在 MySQL 中调用存储过程后使用 GROUP BY答案

【问题标题】：Using GROUP BY after calling a stored procedure in MySQL在 MySQL 中调用存储过程后使用 GROUP BY
【发布时间】：2017-10-15 22:40:02
【问题描述】：

我想做这样的事情：

CALL testFunction('26e4ccaa-b125-3d9c-c7c1-58175227a48f')
GROUP BY id_c;

这似乎不起作用，所以我也尝试了这个：

SELECT *
FROM (
   CALL testFunction('26e4ccaa-b125-3d9c-c7c1-58175227a48f')
) t
GROUP BY t.id_c;

这也不起作用。我找不到关于这是否可能的文档。

我在其他地方使用这个存储过程，创建一个全新的存储过程似乎是多余的，这样我就可以包含GROUP BY。我在一个 php 应用程序中调用这个存储过程。

编辑：

这是存储过程：

BEGIN
    DECLARE lastInsertCount INT;
    DECLARE lastLayer INT;
    DROP TABLE IF EXISTS `temp`;
    DROP TABLE IF EXISTS `productGrid`;

    CREATE TABLE `temp`
    (
        `layer` INT(5),
        `title_c` VARCHAR(255), 
        `name` VARCHAR(255), 
        `rep_first_name` VARCHAR(255), 
        `rep_last_name` VARCHAR(255),
        `id_c` CHAR(36),
        `contact_status_reps_c` VARCHAR(255),
        `phone_mobile` VARCHAR(255),
        `contract_type_c` VARCHAR(255),
        `email_address` VARCHAR(255),
        `active_as_of_c` DATETIME,
        `assigned_user_id` CHAR(36)
    );

    CREATE TABLE `productGrid`
    (
        `percentage_c` INT(5),
        `name` VARCHAR(255), 
        `title_c` VARCHAR(255)
    );

    INSERT INTO `productGrid`(`percentage_c`, `name`, `title_c`)
    SELECT aaigloba_crm.pcg_product_comp_grid_cstm.percentage_c, 
           aaigloba_crm.aos_products.name, 
           aaigloba_crm.pcg_product_comp_grid_cstm.title_c
    FROM aaigloba_crm.aos_products_pcg_product_comp_grid_1_c 
        LEFT OUTER JOIN aaigloba_crm.aos_products ON aaigloba_crm.aos_products_pcg_product_comp_grid_1_c.aos_products_pcg_product_comp_grid_1aos_products_ida = aaigloba_crm.aos_products.id
        LEFT OUTER JOIN aaigloba_crm.pcg_product_comp_grid_cstm ON aaigloba_crm.aos_products_pcg_product_comp_grid_1_c.aos_products_pcg_product_comp_grid_1pcg_product_comp_grid_idb = aaigloba_crm.pcg_product_comp_grid_cstm.id_c
    WHERE aaigloba_crm.aos_products_pcg_product_comp_grid_1_c.deleted = '0';

