如何编写合成的副本构造函数？ [关闭]

Question

下面是我的代码：

class Pulley{
private:
    int noOfTeeth;

public:
    Pulley();
    Pulley(int teeth);
    ~Pulley();

    void show();
};

Pulley::Pulley()
{
    cout << "Pulley constructor called!";
    noOfTeeth = 0;
}

Pulley::Pulley(int teeth)
{
    cout << "Pulley constructor called!";
    noOfTeeth = teeth;
}

void Pulley::show()
{
    cout << "\n\nNo of Teeths of Pulley: " << noOfTeeth;
}

Pulley::~Pulley()
{

}

class GearBox{
    private:
    char *transmission;
    Pulley p;

    public:
    GearBox();
    GearBox(char *trans, int pTeeth);
    ~GearBox();

    void show();
};

GearBox::GearBox(): p()
{
    cout << "Gearbox constructor called!";
    transmission = NULL;
}

GearBox::GearBox(char *trans, int pTeeth): p(pTeeth)
{
    cout << "Gearbox constructor called!";
    if(trans != NULL)
    {
        transmission = new char[strlen(trans)+1];
        strcpy(transmission, trans);
    }
    else
    {
        transmission = NULL;
    }   
}

void GearBox::show()
{
    cout << "\n\nTransmission of vehicle: " << transmission;
    p.show();
}

GearBox::~GearBox()
{

}

class Vehicle{
private:
    char *model;
    char *color;
    GearBox g;

public:
    Vehicle();
    Vehicle(char *mod, char *col, char *gr);
    Vehicle(const Vehicle &vh);
    ~Vehicle();

    void show();
};

Vehicle::Vehicle(): g()
{
    cout << "Vehicle constructor called!";
    model = NULL;
    color = NULL;
}

Vehicle::Vehicle(char *mod, char *col, char *gr): g(gr)
{
    cout << "Vehicle constructor called!";
    if(mod != NULL)
    {
        model = new char[strlen(mod)+1];
        strcpy(model, mod);
    }
    else
    {
        model = NULL;
    }

    if(col != NULL)
    {
        color = new char[strlen(col)+1];
        strcpy(color, col);
    }
    else
    {
        color = NULL;
    }
}

void Vehicle::show()
{
    cout << "\n\nModel of Vehicle: " << model;
    cout << "\n\nColor of Vehicle: " << color;
    g.show();
}

int main()
{
    Pulley p(20);
    GearBox g("Manual", p);
    Vehicle V("Honda", "Black", g);
    V.show();
    system("PAUSE");
}

现在，当我运行这段代码时，我得到了很多错误，我不知道这些是什么以及如何解决它们。我理解的一个错误是复制构造函数，所以任何人都可以向我解释如何为指向字符transmission, model and color 的指针编写复制构造函数。还告诉我如何解决其他错误。非常感谢。

Answer 1

试试这样：

#include <string>
#include <iostream>

class Pulley{
private:
    int noOfTeeth;

public:
    Pulley(int teeth = 0);

    void show();
};

Pulley::Pulley(int teeth)
: noOfTeeth(teeth)
{
    std::cout << "Pulley constructor called!";
}

void Pulley::show()
{
    std::cout << "\n\nNo of Teeths of Pulley: " << noOfTeeth;
}

class GearBox{
    private:
    std::string transmission;
    Pulley p;

    public:
    GearBox(std::string trans = std::string(), Pulley p = Pulley());

    void show();
};

GearBox::GearBox(std::string trans, Pulley p)
: transmission(std::move(trans))
, p(std::move(p))
{
    std::cout << "Gearbox constructor called!";
}

void GearBox::show()
{
    std::cout << "\n\nTransmission of vehicle: " << transmission;
    p.show();
}

class Vehicle{
private:
    std::string model;
    std::string color;
    GearBox g;

public:
    Vehicle();
    Vehicle(std::string mod = "", std::string col = "", GearBox gr = GearBox());

    void show();
};

Vehicle::Vehicle(std::string mod,std::string col, GearBox gr)
: model(std::move(mod))
, color(std::move(col))
, g(std::move(gr))
{
    std::cout << "Vehicle constructor called!";
}

void Vehicle::show()
{
    std::cout << "\n\nModel of Vehicle: " << model;
    std::cout << "\n\nColor of Vehicle: " << color;
    g.show();
}

int main()
{
    Pulley p(20);
    GearBox g("Manual", p);
    Vehicle V("Honda", "Black", g);
    V.show();
//    system("PAUSE");
}