如何在 Django 中序列化答案

【问题标题】：How to serialize in Django如何在 Django 中序列化
【发布时间】：2017-10-15 06:03:40
【问题描述】：

我在 Django 中有一个序列化程序，如下所示：

class ListSerializer(serializers.HyperlinkedModelSerializer):
    vehicles = serializers.HyperlinkedRelatedField(
        view_name='asset-detail',
        many=True,
        read_only=True
    )

    class Meta:
        model = List
        fields = ('url', 'name', 'start', 'stop', 'state', 'vehicles')

我得到的结果如下：

[
    {
        "url": "http://127.0.0.1:8000/sales/api/v1/lists/3741/", 
        "name": "DEA 2017", 
        "start": "2017-03-09T10:00:00", 
        "stop": "2017-12-31T12:00:00", 
        "state": "OPEN", 
        "vehicles": [
            "http://127.0.0.1:8000/sales/api/v1/assets/134299/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/154368/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/154367/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/154246/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/155906/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/155212/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/154574/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/155683/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/153347/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/153183/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/153182/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/153152/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/153116/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/154913/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/152389/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/153459/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/153568/", 
            "http://127.0.0.1:8000/sales/api/v1/assets/153659/"
        ]
    }
]

如果我点击vehicles 中的其中一个网址，我会得到一个对象，如下所示：

{
    "vin": "WVWZZZ6RZEY104640",
    "make": "VOLKSWAGEN", 
    "model": "POLO", 
    "fuel": "Diesel"
}

我想要的是用对象而不是 url 来获得结果。

因此如下：

[
        {
            "url": "http://127.0.0.1:8000/sales/api/v1/lists/3741/", 
            "name": "DEA 2017", 
            "start": "2017-03-09T10:00:00", 
            "stop": "2017-12-31T12:00:00", 
            "state": "OPEN", 
            "vehicles": [
                {
                   "vin": "WVWZZZ6RZEY104123",
                   "make": "VOLKSWAGEN", 
                   "model": "POLO", 
                   "fuel": "Diesel"
                }, 
                {
                   "vin": "WVWZZZ6RZEY10452",
                   "make": "VOLKSWAGEN", 
                   "model": "Golf", 
                   "fuel": "Diesel"
                }, 
                {...},
                {...},
                {...},
                ....
            ]
        }
    ]

有什么建议吗？

附：我完全是初学者，请怜悯:)

【问题讨论】：

标签： python django django-rest-framework django-serializer

【解决方案1】：

我相信您确实有一个 Vehicle 模型来表示 Vehicle 属性。然后您可以为车辆创建序列化程序并为您使用它列出序列化程序如下：

 class VehicleSerializer(serializers.ModelSerializer):
   """Serializer for vehicle"""

      class Meta:
         model = Vehicle



 class ListSerializer(serializers.HyperlinkedModelSerializer):
    vehicles = VehicleSerializer(many=true)

    class Meta:
        model = List
        fields = ('url', 'name', 'start', 'stop', 'state', 'vehicles')

【讨论】：

【解决方案2】：

您正在寻找嵌套的序列化程序，解释了 there

【讨论】：

可能，但由于我们没有模型，更多的只是猜测。