    INSERT INTO `temp`(`layer`, `title_c`, `name`, `rep_first_name`, `rep_last_name`, `id_c`, `contact_status_reps_c`, `phone_mobile`,`contract_type_c`,`email_address`,`active_as_of_c`,`assigned_user_id`)
    SELECT 0,
    wn_writing_number_cstm.title_c, 
    wn_writing_number.`name`, 
    preps_contracted_reps.first_name, 
    preps_contracted_reps.last_name, 
    wn_writing_number_cstm.id_c, 
    preps_contracted_reps_cstm.contact_status_reps_c, 
    preps_contracted_reps.phone_mobile, 
    preps_contracted_reps_cstm.contract_type_c, 
    email_addresses.email_address,
    STR_TO_DATE(preps_contracted_reps_cstm.active_as_of_c, '%m/%d/%Y'),
    wn_writing_number.assigned_user_id
FROM wn_writing_number LEFT OUTER JOIN wn_writing_number_cac_customize_agent_comp_1_c ON wn_writing_number_cac_customize_agent_comp_1_c.wn_writing946b_number_ida = wn_writing_number.id
     LEFT OUTER JOIN cac_customize_agent_comp ON wn_writing_number_cac_customize_agent_comp_1_c.wn_writing3148nt_comp_idb = cac_customize_agent_comp.id
     LEFT OUTER JOIN cac_customize_agent_comp_cstm ON cac_customize_agent_comp.id = cac_customize_agent_comp_cstm.id_c
     LEFT OUTER JOIN aos_products_cac_customize_agent_comp_1_c ON cac_customize_agent_comp_cstm.id_c = aos_products_cac_customize_agent_comp_1_c.aos_produca2b8nt_comp_idb
     LEFT OUTER JOIN preps_contracted_reps_wn_writing_number_1_c ON preps_contracted_reps_wn_writing_number_1_c.preps_contracted_reps_wn_writing_number_1wn_writing_number_idb = wn_writing_number.id
     LEFT OUTER JOIN preps_contracted_reps ON preps_contracted_reps_wn_writing_number_1_c.preps_cont9effed_reps_ida = preps_contracted_reps.id
     LEFT OUTER JOIN preps_contracted_reps_cstm ON preps_contracted_reps.id = preps_contracted_reps_cstm.id_c
     LEFT OUTER JOIN email_addr_bean_rel ON email_addr_bean_rel.bean_id = preps_contracted_reps_cstm.id_c
     LEFT OUTER JOIN email_addresses ON email_addr_bean_rel.email_address_id = email_addresses.id
     LEFT OUTER JOIN wn_writing_number_cstm ON wn_writing_number_cstm.id_c = wn_writing_number.id
    WHERE wn_writing_number_cstm.wn_writing_number_id_c = passId AND wn_writing_number.deleted = '0' AND preps_contracted_reps.deleted = '0' AND wn_writing_number.deleted = '0' AND email_addr_bean_rel.deleted = '0'
    GROUP BY wn_writing_number.`name`;

    SET lastLayer := 0;
    SET lastInsertCount := 1;
    LayerLoop: WHILE lastInsertCount > 0 DO
      INSERT INTO `temp`(`layer`, `title_c`, `name`, `rep_first_name`, `rep_last_name`, `id_c`, `contact_status_reps_c`, `phone_mobile`,`contract_type_c`,`email_address`,`active_as_of_c`,`assigned_user_id`)
      SELECT lastLayer + 1,
        wn_writing_number_cstm.title_c, 
        wn_writing_number.`name`, 
        preps_contracted_reps.first_name, 
        preps_contracted_reps.last_name, 
        wn_writing_number_cstm.id_c,
        preps_contracted_reps_cstm.contact_status_reps_c, 
        preps_contracted_reps.phone_mobile, 
        preps_contracted_reps_cstm.contract_type_c, 
        email_addresses.email_address,
        STR_TO_DATE(preps_contracted_reps_cstm.active_as_of_c, '%m/%d/%Y'),
        wn_writing_number.assigned_user_id
    FROM wn_writing_number LEFT OUTER JOIN wn_writing_number_cac_customize_agent_comp_1_c ON wn_writing_number_cac_customize_agent_comp_1_c.wn_writing946b_number_ida = wn_writing_number.id
         LEFT OUTER JOIN cac_customize_agent_comp ON wn_writing_number_cac_customize_agent_comp_1_c.wn_writing3148nt_comp_idb = cac_customize_agent_comp.id
         LEFT OUTER JOIN cac_customize_agent_comp_cstm ON cac_customize_agent_comp.id = cac_customize_agent_comp_cstm.id_c
         LEFT OUTER JOIN aos_products_cac_customize_agent_comp_1_c ON cac_customize_agent_comp_cstm.id_c = aos_products_cac_customize_agent_comp_1_c.aos_produca2b8nt_comp_idb
         LEFT OUTER JOIN preps_contracted_reps_wn_writing_number_1_c ON preps_contracted_reps_wn_writing_number_1_c.preps_contracted_reps_wn_writing_number_1wn_writing_number_idb = wn_writing_number.id
         LEFT OUTER JOIN preps_contracted_reps ON preps_contracted_reps_wn_writing_number_1_c.preps_cont9effed_reps_ida = preps_contracted_reps.id
         LEFT OUTER JOIN preps_contracted_reps_cstm ON preps_contracted_reps.id = preps_contracted_reps_cstm.id_c
         LEFT OUTER JOIN email_addr_bean_rel ON email_addr_bean_rel.bean_id = preps_contracted_reps_cstm.id_c
         LEFT OUTER JOIN email_addresses ON email_addr_bean_rel.email_address_id = email_addresses.id
         LEFT OUTER JOIN wn_writing_number_cstm ON wn_writing_number_cstm.id_c = wn_writing_number.id
      WHERE preps_contracted_reps.deleted = '0' AND wn_writing_number.deleted = '0' AND email_addr_bean_rel.deleted = '0' AND wn_writing_number_cstm.wn_writing_number_id_c IN (SELECT id_c FROM `temp` WHERE layer = lastLayer)
      GROUP BY wn_writing_number.`name`;

