XML 解析（NeTEX 格式）

Question

我有一个来自该位置的 xml 文件的巴士票价信息

Bus data from DfT website

我正在努力寻找一种方法来获得

1. 巴士站名称
2. Atco 代码
3. 所属的公交站区
4. 该区域的票价

可在标签“ScheduledStopPointRef”中访问。

这里有一个示例 xml

https://data.bus-data.dft.gov.uk/fares/dataset/997/download/

有没有办法使用图书馆 Elementree 或任何其他方法来做到这一点。必须使用多个嵌套的“for”循环遍历 xml 文件。

“某种”工作的测试代码如下所示

tree = ET.ElementTree(file=/path/to/file.xml)
root = tree.getroot()
children = root.getchildren()
for child in children:
    for a in child:
        for b in a:
            for c in b:
                for d in c:
                    if 'FareFrame' in c.tag:
                        for e in d:
                            print("E->", e.text)
                            for f in e:
                                if ('Name' in f.tag):
                                    print("F->", f.text)
                    
                                elif ('members' in f.tag):
                                    for g in f:
                                        print("G tag ->" , g.tag)
                                        print("G->", g.text)

预期输出

请指教。

Answer 1

您要查找的日期（如果我理解正确的话）是以 json 格式而不是 xml 动态加载的。获得它的方法之一是：

import requests
import json

req = requests.get('https://data.bus-data.dft.gov.uk/api/app/fare_stops/?revision=2457')
data = json.loads(req.text)

#once you have the data, extract the target information:
features = data['features']
for feature in features:
    print(feature['properties']['common_name'],feature['properties']['atco_code'])

输出：

Southfield 040000002345
Dadbrook 040000002429
Pearson Close 040000004402
The Bugle Horn PH 040000004404
The Rose & Crown PH 040000004406

等等

Answer 2

试试下面的（bus.xml是链接里的文件）

import xml.etree.ElementTree as ET

root = ET.parse('bus.xml')

points = root.findall('.//{http://www.netex.org.uk/netex}ScheduledStopPoint')
for idx,point in enumerate(points,1):
  print(point.attrib['id'])
  print(point.find('{http://www.netex.org.uk/netex}Name').text)
  print(point.find('{http://www.netex.org.uk/netex}TopographicPlaceView').find('{http://www.netex.org.uk/netex}Name').text)
  print(f'--------{idx}----------')
print('Done.')

输出

--------1----------
atco:040000004658
Bus Station
Aylesbury
--------2----------
atco:040000004402
Pearson Close
Aylesbury
--------3----------
atco:040000004918
Churchill Avenue
Aylesbury
--------4----------
atco:040000004917
Aylesbury College
Aylesbury
--------5----------
atco:040000004412
Upton Turn
Stone
--------6----------
atco:040000004410
Long Furlong
Stone
--------7----------
atco:040000004408
Village Hall
Stone
--------8----------
atco:040000004406
The Rose & Crown PH
Stone
--------9----------
atco:040000004404
The Bugle Horn PH
Stone
--------10----------
atco:040000004416
New Road
Dinton
...