如何连接两个 XML 表并嵌套而不重复

Question

我正在尝试加入下面的两个 XML 文件

XML 文件 1 - 日志

<Journals>
    <JournalID>1</JournalID>
    <Description>BKI- 1</Description>
</Journals>
<Journals>
    <JournalID>2</JournalID>
    <Description>BKI- 2</Description>
</Journals>

XML 文件 2 - 事务

<Transaction>
    <JID>1</JID>
    <TransactionID>0005932053</TransactionID>
    <Period>5</Period>
</Transaction>
<Transaction>
    <JID>1</JID>
    <TransactionID>0005932054</TransactionID>
    <Period>8</Period>
</Transaction>
<Transaction>
    <JID>2</JID>
    <TransactionID>0005932053</TransactionID>
    <Period>2</Period>
</Transaction>
<Transaction>
    <JID>2</JID>
    <TransactionID>0005932053</TransactionID>
    <Period>4</Period>
</Transaction>

变成如下图

XML 输出

<Journals>
    <JournalID>1</JournalID>
    <Description>BKI- 1</Description>
        <Transaction>
            <JID>1</JID>
            <TransactionID>0005932053</TransactionID>
            <Period>5</Period>
        </Transaction>
        <Transaction>
            <JID>1</JID>
            <TransactionID>0005932054</TransactionID>
            <Period>8</Period>
        </Transaction>
</Journals>
<Journals>
    <JournalID>2</JournalID>
    <Description>BKI- 2</Description>
        <Transaction>
            <JID>2</JID>
            <TransactionID>0005932053</TransactionID>
            <Period>2</Period>
        </Transaction>
        <Transaction>
            <JID>2</JID>
            <TransactionID>0005932053</TransactionID>
            <Period>4</Period>
        </Transaction>

</Journals>

如您所见，我正在尝试加入它，以便对于每个日记 - 所有交易都将显示为子节点。

到目前为止我的代码 - 未能做到这一点（因为它为每个事务复制 Journals 节点）：

        XDocument FileTransactions = XDocument.Load("Final_Transaction.xml");
        XDocument FileJournals = XDocument.Load("Final_Journals.xml");
        var joinQuery = from j in FileJournals.Root.Descendants("Final_Journals")

                        join t in FileTransactions.Root.Descendants("Final_Transaction")

                        on (string)j.Element("JournalID").Value equals (string)t.Element("JID").Value

                        select new XElement("Journals",
        new XElement("JournalID", (string)j.Element("JournalID")),
        new XElement("Description", (string)j.Element("Description")),
        new XElement("Type", (string)j.Element("Type")),
        new XElement("Transaction", new XElement(t))
                );

我需要在这里添加一个 foreach 循环吗？如何在不重复父节点的情况下搭建父节点中的所有相关子节点？

我已经尝试查看教程和其他帖子 - 它们都没有涵盖我面临的复杂性

请指出正确的方向

Answer 1

您可以使用 for 循环或 join（使用 for 循环）。我用加入。您需要使用格式良好的 xml，因此我在输入中添加了根标签。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
using System.IO;

namespace ConsoleApplication1
{
    class Program
    {
        const string journalsStr = @"c:\temp\test.xml";
        const string transactionsStr = @"c:\temp\test1.xml";
        static void Main(string[] args)
        {
            // xml files are not well formed. A well formed xml has only one root tag
            string jXml = File.ReadAllText(journalsStr);
            jXml = string.Format("<Root>{0}</Root>", jXml);
            XDocument jDoc = XDocument.Parse(jXml);
            string tXml = File.ReadAllText(transactionsStr);
            tXml = string.Format("<Root>{0}</Root>", tXml);
            XDocument tDoc = XDocument.Parse(tXml);

            var query = (from j in jDoc.Descendants("Journals")
                          join t in tDoc.Descendants("Transaction") on (int)j.Element("JournalID") equals (int)t.Element("JID")
                         select new {j = j, t = t}
                         ).ToList();

            var groups = query.GroupBy(x => (int)x.j.Element("JournalID")).ToList();

            string root = "<Journals></Journals>";
            XDocument doc = XDocument.Parse(root);
            XElement journals = doc.Root;
            foreach (var group in groups)
            {
                XElement journal = group.First().j;
                foreach (var trans in group)
                {
                    journal.Add(trans.t);
                }
                journals.Add(journal);
            }
        }
    }
}