      SET lastInsertCount := ROW_COUNT();
      SET lastLayer := lastLayer + 1;
    END WHILE LayerLoop;

    SELECT `title_c`, `name`, `rep_first_name`, `rep_last_name`, `id_c`, `contact_status_reps_c`, `phone_mobile`,`contract_type_c`,`email_address`,`active_as_of_c`,`assigned_user_id`
    FROM `temp`
    ORDER BY rep_first_name ASC;
END

【问题讨论】：

Can I Use Order by to sort Stored Procedure results?的可能重复
您需要先在表中插入数据。然后你可以对数据进行操作。见上面的链接。
我已经将所有内容存储到存储过程中的临时表中，然后在存储过程结束时使用临时表的选择。我的问题是，你能不能在存储过程之外使用 GROUP BY。
问题出在哪里？如果您的函数返回行，您可以执行 SELECT * FROM yourFunction()
什么？ SELECT * FROM testFunction('26e4ccaa-b125-3d9c-c7c1-58175227a48f') 在 MySQL 中不起作用。

标签： php mysql stored-procedures group-by call

【解决方案1】：

GROUP 子句是 SQL 子句，需要合并到完整的 SQL 表达式中，因为 SQL 解析器会自动优化和执行整个表达式。该函数返回一个表，而不是 SQL 表达式，并且 SQL 子句不能修改表。

使用临时表是您在概念上分解您的操作的另一个迹象，可能会对其进行优化。分解是过程代码的好模式，但它是声明性代码的反模式。

您可能已经知道 WHILE 循环在对关系数据的操作中存在问题。太糟糕了，你没有使用 isam 表。

【讨论】：

我认为这回答了我的问题。 “该函数返回一个表，而不是 SQL 表达式，并且 SQL 子句不能修改表。”所以，不，我不能在 CALL 语句之后使用 GROUP BY 语句，尤其是当我的功能是返回一个表。这意味着我要么必须更改我的存储过程，创建一个新的，要么处理 php.ini 中的分组。我想我会做第三个选项。

【解决方案2】：

您的函数需要返回一组记录。

CREATE OR REPLACE FUNCTION testFunction(field1 OUT text, field2 OUT INT)
RETURNS setof record
AS $$ SELECT field1, field2 FROM yourTable $$
LANGUAGE sql;

然后你就可以调用你的函数了

SELECT field1, SUM(field2)
FROM testFunction()
GROUP BY field1

检查这个DEMO

CREATE OR REPLACE FUNCTION dup1(int) 
RETURNS TABLE( f1 text, f2 int) AS 
$$ 
   select f1::text, f2
   FROM ( VALUES ('apple', 3), ('apple', 2), 
                 ('mango', 1), ('pineapple', 3), 
                 ('pineapple', 5) ) T(f1, f2)
$$
LANGUAGE sql;

SELECT f1, SUM(f2)
FROM dup1(1)
GROUP BY f1;

输出

【讨论】：

我的函数确实返回记录。虽然我知道我可以做另一个选择，但我试图看看是否可以在我已经拥有的现有结果集上做一个GROUP BY，而不是做另一个选择。我每次都需要调用该函数，忽略结果，然后进行这个单独的选择，以便我可以对结果进行分组。如果没有，那么 IMO，最好只创建一个包含 GROUP BY 的单独存储过程并使用它。
我不确定是什么问题。我改为RETURN TABLE sintaxis。函数返回数据，可以使用GROUP BY