使用内部联接更新查询答案

【问题标题】：Update query using inner join使用内部联接更新查询
【发布时间】：2015-08-01 22:26:22
【问题描述】：

为什么在这部分存储过程中出现以下语法错误：

关键字“FROM”附近的语法不正确。

WITH CTE_Residence_Overtime
    AS
    (
      SELECT * 
      FROM #Residence
    )
    UPDATE t1 
    SET t1.over_time = t1.over_time + CONVERT(TIME, CAST(CTE_Residence_Overtime.overtimeHours AS VARCHAR(2))  
    FROM r_overtime AS t1
    INNER JOIN CTE_Residence_Overtime 
    ON t1.[trans_date] = CTE_Residence_Overtime.[dayDate];

【问题讨论】：

看起来您在 CONVERT() 上缺少右括号
更正括号！！！

标签： sql sql-server stored-procedures inner-join common-table-expression

【解决方案1】：

您在set 上缺少一个结束括号：

    SET t1.over_time = t1.over_time +
                       CONVERT(TIME,
                               CAST(CTE_Residence_Overtime.overtimeHours AS VARCHAR(2)
                                   )  
                              )
------------------------------^

【讨论】：

【解决方案2】：

我觉得你少了一个括号

WITH CTE_Residence_Overtime
    AS
    (
      SELECT * 
      FROM #Residence
    )
    UPDATE t1 
    SET t1.over_time = t1.over_time + CONVERT(TIME, CAST(CTE_Residence_Overtime.overtimeHours AS VARCHAR(2)))  
    FROM r_overtime AS t1
    INNER JOIN CTE_Residence_Overtime 
    ON t1.[trans_date] = CTE_Residence_Overtime.[dayDate];

【讨论】：

【解决方案3】：

缺少一个括号会使您的生活变得非常忙碌！

WITH CTE_Residence_Overtime
        AS
        (
          SELECT * 
          FROM #Residence
        )
        UPDATE t1 
        SET t1.over_time = t1.over_time + CONVERT(TIME, CAST(CTE_Residence_Overtime.overtimeHours AS VARCHAR(2)))  
        FROM r_overtime AS t1
        INNER JOIN CTE_Residence_Overtime 
        ON t1.[trans_date] = CTE_Residence_Overtime.[dayDate];

【讨论】：