那么这是匹配还是不同牌的 icon1 = icon1？跨度>
-
嗨，我想我现在有一个解决方案。您的解释是正确的 - 您的示例中没有匹配对。我为每个图标创建了一个索引数组，然后可以查看两个索引是否相同，然后这两张卡有一对匹配。因此，如果我将这两个数组取回 [0, 2,3, 6, 7, 8] 和 [0, 1, 2, 3, 6, 7] 那么我有 5 张带有匹配对的卡片（或根据我的游戏规则）。谢谢。现在只需要编写逻辑来比较数组并声明玩家是否有集合 - 目前我只是输出数组并查看它们。