使用另一个表中的数据更新一个表 - Oracle答案

【问题标题】：Update one table using data from another table - Oracle使用另一个表中的数据更新一个表 - Oracle
【发布时间】：2012-04-07 04:03:33
【问题描述】：

这是我的试用查询。我正在尝试根据 person_id 使用来自ADDR 的相应数据更新TABLE1 表。下面说缺少 SET 关键字。

UPDATE TABLE1 CFI
INNER JOIN 
(
  SELECT ADDRESS_LINE1, ADDRESS_LINE2, CITY, STATE_PROVINCE, ZIP FROM ADDR WHERE PERSON_ID = CFI.PERSON_ID AND STATUS = 'Active' 
) AS ADDR_DATA
SET CFI.PAYEE_ADDRESS1 = ADDR_DATA.ADDRESS_LINE1, 
    CFI.PAYEE_ADDRESS2 = ADDR_DATA.ADDRESS_LINE2, 
    CFI.PAYEE_CITY= ADDR_DATA.CITY, 
    CFI.PAYEE_STATE_PROVINCE = ADDR_DATA.STATE_PROVINCE,
    CFI.PAYEE_POSTALCODE = ADDR_DATA.ZIP, 
    CFI.PAYEE_COUNTRY_CODE = 'USA'    
WHERE CFI.CUSTOMER_INSTITUTION_ID = 966362 AND CFI.PERSON_ID = ADDR_DATA.PERSON_ID;

请帮忙。提前致谢。

【问题讨论】：

标签： sql select oracle10g inner-join

【解决方案1】：

那就是

UPDATE TABLE1 CFI
    SET (PAYEE_ADDRESS1, PAYEE_ADDRESS2, PAYEE_CITY, PAYEE_STATE_PROVINCE, PAYEE_POSTALCODE, PAYEE_COUNTRY_CODE) =
        (SELECT ADDRESS_LINE1, ADDRESS_LINE2, CITY, STATE_PROVINCE, ZIP, 'USA' FROM ADDR WHERE PERSON_ID = CFI.PERSON_ID AND STATUS = 'Active')
    WHERE CFI.CUSTOMER_INSTITUTION_ID = 966362;

编辑：错误已修复（希望如此）

【讨论】：

感谢您的回复。但它说，ADDR_DATA.PERSON_ID 无效标识符。

【解决方案2】：

MERGE INTO TABLE1
USING (
       SELECT PERSON_ID, 
              ADDRESS_LINE1, ADDRESS_LINE2, CITY, STATE_PROVINCE, ZIP 
         FROM ADDR 
        WHERE STATUS = 'Active' 
      ) ADDR_DATA
   ON TABLE1.PERSON_ID = ADDR_DATA.PERSON_ID 
      AND TABLE1.CUSTOMER_INSTITUTION_ID = 966362 
WHEN MATCHED THEN 
   UPDATE
      SET PAYEE_ADDRESS1 = ADDR_DATA.ADDRESS_LINE1, 
          PAYEE_ADDRESS2 = ADDR_DATA.ADDRESS_LINE2, 
          PAYEE_CITY = ADDR_DATA.CITY, 
          PAYEE_STATE_PROVINCE = ADDR_DATA.STATE_PROVINCE,
          PAYEE_POSTALCODE = ADDR_DATA.ZIP, 
          PAYEE_COUNTRY_CODE = 'USA';

【讨论】：

感谢您的回复。但它说缺少 ON 关键字。
尝试从 ADDR_DATA 子查询中选择 PERSON_ID，它成功了。非常感谢。