我怎样才能像这样查询总和答案

【问题标题】：How can i Query sum like this我怎样才能像这样查询总和
【发布时间】：2018-11-29 02:12:21
【问题描述】：

我有一个这样的查询

  SELECT a.code ,a.group ,a.Desc ,
         Sum(CONVERT(decimal(10,2),a.amount)) 'BYDESC'
    FROM table1 as a
   WHERE a.Bol = 'Y'
GROUP BY a.code,a.group,a.Desc
ORDER BY a.code 
         Asc ,a.group asc ,a.Desc asc

它给了我一张这样的桌子

CODE   GROUP  DESC        BYDESC
--------------------------------
G001   00001  D001          15.0
G001   00001  D002           3.0
G001   00001  D003         354.0
G001   00002  D001          27.0
   .       .     .             .
   .       .     .             .
   .       .     .             .
--------------------------------

我想对每个组求和并像这样显示

CODE   GROUP  DESC        BYDESC  Sum(BYGROUP)
---------------------------------------------
G001   00001  D001          15.0        372.0
G001   00001  D002           3.0        372.0
G001   00001  D003         354.0        372.0
G001   00002  D001          27.0         27.0
   .       .     .             .            .
   .       .     .             .            . 
   .       .     .             .            .
----------------------------------------------

【问题讨论】：

标签： sql-server group-by sum

【解决方案1】：

您可以使用公用表表达式来实现此目的。
试试这个。

;with sumTable 
AS
( 
        SELECT a.code ,a.group ,Sum(CONVERT(decimal(10,2),a.amount)) SUMBYGROUP
          FROM table1 as a
          WHERE a.Bol = 'Y'
       GROUP BY a.code,a.group

)
  SELECT a.code ,a.group ,a.Desc ,Sum(CONVERT(decimal(10,2),a.amount)) 'BYDESC', sumTable.SUMBYGROUP as 'Sum(BYGROUP)'
    FROM table1 as a
    JOIN sumTable 
      ON (
          sumTable.code = a.code And sumTable.group = a.group 
         )
   WHERE a.Bol = 'Y'
GROUP BY a.code,a.group,a.Desc, sumTable.SUMBYGROUP
ORDER BY a.code asc ,a.group asc ,a.Desc asc

【讨论】：

感谢您的回答。尝试此操作后，出现以下错误 - > 列“sumTable.SUMBYGROUP”在选择列表中无效，因为它既不包含在聚合函数或 GROUP BY 子句中。
@Izle 我已经编辑了我的答案，你现在可以试一试。

【解决方案2】：

;with GroupedTable 
AS
( 
    SELECT a.[COL1] ,a.[COL2] ,a.[COL3] ,Sum(CONVERT(decimal(10,2),a.[COL4])) 
     'BYDESC'
    FROM MyTable as a
    GROUP BY a.[COL1],a.[COL2],a.[COL3] 
)

SELECT 
    a.[COL1] ,a.[COL2] , a.[COL3] 
    ,Sum(CONVERT(decimal(10,2),a.[COL4])) 'BYDESC', mt.SUM
FROM MyTable as a
INNER JOIN 
(
   SELECT gt.[COL1] ,gt.[COL2] ,Sum(CONVERT(decimal(10,2),gt.[BYDESC])) AS 'SUM'
  FROM GroupedTable as gt
  GROUP BY gt.[COL1] ,gt.[COL2] 
) mt ON mt.[COL1] = a.[COL1] AND mt.[COL2] = a.[COL2]
GROUP BY a.[COL1],a.[COL2],a.[COL3], mt.SUM
ORDER BY  a.[COL1],a.[COL2],a.[COL3], mt.SUM

DB Fiddle

【讨论】：

【解决方案3】：

你可以使用windows功能来实现这一点。

with cte as
   (SELECT a.code,
        a.group,
        a.Desc,
        Sum(CONVERT(decimal(10,2),a.amount)) 'BYDESC'
        FROM table1 as a
        WHERE a.Bol = 'Y'
        GROUP BY a.code,a.group,a.Desc
       ) 
select *, 
sum(bydesc) over (partition by [group] order by [desc]
 ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING)
    from cte
ORDER BY code Asc ,[group] asc , [Desc] asc

【讨论】：

感谢您的回答，我已经测试了您的解决方案，但似乎最后两列的结果有点奇怪:(
嘿 izle，你能把所面临的问题说清楚一点吗？
好吧，首先我遇到以下错误“ORDER BY 子句在视图中无效”，所以我将订单移到查询的最后一行，结果显示“sum(bydesc) over (按 CallDesc 排序的 CallGroup 分区)”的总和不正确
抱歉错过了范围条件。请检查更新后的查询。